Mathematics high school experts please, math experts please

This kind of topic is ...... with one ideaI don't know what I thought about it, but that's what I did.

px^2+(p-3)x-3>0

p(x^2-x)-3(x+1)>0

1<=p<=1】

Let f(p)=p(x 2-x)-3(x+1).

then x is regarded as a parameter, and f(p) is monotonic on [-1,1].

So f(-1)=-x 2+x-3x-3=-x 2-4x-3>0

x^2+4x+3=(x+1)(x+3)<0

f(1)=x^2-x-3x-3=x^2-2x-3=(x-3)（x+1）>0

Just take the union. (Because the question requires the existence of p, and we have p as the main element).

This method is called master-slave substitution, that is, the slave element (parameter) is regarded as the master element (independent variable), which is relatively simple.

Organized as x(x+1)>3(x+1) p

The straight line y=3(x+1) p passes the fixed point (-1,0) and the slope range is (- 3) (3,+).

Parabola y1 = x (x + 1) passes through the point (-1,0), (0,0).

Find the solution of y1>y2 in the line system y2=k(x+), k (-3) (3,+).

Make a straight line y=-3(x+1) and y=3(x+1) to shadow the area to which the corner of the upward opening belongs.

then the image of the parabola in the shaded area is in line with the title.

y=3(x+1)=x（x+1）

The intersection of the first quadrant is (3,12).

So x ranges to x<-1 or x>3

I'll talk about it casually (I haven't done it for a long time).

Can you discuss it by category, the scope of p is:

Then do it using the monotonicity of the quadratic function.

Then you can discuss the range of the root as a quadratic function, the symmetry axis.

Summary. Hello dear I don't know what kind of confusion you have encountered, can you describe it to me in detail and see if I can give you some advice.

High school math problems, a math master, thank you.

Hello dear I don't know what kind of confusion you have encountered, can you describe it to me in detail and see if I can give you some advice.

18 questions are sufficient, and if it is not convenient to type, you can write them down on paper and send them to me.

Summary. Please send me a question.

High school math problems, a math master, thank you.

Please send me a question.

You can take a photo and post the question.

17 all, and 18 (1) to ask, thank you, if it is inconvenient to type, you can write on paper and send it to me, thank you.

Okay. In the first question of the seventeenth question, you can apply the sine theorem, and in the triangle ABC, you can find the length of BC.

In the triangle ABC, each side can be found.

Summary. Hello dear, the process answer is as follows: first, I want to prove that BC is perpendicular to DC1, then first consider proving that the line is perpendicular to the surface, that is to say, to prove that BC is perpendicular to the surface CC1D Second, to prove that the line is perpendicular to the surface, then it is necessary to prove that the line is perpendicular to the two intersecting lines in the surface, then we already know that BC is perpendicular to CC1, and then prove that BC is perpendicular to another line, and third, according to the ** plane diagram, it is found that if the 120-degree angle condition is used, it can be proved that BC is perpendicular to CD, This is very easy, so we achieve the proof that the line is perpendicular to the surface, and finally we get the <> BC perpendicular to DC1

High school math problems, a math master, thank you.

Hello dear, may I ask what your math problem is?

20 questions The first question.

Hello, please as soon as possible, thanks.

Okay? Hello dear, it's been written, and the process is in**.

Thank you. Hello bent sedan open, the process answer is as follows: first, I want to prove that BC is perpendicular to DC1, then first consider proving that the line is perpendicular to the surface, that is to say, to prove that BC is perpendicular to the buried surface CC1D Second, to prove that the line is perpendicular to the surface, then it is necessary to prove that the line is perpendicular to the two intersecting lines in the plane, then it is already known that BC is perpendicular to CC1, and then prove that the sail ridge is perpendicular to the other line, third, then according to the ** plan, it is found that if the 120-degree angle condition is used, It is very easy to prove that BC is perpendicular to CD, so we can prove that the line is perpendicular to the surface, and finally we get the <> BC perpendicular to DC1

Summary. When judging from scatter plots, you need to look at the overall trend and distribution between data points. A linear regression model y=a+bx is more appropriate if the data points are distributed linearly or nearly linear, indicating a strong linear correlation between y and x.

If the distribution of data points is not linear, you may want to consider a nonlinear regression model. Conversely, if the data points exhibit a parabolic shape relationship of "opening up" or "opening down", a quadratic regression model y=c+dx is more suitable. Therefore, based on the scatter plot, it is possible to preliminarily determine which regression model is more suitable for fitting the data.

However, the final determination of the regression equation requires mathematical statistical analysis, index evaluation and empirical testing to ensure that the regression equation has certain reliability and validity.

High school math problems, a math master, thank you.

Good kiss. If it's not convenient to type, you can write it down on paper and send it to me, thank you.

Good kiss. When judging from scatter plots, you need to look at the overall trend and distribution between data points. A linear regression model y=a+bx is more appropriate if the data points are distributed linearly or nearly linear, indicating a strong linear correlation between y and x.

If the distribution of data points is not linear, you may want to consider a linear frontal regression model. Conversely, if the data points exhibit a parabolic shape relationship of "opening up" or "opening down", a quadratic regression model y=c+dx is more suitable. Therefore, based on the scatter plot, it is possible to preliminarily determine which regression model is more suitable for fitting the data.

However, the final determination of the regression equation requires mathematical statistical analysis, index evaluation and empirical test to ensure that the regression equation has a certain reliability and Li Zheng validity.

Summary. Hello I don't know what kind of confusion you have encountered, can you describe it to me in detail and see if I can give you some advice.

High school math problems, a math master, thank you.

Hello I don't know what kind of confusion you have encountered, can you describe it to me in detail and see if I can give you some advice.

Hello I don't know what kind of confusion you have encountered, can you describe it to me in detail and see if I can give you some advice.

I only do the first question, thank you.

Okay, expect 5-10 minutes to give you the handwriting process.

22 questions for the first question.

21 first questions.

What is this making equal to 0?

Triangle, delt

The discriminant formula of a quadratic equation with one solution, no solution, and two solutions.

Summary. 21 Questions: (1) The equation is:

x2 a2-y2 b2=1(2) set the point g(x1,y1),h(x2,y2), then there is: x1 2 a 2-y1 2 b 2=1x2 2 a 2-y2 2 b 2=1 subtract the two formulas to obtain: (x1 2-x2 2) a 2-(y1 2-y2 2) b 2=0 i.e.:

x1-x2) a 2 = (y1-y2) b 2 is known to: x1-x2=2 root number 2y1-y2 = 3 to obtain: 2 root number 2 a 2 = 3 b 2 i.e.:

A b = root number 2 3 and because the focal length is 10, there are: c 2 = a 2 + b 2 = 100, that is: a 2 = 50, b 2 = 50 from a b = root number 2 3:

A = 5 root number 2, b = 5 root number 3, therefore: gd ge=hd he=5 root number 2 5 root number 3 = root number 2 root number 3

High school math problems, a math master, thank you.

21 Questions: (1) The equation is: x2 a2-y2 b2=1 (2) set the point g(x1,y1) and h(x2,y2), then there is:

X1 2 A 2-Y1 2 B 2=1X2 2 A 2-Y2 2 B 2=1 Subtract the two formulas to obtain: (X1 2-X2 2) A 2-(Y1 2-Y2 2) B 2=0 i.e.: (X1-X2) A 2=(Y1-Y2) B 2 is known to be nuclear:

x1-x2=2 root number 2y1-y2 = 3 get: Nian Huai 2 root number 2 a 2 = 3 b 2 i.e.: a b = root number 2 3 and because the focal length is 10, there is:

c 2 = a 2 + b 2 = 100 i.e.: a 2 = 50, b 2 = 50 from a b = root number 2 3: a = 5 root number 2, b = 5 root number 3 so:

gd ge=hd he=5 root number 2 5 root number 3 = root number 2 root number 3

Question 19: (1)a n=t n-1a n-1=t n-2a n-1=t(t n-2)a n=t n-1 General formula: pat a n=t n-1(2)m 1 a 1+2 a 2+.

n/a^nm≥1/t^0+2/t^1+..n/t^n-1m≥(1+2+..n) t n-1m then stuffy (n(n+1) 2) t n-1m (n(n+1) 2) (t n-1) minimum value:

m=(n(n+1)/2)/(t^n-1)

, then share 5,000 kg of rapeseed.

It can extract 1680 kg of oil.