Please tell me about this biology question, the answer is 3 5 times

At 15 degrees, both organic matter produced by photosynthesis and organic matter consumed by respiration is calculated as carbon dioxide.

The organic matter consumed by respiration is, and the organic matter produced by photosynthesis is, so at 15 degrees, the organic matter produced by photosynthesis is twice that of the organic matter consumed by respiration.

At 15°, the amount of CO2 released in the dark is respiration, which is 1mg H, this process consumes organic matter, and the absorption of CO2 under light is photosynthesis minus respiration, because respiration under light is also carried out, for.

So the photosynthetic CO2 uptake is 1mg H+, and this process produces organic matter.

Correspondingly, the amount of organic matter produced at 15°C is a double of the amount of organic matter consumed.

1a2b3d

One is fat-soluble and the other is water-soluble, which is just suitable for using water as chromatography solution.

b Both are water-soluble, and the solubility is very large, and they cannot be separated.

c Both are fat-soluble and suitable for acetone as chromatography.

d Same as c acetic acid bacteria without partichondria.

b Correct. c Acetic acid is an oxidation product and does not produce CO2

D CaCO3 has no inhibitory effect on acetic acid bacteria, and is only a pH buffer.

When aerobic respiration is vigorous, anaerobic respiration is inhibited.

b ectotherms have no internal ability to regulate body temperature, and when the temperature is low, the body temperature is also low, the metabolism is slow, and the oxygen consumption is low. When the outside temperature rises, its body temperature can only passively rise, resulting in accelerated respiration and increased oxygen consumption.

Homeothermic animals regulate their body temperature on their own, and their metabolism increases when the temperature is low to maintain their body temperature. When the outside temperature rises to a certain level, the body no longer needs to accelerate heat production to maintain body temperature, so oxygen consumption decreases.

c If no new allele is generated, the sum of the frequencies of this pair of alleles will always be 1, and the other will increase.

d False. The effects of auxin on rhizomes are all low concentration promotion and high concentration inhibition, but their concentration range is different. Therefore, this diagram should be changed to two curves that are also high on the left and low on the right, indicating that the root is on the left and the stem is on the right.

1、b。

Only these two substances in item b are dissolved in water.

2、b。A is false, acetic acid bacteria do not have mitochondria; c False, there is no carbon dioxide emission link; d False.

3、d。Item d reverses root and stem.

Question 1 c

Paper chromatography is separated by using the different solubility of substances in the same solvent Item A chloroplast pigments and anthocyanins are not clear Should it be item B Glucose and fructose are both sugars How can paper chromatography be used if they are so similar Item C is not explained Classic experiments in high school textbooks Item d are all sterols.

Question 2 Item BA Acetic acid bacteria are bacteria without partichondria Item B Acetic acid bacteria can directly turn glucose sugar into acetic acid if the sugar source is sufficient, and in the case of sufficient oxygen, it can oxidize alcohol into acetic acid to make vinegar Item C Why does it release gas after supplementing oxygen Item D is not clear.

Question 3 The optimal concentration of D roots is about 10 (-10)mol l, the optimal concentration of buds is about 10 (-8)mol l, the optimal concentration of stems is about 10 (-4)mol l, and it is obvious that b is the root and a is the stem.

Yes! Give me a junior high school student to do, I can't do it!

Color blindness is a recessive genetic disorder, and the gene for color blindness is set as B

The woman's father suffers from color blindness, xb y

Among them, XB must have been inherited to the woman, the woman's genotype is XB XB The male is normal, the genotype is XB Y, the man is a girl if he provides XB, and the girl must not be color blind, because there must be XB; Providing Y is a boy, Y has a 1 2 chance of binding to XB, and 1 2 has a chance of color blindness.

So it's good to have a girl.

It is good to have a girl, because having a girl can reduce the burden on parents. And the girl is very well-behaved.

The answer is d.

This question is a difficult multiple-choice question, and if it is a student's analysis, starting from the relevant knowledge of the textbook, through reasonable reasoning and analysis, the correct answer can also be obtained.

Option A analysis: When the DNA molecule is transcribed, it only uses one of the strands as a template strand to participate in the transcription, and the other strand does not participate in the synthesis of mRNA in the transcription, all A errors.

Analysis of option b: On page 23 of compulsory course 1 there is "....However, after the egg is cooked, the protein is denatured and cannot return to its original state. The reason is that the high temperature makes the spatial structure of protein molecules stretched, loose, and easily hydrolyzed by proteases", which can reflect the change of the spatial structure of proteins under the heating conditions of boiling water baths, and imply that the peptide bonds are not hydrolyzed.

Analysis of option c: It is also clarified on page 23 of compulsory course 1 that the diversity of proteins is determined by the number of amino acids that make up protein molecules, the type, the order of arrangement, and the spatial structure of protein molecules, so the function of insulin in this question is related to the spatial structure of proteins.

D option analysis: from the concept, it can be obtained that the gene is "the basic unit of genetic information encoding a protein or RNA and other genetic information with specific functional products", in this question, "the two peptide chains of insulin A and B are encoded by a gene", so that only one polypeptide chain can be obtained after transcription and translation, and insulin is composed of two peptide chains A and B, and comprehensive analysis can show that the gene should use proteolytic enzymes in the process of encoding proteins, and only then hydrolyze a large peptide chain into two peptide chains A and B, Hence the use of hydrolase enzymes.

P.S. Find out the information yourself.

The insulin synthesized in the human body is originally a single-chain amino acid sequence, which needs to be isomerized, formed into disulfide bonds, and cut off part of the original peptide bonds to become biologically active insulin. So it has to be protease.

The answer is a. Analysis:

For B, the high temperature does not break the peptide bond structure of the protein.

For C, it must be related to the spatial structure, it is necessary.

For D, the protease action is to hydrolyze the proteolysis. It cannot be used to synthesize insulin.

A triploids cannot be combined due to association disorder, so genetic recombination is not possible.

d is possible, environmental factors can also cause variation, but the trait changes, the genetic material does not change, so the variation caused by the environment is not heritable.

Trait variations are all caused by genetic mutations, ABC is talking about genetic mutations, and the answer is naturally D!

It should be A, as if triploids cannot be combined, so genetic recombination cannot be performed.

For a, it is not moving to grind oranges like plants.

C viruses do not have a cellular structure, and some even have no ribose.

dMan is not on the land.

2,d Because the five characteristics of living things are: stress touring, growth and development, reproduction, adaptability, and a common material and structural basis.

3, C is the same as 2, because growth and development is one of the five characteristics of living things, and the rest are wrong.

, the process is self-breeding, F1 Ginkgo self-inbreeding with ginkgo and yellow fruit, then white is the dominant trait, yellow is the recessive trait, so F1 ginkgo is AA, F1 yellow fruit is AA; Further, P ginkgo is AA and yellow fruit is AA, so option D is incorrect.

The reason why option c is correct: F1 Ginkgo (probability 1 2) inbred to produce Ginkgo is 1 2*3 4=3 8, and to produce Yellow Fruit is 1 2*1 4=1 8;F1 Huangguo (probability 1 2) inbred to produce Huangguo 1 2*1=1 2, and F2 produced Huangguo 1 8+1 2=5 8

C F1: Yellow:White = 1:1

f2: 3 in yellow: white = 1:3

So yellow accounts for 1 2 + 1 2 * 1 4 = 5 8 white is 1 2 * 3 4 = 3 8 yellow: white = 5:3

D: If Ginkgo is AA, then the inbred offspring of F1 Ginkgo will not produce yellow seed.