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However, the application of this method in synthesis.

Hydroxyindole phosphate with a nucleophile of phosphorus.

has not yet been realized, probably due to the strong.

Substrate and product coordination. At.

In addition, these reactions are generally used with (OAC).

Oxidant to make phosphorus nucleophile.

Decomposition under strong oxidizing conditions. In the past.

For several years, we have focused our efforts and developed.

New and effective transition metal catalyzed protocols.

Formation of Cp bonds. [10] It has been found that relatively mild.

Salts of copper and silver can be formed with ph2p(o)h.

The corresponding active [pH2P(O)Cu] or [Ph2P(O)] complexes AG can be used for the addition of olefins. [ 11 ]

For these factors, we speculate that silver or copper.

Salts may catalyze the functionalization of carbon phosphorus.

olefins and are obtained by direct cyclization.

It has the corresponding phosphorylated hydroxyindole.

It could be a new pesticide or herbicide. [12] In addition, it can also be used as a p-to-transition metal O-ligand

Catalytic reactions. Through our efforts, a new approach.

Catalytic functionalization of carbon phosphorus for silver nitrate.

Olefins have been developed and demonstrated several.

Unique features (Scheme 1): 1) Different palladium, silver heads.

with PH2P(O)H and the formation of key intermediates.

2a, thereby facilitating the reaction;

1.The following groups of substances were added to the water, and a chemical reaction occurred, but there was no obvious phenomenon ().

There is caCO3 precipitation.

BCUSO4, NaOH, Na2CO3 - with basic copper carbonate precipitation.

There is a neutralization reaction, but there is no obvious phenomenon.

No response. The answer is to remove the impurities in the following solutions (impurities in parentheses) and write the chemical equation for the impurity removal reaction

1）nacl(fecl3)：fecl3

3naohfe(oh)3↓

3nacl2）kno3(agno3)：agno3

kclagcl↓

kno33）naoh(na2co3)：na2co3

ca(oh)2

caco3↓

2naoh3.The following groups of substances are put into water separately, and there is no precipitation at the end, and the colorless and transparent solution is obtained with () Baso4 precipitation.

There is caCO3 precipitation.

Add more HCl, you can have no precipitation, and get a colorless solution.

There is no reaction, but the Fe3+ ions are colored and appear yellow.

The answer is to verify the order of activity of the three metals of mg, fe, and cu, and the best reagent set to use is ( ).

No response, no verifiability.

Yes, fecuso4

FeSo4Cu, while Fe does not react with MgCl2 solution.

No response, no verifiability.

mg+cuso4=cu

mgso4，mg

feso4mgso4

fe, can be replaced, still can't be compared.

The answer is to mix the solution of the two substances in each of the following groups, there is a precipitation, add a sufficient amount of dilute hydrochloric acid, the precipitate is partially dissolved and filtered, and the filtrate is yellow, then the substances in this group are: (

a.Sodium hydroxide, ferric chloride: FeCl3

3naohfe(oh)3↓

3nacl，fe(oh)3

3hclfecl3

3H2O, the precipitate was completely dissolved.

b.Sodium hydroxide, copper sulfate: CuSO4

2naohcu(oh)2↓

na2so4，cu(oh)2

2hclcucl2

2H2O, the precipitate is completely dissolved.

c.Barium hydroxide, iron sulfate: 3Ba(OH)2

fe2(so4)3

2fe(oh)3↓

3BaSO4, but in the case of hydrochloric acid, only Fe(OH)3 is dissolved, Fe(OH)3

3hclfecl3

3H2O,Baso4 is insoluble in hydrochloric acid.

d.Calcium carbonate, calcium chloride: CaCl2

na2co3

caco3↓

2nacl，caco3

2hclcacl2

CO2 H2O, precipitate fully dissolved.

Answer: Carbonate is known to be more acidic than hypochlorous acid (HCLO), and carbon dioxide reacts with positive carbonate to form acid salts, so please write the chemical equations for excess carbon dioxide to sodium hypochlorite solution and calcium hypochlorite.

nacloco2

h2onahco3

hclo，ca(clo)2

2co22h2o

ca(hco3)2

2hclo

1. Select C, the carbonate in A should react with calcium ions to form a white precipitate; Item b copper ions and hydroxide groups form blue precipitates; Item d does not undergo a chemical reaction. In the second question, NaOH is used to remove FeCl to generate precipitation filtration; In addition to AGNO3, KCl is used to generate white precipitate filtration, NaCO3 in NaOH is used to generate Ca(OH)2 to generate precipitation filtration to remove the third question D, item A generates Baso4 precipitate and is insoluble in nitric acid, item B generates CaCO3 precipitate, and item C generates BaCO3 precipitate... The word is too difficult to type, so it's like this, I hope to understand, pure hand typing, hope to adopt.

Because HCl+NaOH = H2O+NaCl

There is no obvious phenomenon.

kcl+agno3=kno3+agcl↓

Ba(OH)2+2Na2CO3=2NaOH+BACO3 turns back into barium sulfate, which is stubbornly precipitated.

BCACo3 precipitation.

c Barium carbonate precipitation. Let's choose D.

4.I choose B, and the others cannot be placed.

Precipitated iron hydroxide is red, b copper hydroxide is not allowed to dilute hydrochloric acid.

c Barium sulfate stubbornly precipitates, insoluble in acid and alkali.

d calcium has no color.,Pit.。。 And then you can't do it.

6.Pitted.

1,1) Water is composed of hydrogen and oxygen, so it is incorrect 2) Correct.

3) Seawater is a mixture, containing water, sodium chloride and other salts 2ac3m(h):m(o)=2*1:(16)=1:8d

1, diethylaminothiocarbamate-s-s-(4-chlorobenzyl)ester 2, -naphthylamine and its salts.

3, chloromethyl ether.

Dichloro-diaminodiphenylmethane.

5, Di-dimethylamino.

and N2, indicating that their average relative Hopper Leak molecular Heldane mass is 28.

Since the relative molecular mass of CO is 28, its amount can be arbitrary.

The key is H2 and CO2. Using the cross method, the volume ratio of CO2 and H2:

So as long as the volume ratio of CO2 to H2 is 13:8, it is right. Or.