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Solution: From known conditions, obtained.
3b-2=0
2a-b-3=0
The solution yields a=11 6 b=2 3
Original = 10a-5b-12a+4b-4+4a-3b-1 22a-4b-9 2
Substituting a=11 6 b=2 3 into an algebraic formula.
There are 2*11 6-4*2 3-9 2
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|3b-2|2a b 3 0 and |3b-2|Greater than or equal to 0, 2a b 3 greater than or equal to 0
3b-2|=0 to get 3b=2 b=2 3
2a b 3 0 gives 2a-b-3=0 2a-2 3-3=0 2a=11 3 a=11 6
5﹙2a-b﹚-2﹙6a-2b+2﹚+﹙4a-3b-1∕2﹚10a-5b-12a+4b-4+4a-3b-1∕210a-12a+4a-(5b-4b+3b)-(4+1/2)2a-4b-9/2
Substituting a=11 6, b=2 3 into the algebraic formula, obtain.
2a-4b-9/2
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In the front of the elimination of 5-3a 2b + 2ab = 1, 3a b - 2ab = 5 - sell regret and filial piety 1 = 4, 6 - ab + 3 2a2b
6+1 2 (3a b a 2ab).
6+1/2x4
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2a-3b) 2-a-(a2b)(a-2b) a(a-2b) a(a-5b)(a-b) 4a2a-12ab 9b2a-2a-2 4b 2-a-2a-4ab 5b2
2a 2 16ab 18b 2
2 (a 2 a 8ab 9b 2) noisy burial.
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2a+5b-3=0,2a+5b=3,4a
32b22a
25b22a+5b
8. Which liter to rush.
Therefore, the delay in answering the old case is 8
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It is known that the bucket skin 3a-4b+5=0
Then 4b-3a=5 3a-4b=-5
4b-3a)^2+6a-8b-2
5 2+2 (3a-4b) -2
25+2 (-5) keybook-2
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From the question, we can get the ruler, (Ling lead Wang 3b-2) 2=0, |2a-b-3|=0, then b=2 excite3, a=6 11
Original = -581 66
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Solution 5a-5b-12a+4b-4+
Bu Wei 5a-12a+4a-5b+
The disadvantages are high.
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Because the absolute value is not negative.
So 3b-2=0 2a-b-3=0
b=2/3 2a-2/3-3=0
a=11/6
Substitute the values of a and b into 5(2a-b)-2(6a-2b+2)+(4a-3b-1 2).
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.1. Obtain the system of equations according to the meaning of the question:
3b-2=0
2a-b-3=0
The solution is: a=11 6, b=2 3,5(2a-b)-2(6a-2b+4)+(4a-3b-2)=10a-5b-12a+4b-8+4a-3b-2=2a-4b-2
11/3+8/3-2=13/3,2、(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
2ab+2a+3b-3ab-2b+2a-a-4b-ab=-6ab+3(a-b)
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1.Since both terms are greater than or equal to zero, the formula 3b=2 2a-b=3 is reduced to 15-(8a-b+10)=5-(6a+2a-b)=5-11-3=-9
2.The formula is simplified to -6ab+3(a-b)=-6+12=6
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Solution: 3(2a-3b) 0 2|5b-2c|0 is not a negative number.
and is 0, then.
3(2a-3b)²=0 2|5b-2c|=02a-3b=0 5b-2c=0
2a=3b 5b=2c
10a=15b 15b=6c
That is, 10a = 15b = 6c
a:b:c=3∶2∶5
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Remember: |a-3|is a positive number, (b+4) is also a positive number, and the addition of two positive numbers gives 0, which only means that both numbers are 0, so |a-3|=0,a=3,,(b+4) =0,b=-4, so a+b=-1
Solution:1. Because a+b=3, ab=1, 1 a+1 b=(a+b) ab
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