vb column value substitution, VB two array content substitution issue

The condition in the SQL statement is not set correctly.

For example, update table name set column name = new value where student = a certain value.

When where is followed by student = a value corresponding to multiple pieces of data, all of them will be replaced.

The solution is.

Plus a unique field such as where id = value.

1. The program ** may be related.

2. Logical errors may occur after modification.

** Below:

dim a as string

a = "0101010"

mid(a, 3, 1) = "1"

print a

The result is: 0111010

What you said" "This one! Seek difference or.

1. Table ST01 is also an excel sheet or a table in another database?

2. Use VB operation to complete, or write macro ** directly in Excel to complete?

The implementation method and detailed operation steps are as follows:

1. First of all, a "student" data table, here you need to modify the data in the "studentname" data table in the data table, as shown in the following figure, and then go to the next step.

2. Secondly, after completing the above steps, open the database query statement, and then enter the query statement to query the data content in the data table, as shown in the following figure, and then enter the next step.

3. Then, after completing the above steps, enter the query statement marked as below, after entering, ask to select everything, and then select the execute button to execute the SQL statement, as shown in the following figure, and then enter the next step.

4. Then, after completing the above steps, the execution is completed, in the fourth row of data in the "student" table ("Cui" in "studentname"), you need to modify it to "bright", as shown in the following figure, and then enter the next step.

6. Then, after completing the above steps, directly select the internal content to modify it to "Bright", as shown in the image below, and then proceed to the next step.

7. Then, after completing the above steps, the modification is done, select Right-click on this and click on the "Go" option as shown in the image below and proceed to the next step.

8. Finally, after completing the above steps, the execution is completed, and the data query statement is used in the same way to query the data. You can see that the data content has been successfully modified, as shown in the following figure. In this way, the problem is solved.

First, clarify the data structure as follows:

a(userid,val)

b(userid,val)

Update the val value of the userid in table A to the val field of the corresponding userid in table B.

update b,a set where ;

Note: Action query is an area where SQL dialects are more commonly populated in different database management systems. The above statements are definitely OK in MySQL and Access, but other databases such as mssql have not been tested, if there is a problem, we will make adjustments.

Method 1: Try if this statement works:

update table_a set table_ table_ where table_;

Method 2Create a view:

First, create view view temp (select as num, as qh) from a,b where ;

Clause. 2. Update view:

update view_temp set num=qh

The database class in .net, if the preceding paragraph refers to this class, then it will not be followed by a).

1, the first statement is a connection, and this connection is to the database: dim CNN a as the new **quotient = ; Data source = c: This is your address database).

2. Connect to the database: CNN

3. New database operation command for customs declaration dim cmd a:

Is this the command you want to operate on the database? , such as select, update.sql statement cnn a).

4. Run the sql operation command: cmd a.

executeNonQuery().

5. Trash cans. 。Child, student. 。

Can you copy your current **?

Language has ambiguity, maybe you already feel that you are speaking in detail and clearly, but you can't understand it?

It's hard to type so many words for you, but this typography is so ugly that I didn't understand it after reading it twice.

Let xl1 be the ** variable you have assigned, then your question should be like this.

1) = "Numeric value"

Your question is still not clear enough, are the three columns in the graph the coefficients of y=ax 2+bx+c? If so, then there are multiple quadratic equations. x takes any value, is it a random number or a set of numbers?

Result y placed in **? Without further information, it's really hard to know where to start.

Suppose the y value is in column d.

Enter =A1+B1+C1 in D1

You can interpolate with data. It is also possible to use fitted.