If 3b 2 2a b 3 0, find the value of 5 2a b 2 6a 2b 2 4a 3b 1 2

Updated on educate 2024-05-18
12 answers
  1. Anonymous users2024-02-10

    Solution: From known conditions, obtained.

    3b-2=0

    2a-b-3=0

    The solution yields a=11 6 b=2 3

    Original = 10a-5b-12a+4b-4+4a-3b-1 22a-4b-9 2

    Substituting a=11 6 b=2 3 into an algebraic formula.

    There are 2*11 6-4*2 3-9 2

  2. Anonymous users2024-02-09

    |3b-2|2a b 3 0 and |3b-2|Greater than or equal to 0, 2a b 3 greater than or equal to 0

    3b-2|=0 to get 3b=2 b=2 3

    2a b 3 0 gives 2a-b-3=0 2a-2 3-3=0 2a=11 3 a=11 6

    5﹙2a-b﹚-2﹙6a-2b+2﹚+﹙4a-3b-1∕2﹚10a-5b-12a+4b-4+4a-3b-1∕210a-12a+4a-(5b-4b+3b)-(4+1/2)2a-4b-9/2

    Substituting a=11 6, b=2 3 into the algebraic formula, obtain.

    2a-4b-9/2

  3. Anonymous users2024-02-08

    In the front of the elimination of 5-3a 2b + 2ab = 1, 3a b - 2ab = 5 - sell regret and filial piety 1 = 4, 6 - ab + 3 2a2b

    6+1 2 (3a b a 2ab).

    6+1/2x4

  4. Anonymous users2024-02-07

    2a-3b) 2-a-(a2b)(a-2b) a(a-2b) a(a-5b)(a-b) 4a2a-12ab 9b2a-2a-2 4b 2-a-2a-4ab 5b2

    2a 2 16ab 18b 2

    2 (a 2 a 8ab 9b 2) noisy burial.

  5. Anonymous users2024-02-06

    2a+5b-3=0,2a+5b=3,4a

    32b22a

    25b22a+5b

    8. Which liter to rush.

    Therefore, the delay in answering the old case is 8

  6. Anonymous users2024-02-05

    It is known that the bucket skin 3a-4b+5=0

    Then 4b-3a=5 3a-4b=-5

    4b-3a)^2+6a-8b-2

    5 2+2 (3a-4b) -2

    25+2 (-5) keybook-2

  7. Anonymous users2024-02-04

    From the question, we can get the ruler, (Ling lead Wang 3b-2) 2=0, |2a-b-3|=0, then b=2 excite3, a=6 11

    Original = -581 66

  8. Anonymous users2024-02-03

    Solution 5a-5b-12a+4b-4+

    Bu Wei 5a-12a+4a-5b+

    The disadvantages are high.

  9. Anonymous users2024-02-02

    Because the absolute value is not negative.

    So 3b-2=0 2a-b-3=0

    b=2/3 2a-2/3-3=0

    a=11/6

    Substitute the values of a and b into 5(2a-b)-2(6a-2b+2)+(4a-3b-1 2).

  10. Anonymous users2024-02-01

    .1. Obtain the system of equations according to the meaning of the question:

    3b-2=0

    2a-b-3=0

    The solution is: a=11 6, b=2 3,5(2a-b)-2(6a-2b+4)+(4a-3b-2)=10a-5b-12a+4b-8+4a-3b-2=2a-4b-2

    11/3+8/3-2=13/3,2、(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)

    2ab+2a+3b-3ab-2b+2a-a-4b-ab=-6ab+3(a-b)

  11. Anonymous users2024-01-31

    1.Since both terms are greater than or equal to zero, the formula 3b=2 2a-b=3 is reduced to 15-(8a-b+10)=5-(6a+2a-b)=5-11-3=-9

    2.The formula is simplified to -6ab+3(a-b)=-6+12=6

  12. Anonymous users2024-01-30

    Solution: 3(2a-3b) 0 2|5b-2c|0 is not a negative number.

    and is 0, then.

    3(2a-3b)²=0 2|5b-2c|=02a-3b=0 5b-2c=0

    2a=3b 5b=2c

    10a=15b 15b=6c

    That is, 10a = 15b = 6c

    a:b:c=3∶2∶5

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