A 3 b 4 squared 0 then a b

Remember: |a-3|is a positive number, (b+4) is also a positive number, and the addition of two positive numbers gives 0, which only means that both numbers are 0, so |a-3|=0,a=3,,(b+4) =0,b=-4, so a+b=-1

It can be seen according to the title.

a-3|=0，a=3

b+4) squared = 0, b = -4, a+b) = -1

Because the absolute value of a-3 is 0 and the square of b+4 is 0 so a=3 b=-4 so a+b=-1

There is ambiguity in the question you are asking. Is it the square of the whole equation, or is it the square of (a+b)???

a-3 is greater than or equal to 0, (b+4) is greater than or equal to 0, so in this equation a-3 =0, b+4=0, so a=3 b=-4, so a+b=3-4=-1

From the question, we can see that a-3=0 b+4=0

solution, obtain: a=3 b=-4

Original formula = a+b = 3+(-4).

The steps and processes are taught by our teachers in this way, and they should be very standard.

Because |a-3|The square of +(b+4) = 0, so a-3=0, b+4=0, so a=3, b=-4

Then 2*a+4*b

By |a-3|≥0 ，（b+4）^2≥0

and |a-3|+(b+4) squared = 0, we get a-3=0, b+4=0, so a=3, b=-4,..

The sum of two non-negative numbers is equal to 0, so there is a+2=0, b-4=0, i.e., a=-2, b=4, then a+b=-2+4=2

Because the square of (a+2) + b-4 = 0

So a+2=0 b-4=0

The solution gives a=-2 b=4

So a+b=-2+4=2

Because |a+2|+(b-3) squared = 0

So: a+2=0

b-3=0So: a=-2, b=3

So: a-b=-5

|a+3|If it is greater than or equal to 0, the square of (b-2) is greater than or equal to 0, and the sum of 2 is 0, which means that both are equal to 0, so a+3=0, a=-3, b-2=0, b=2, a-b=-5

Solution.|a+3|+(b-2) squared = 0, each term is greater than or equal to 0, and the above equation holds only that every term is equal to 0

then a+3=0 gives a=-3

b-2=0 gives b=2

a-b=2-（-3）=5

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-5, the absolute value and the square will not be negative, and the sum of the addition will not, now 0 can only be 0+0=0, that is, a=-3, b=2;

Solution: First of all, you need to know the absolute value.

and the square of the meaning.

The absolute value and the square number 0, while the equation=0

Rule. a-4=0

b+1=0.

a=4b=-1

then a+b=4-1=3

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Because the equation is equal to 6, the left side of the equation is constant positive, so it must be a-4=so a=

From the question, a+b-3=0, a-b+5=0

then a+b=3, a-b=-5

Get a=-1 b=4

The square of a - the square of b = -15

(a+b-3) + |a-b+5|=0

a+b-3) squared = 0, |a-b+5|=0a+b=3,a-b=-5

The square of a - the square of b.

a+b)(a-b)

∵（a+b-3)²≥0；+|a-b+5|≥0∴a+b-3=0

a-b+5=0

The solution yields a=-1 and b=4

Then the square of a - the square of b = 1-16 = -15