ABC is an equilateral triangle, D is a point on the straight line BC, ADE 60, CE AB

1. Proof : take the point F on AC, make CF=CD, connect DF ACB=60°, DCF is an equilateral triangle

1+∠ade=∠2+∠ace，∠1=∠2．△adf≌△edc（aas）．

ce=af．

cd+ce=cf+af=ca=ab

2. CD, CE, CA meet CE+CA=CD;

Take CF=CD from the CA extension cable and connect it to DF

ABC is an equilateral triangle, ACD=60°, CF=CD, and FCD is an equilateral triangle

1+∠2=60°，∠ade=∠2+∠3=60°，∠1=∠3．△dfa≌△dce（asa）．

ce=fa．

ce+ca=fa+ca=cf=cd．

i.e. CE+AB=CD

1) Prove: Take the point F on AC, so that CF=CD, ACB=60°, DCF is an equilateral triangle

3 + 4 = 4 + 5 = 60°

1+ ADE= 2+ ACE, 1= 2 in ADF and ECD, 1= 2, 3= 5,CD=DF, ADF EDC

ce=af．

cd+ce=cf+af=ca．

2) Solution: CD, CE, CA satisfy CE+CA=CD; The proof is as follows:

Take CF=CD, ACD=60° on the CA extension line, and do the cavity search, and FCD is an equilateral triangle

In DFA and DCE.

f= dce, df=cd, 1= 3, dfa dce ce=fa

ce+ca=fa+ca=cf=cd．

1) Extend EC to F, so that the liquid is cf=cd, and the connection DF is easy to know: CDF is an equilateral triangle, ACD= EFD=60°,CD=FD, ADC= ADE+ CDE=60° CDE, EDF= CDF+ CDE=60° CDE, ADC= EDF, ADC EDF, CA=FE=CF+CE=CD+CE

2) C=Ca+CE, extend AC to F, connect AE, EF, and it is easy to know that CEF is an equilateral triangle, ade=60°, ace=120°, A, C, E, D four-point contour, fae= cde, aed= acd=60°, AEF= AEC+ CEF= AEC+60°, dec= AEC+ AED= AEC+60°, DEC= AEf, and CE=FE, so DEC AEF, CD=FA=AC+ce，

Good boy, do it yourself. There are benefits to using your brain more.

The ground floor is wrong, that's all I can say.

No change. ∠abc=∠ebf=60°

Panicle abc- ebc= ebf- ebc, i.e. abe= cbf

AB=BC, BE=BF

Sakura code ABE is equal to CBF (corner edge).

ae=fc, that is, ae fc=1 is the value of Dingnasong.

No change. Proof: abc and bef are equilateral triangles.

ab=bc be=bf

abc= ebf

abe= ∠abc- ∠ebc

cbf= ∠ebf- ∠ebc

ABE= Blind Burning CBF

In ABE vs. CBF.

ab=bc, abe=cbf

be=bf, so abe is equal to cbf(sas)ae=fc

The inscription is wrong, how do you take the point f? Is ae a dynamic value and dc a fixed value? There is no picture and no truth.