Electrician friends help. 10

You are talking about a single connection and double control, a total of three wires, one lamp head is connected to the positive power supply and the other is connected to the terminal pile in the middle of the switch, the negative power line is connected to the terminal pile in the middle of the other switch, and there are two wires connected to the terminal pile at both ends of the two switches. Do you understand? The diagram you drew is missing a line, find an electrician to the scene to check the circuit, in the embedded two wires from the switch to the other switch, one of the switch positive wire abolish the power negative wire switch in the middle of the terminal pile embedded in the two switches are connected to the two ends of the terminal pile on the two switches are OK, what I said is that both switches have power lines from a meter next.

I spent an afternoon on your problem for the first time I didn't see it, the second time it was incomplete, and I added it again for fear that you don't understand, and you're not a little sorry for me. Just kidding!

Look at what you're talking about. You should connect it like this here, you put the power supply (you said it should be the fire wire, right?) ) to the terminal hole marked "L" of the switch, and then connect the other two to the terminal hole "L1" and "L2" respectively.

The other side is the same as the one on this side.

Absolutely, and you've got an extra line. Both sides can take the power supply, take one at either end of the neutral wire (blue N), and connect the switches on both sides to the live wire (red L) respectively. Specific:

1. One inlet light from the zero line. 2. Live Wire 1 - switch --- light.

3. The 2--- switch --- lights of the live wire. In layman's terms, there are a total of 3 wires on the last lamp, two live wires and one zero line.

If there is a power supply on both sides of the switch, plus the switch on both sides and the lamp are walking a line (that is, the same line), that is, there are 3 wires on each side of the switch box, and there is only one wire on the lamp, cut it and connect it to the lamp. You still don't understand me q491275032

This really won't solve it.

Both voltage sources are converted into current sources.

Two current sources are combined into a single current source.

with a simplified circuit diagram.

Find the potential of point a.

Find homework help, think about it yourself, and ask the teacher.

I also know what the head teacher of the ancient second class said.

(1) Apparent power of the electrical appliance at the time of the power factor =

The number of electrical appliances that can be connected is 440kva).

2) If the power factor is raised to 1, the apparent power is equal to the active power, and the number of electrical appliances that can be connected is 440kva).

(1) Active power apparent power = power factor 44 440 = (2) 100

.The power factor is 50 when it is , and 1 is 100.

The total power remains the same, or 5 23 = 115kw, the load is evenly distributed in three phases, and each phase has a maximum of 8 rooms, which is 40kw. Therefore, according to the maximum power of each phase, the power is 120kw, and the power factor is calculated according to the calculation, and the current of each phase is 227A.

The distribution is balanced, and the total power should be 40kw.

The three boxes are balanced, and the current is calculated on a single item.