Questions about subnetting

The first building, the number of hosts: 100;

Subnet Mask:;

Network number:; Host IP range:;

The second building, the number of main units: 64;

Subnet Mask:;

Network number:; Host IP range:;

Network Center, number of hosts: 120;

Subnet Mask:;

Network number:; Host IP range:;

The third building, the number of main engines: 25;

Subnet Mask:;

Network number:; Host IP range:;

Network servers and equipment, number: 20;

Subnet Mask:;

Network number:; Host IP range:;

The fourth building, the number of main units: 12;

Subnet Mask:;

Network number:; Host IP range:;

The fifth building, the number of main units: 8;

Subnet Mask:;

Network number:; Host IP range:;

126 usable hosts 100 hosts building.

16 buildings with 8 mainframes.

30 buildings with 25 hosts.

16 buildings with 12 mainframes.

30 available 20 web servers.

126 buildings with 64 mainframes.

126 available 120 network centers.

4 mainframes for 5 buildings. The school wants 3 hosts.

The IP address starting with 35 belongs to a Class A address, and the default subnet mask is generally expressed as. Since the title requires that this class A address be divided into 48 subnets, the principle of subnet division is 2 n(n......That is, you can only press ......In this way, it needs to be divided into 48 subnets, and it is actually divided into 64 subnets.

1. Since n=6, it means that the original default subnet mask needs to borrow 6 bits, that is, it becomes, and the decimal subnet mask is.

Paragraph 0: Paragraph 1:

Paragraph 2: Paragraph 38:

2. After dividing the subnet, the largest subnet network address is, and the smallest subnet network address is.

3. The maximum available host address in the maximum subnet address range is, and the smallest available host address is.

4. The maximum available host address in the minimum subnet address segment is, and the smallest available host address is.

You can divide 512 subnets by borrowing 9 bits, which is greater than 510; So the netmask is 25 bits, b answer;

Class B masks are.

16-bit; If you want 510 subnets, you need to divide them by borrowing, borrowing one bit is to divide 2 subnets, borrowing 2 bits can be divided into 4, borrowing n bits can divide 2 n,,, you know to borrow 8 bits to divide 256, borrow 9 bits to divide 512 (2 n = >510, you just ask n); The mask of the subnet is 16 + 9 = 25 bits, that is, the first 25 bits of the subnet mask are 1

Convert to decimal system.