10 How do you mix alcohol? Please write down the steps specifically

To prepare 10% alcohol, you need to follow these steps:

1.Based on the alcohol concentration to be formulated, calculate how much absolute ethanol and the amount of water are needed. For example, if you need to prepare 1000 ml of 10% alcohol, then you need 100 ml of absolute ethanol and 900 ml of water.

2.Pour the absolute ethanol into a clean container.

3.Pour the water into a container with absolute ethanol, taking care to add enough water in proportion to ensure that the alcohol concentration reaches 10%.

4.Mix absolute ethanol and water thoroughly with a stirrer or vortex mixer to mix well and evenly.

5.Filter the mixture to remove any precipitate or particulate matter that may be present.

6.Pour the mixture into a clean container, seal the container and mark the concentration of alcohol and the date of preparation.

Please note that it is important to follow the relevant safety regulations when preparing alcohol to ensure the safety of yourself and others.

It depends on how much alcohol you choose.

If you choose 100ml of 100% alcohol, you only need to add 900ml of distilled water to the alcohol and shake it well.

Because you don't tell the concentration, you can only be given a formula, and you can calculate the formulation yourself:

The formula is: x (need to add distilled water) [original liquid amount original concentration] new concentration] original liquid volume.

10 ml absolute ethanol.

Mix with 90 ml of distilled water, i.e., a 10% alcohol solution. That is, the volume ratio of absolute ethanol to distilled water is 1:9

% alcohol, is to indicate that the concentration of alcohol is expressed as a volume fraction, and its value is 75%, 2, the preparation of this question is a family, that is, the volume of 20% alcohol v, you need to determine first: for example v = 100ml

3. Calculate the volume of wine spines that need to be mixed with 20% alcohol: 20% x 100ml = 20 ml

4. Calculate the volume of 75% alcohol that needs to be measured: 20 = ml5, preparation: measure ml of 75% alcohol, add purified water to 100 ml, mix well, and you can.

20 3) * (50 5) = 200 3 times.

The solution was diluted a total of 200 3 times during this cavity.

Move 3ml to a 20ml volumetric flask to set the volume, which means add 3ml of water to the volume of 20ml, and dilute it by 20 3

Move another 5ml to a 50ml volumetric flask, (this should also be fixed, right?) You didn't say it in the question) If the volume is also fixed, it is to add water to the volume of 50ml, and dilute it by 50 5, so the solution in this process is 200 3 times.

First, calculate the volume of 95% alcohol required as 65%*250ml 95%=171ml, take 171ml of 95% alcohol and add water to dissolve in a beaker, and finally move it into a 250ml volumetric flask to determine the volume.

Solution: Let the volume of 95% alcohol required be xml, and obtain:

xml * 95% = 1000ml * 20%

Obtain: x = alcohol dilution The process of preparing a high concentration (95%) of alcohol (95% alcohol in a 500ml package) with a certain volume of water and a low concentration (e.g. 75%) alcohol.

This question tests the solution of an equation, and the value of an unknown number that makes the equation with an unknown hold is called a "solution" or "root".

The basis for solving the equation is to move some terms in the equation from one side of the equation to the other with the previous signs, and add and subtract, subtract and add, multiply and divide, and divide by multiplication.

Dilute it. For example, take 100ml of 95 alcohol, 95 , you need to add water, and you will be prepared with 75 degrees of alcohol.

For example, to prepare 100 ml of 75% alcohol: the calculation formula is calculated to find the volume of 95% alcohol v=(75%x100ml) 95%=.

Dilution operation: Add alcohol to a 100 ml dry graduated cylinder, dilute it with distilled water to a 100 ml engraved line, then transfer to a reagent bottle and label it.

Analysis: During dilution, the amount of solute is constant.

Take the configuration of 1000ml as an example:

Solution: Let the volume of 95% alcohol required be xml, and obtain:

xml * 95% = 1000ml * 20% yields: x =

Note: The concentration of alcohol refers to "volume concentration", not mass concentration. So just calculate the volume.

1 cup of 95% water is the result.

100ml of 95% alcohol filled with pure water is 60%.

The degree of alcohol is the volume ratio:

95/5+x =60/40x=

I'm not a professional, but I can help you figure out how to dilute it.

Volume fraction 95%, diluted to 60%, assuming 1L solvent, then there is 950ml of solute diluted to 60%, then 950ml of pure solute accounts for 60% of the solution, that is to say, every 1L of 95% edible alcohol will be diluted to 60% by adding 583ml of water, the same way, you want to dilute to how much % is used to divide by a few percent, and then subtract 1 to get the amount of solvent to be added.

95 60-1 = times.

That is, its multiplier volume of water is added to a 95% alcohol solution. For example, if you have 1000 ml of 95% alcohol, how many ml of water do you need to add to make 60 ml of alcohol?

1000 (95 60-1) = milliliters.

The degree of alcohol is the volume ratio:

95/5+x =60/40

x = says 100ml of 95% alcohol filled with pure water to mix 60%.

Add purified water to adjust the required alcohol concentration ratio, and use a measuring cup to operate to ensure a good ratio.

1. Use 100 alcohol to dilute to prepare 75% alcohol.

2. Alcohol dilution is the process of preparing (e.g., 75) alcohol with a low concentration (such as 75) alcohol after adding a fixed volume of water with a certain concentration of water.

3. Dilution operation: add ml of 100 alcohol to a 100 ml dry and clean graduated cylinder, dilute it with distilled water to a 100 ml engraved line, and then transfer it to a reagent bottle and label it.