-
In salt water, the buoyancy is equal to the weight of the egg, while in clear water it is less than the weight of the egg: the amount of buoyancy is equal to the weight of the liquid it distributes, and in both cases the volume of the liquid discharged is equal and equal to the volume of the egg, but the salt water discharged in the brine is denser and buoyant.
-
Buoyancy in salt water is equal to the gravitational force of the egg, and buoyancy in water is less than gravity. Therefore, the buoyancy in the salt water is large.
-
In salt water, buoyancy equals gravity, the two forces are balanced, and the egg is at rest.
In clear water, buoyancy is less than gravity. Buoyancy plus the supporting force (at the bottom of the container against the egg) equals gravity, the three forces are balanced, and the egg is at rest.
-
Buoyancy = volume of liquid discharged x specific gravity of liquid.
Know. The specific gravity of salt water is greater than that of water.
Place. It is buoyant in salt water.
Small in water. So in salt water is floating.
In the water is sinking.
And the buoyancy in the salt water is equal to the gravitational force of the egg.
So it floated.
-
The egg floats in salt water, and the buoyancy is equal to the gravitational force when at rest. The sinking of the egg in the water indicates that the buoyancy of the egg is not enough to resist gravity, and the gravity force is low before sinking. So the buoyancy experienced in the water is less than the buoyancy experienced in the salt water.
-
The object is in water, and the buoyancy is equal to the gravitational force when floating; Buoyancy is less than gravity when sinking to the bottom. The gravity of the eggs is the same twice, so it is buoyant in salt water!
-
1. Arbitrarily divide into 3 parts, 3 pieces each; Take two portions and put them at both ends of the balance 2, if there is one side light, prepare to weigh the light one; If both sides weigh the same, be prepared to weigh the one that is not on the scale.
3. Take any two of the three balls and place them at both ends of the scale.
4. If one side is light, it is a hollow ball; If it is the same weight, then the unweighed ball in step 3 is a hollow ball.
-
Divided into 3 groups of 3 each.
Take 2 groups first, the hollow ball is in the light group, and if it is balanced, it is in the third group.
Then take 2 balls in this group, the light one is the hollow ball, and if it is balanced, the remaining one is hollow
-
Take 3 of the 9 balls at random, and divide the remaining 6 into two groups (3 in a group) and place them on either side of the scale. The first situation: if the balance balance, that is, the hollow ball does not participate in the weighing of the 3 balls, and then select one of the 3 balls, the remaining 2 are placed on both sides of the balance to weigh, the same way as the balance balance is not to participate in the weighing of a ball is a hollow ball, if the balance is unbalanced, the lighter side of the ball is a hollow ball.
The second case: if the balance is unbalanced, the hollow ball is in the lighter side of the 3 balls, take out the 3 balls and weigh them again according to the above steps to determine the hollow ball.
-
9 balls are divided into 3 points, each part is 3 balls, first two of them are placed on both sides of the scale, if one side is tilted upward, there must be that hollow ball in the pile, if the two sides are balanced, then the remaining part is a hollow ball. Divide the three balls with the hollow into three parts, if one side is tilted upward, the upward side is the hollow ball, and if it is balanced, then the ball that is not weighed is hollow.
-
No. Maybe not even a little bit.
-
This is the reason for the elastic change and the plastic change.
When the critical force is lower than the critical force, complete elastic deformation occurs, and incomplete elastic deformation occurs within a certain range.
This is also related to the shape of the material, for example, an egg, after a small opening, there is a longitudinal force, which is easy to break, in the case of an ellipse, a lot of force is canceled out, so it is not easy to break.
-
Of course not. There is also a problem of friction force involved here, and the total work done by the combined force of your force and frictional resistance is the common cause of the thickness. You think that way, just considering the work of manpower and ignoring the frictional resistance. Hope it helps.
-
As the "trainee embarrassment" said, the centripetal force is not a constant force, no matter how many constant forces you use to act on an object, according to the synthesis of the force, the final result is still a constant force.
Therefore, it is correct if the object is likely to do a curvilinear action under the action of constant force.
-
When an object moves in a circular motion, the direction of the centripetal force always points to the center of the circle, and it can be said that the direction of the force changes all the time, so it is not a constant force, and c is not right, and it is impossible for an object (i.e., constant force) to get a stable centripetal force under the action of a force that is not the same in one direction, so it is not right to say c.
-
Is your force that provides centripetal force a constant force? If so, the motion of the object is not a circular motion but a flat throw or a straight motion, hehe, less to focus on the tip of the horns, but it is still appropriate to think more, just know it, it is not necessary to spend too much time on this kind of problem.
-
What is constant force. The size direction does not change. The direction of the centripetal force is changing all the time. It always points to the center of the circle. With the circular motion of the object. Its direction is to become all the time.
-
When you say "a force provides a centripetal force", then this force always points to the center of the circle, and the direction is always changing! It's a variable force, not a constant force! You are wrong to think that the direction does not change for the "force pointing to the center of the circle". Usually pay attention to the learning of concepts.
Gravity is not equal to the gravitational pull of the Earth on an object. Due to the rotation of the earth itself, in addition to the poles, the objects in other places on the ground are moving in an approximate uniform circular motion around the earth's axis together with the earth, which requires a centripetal force directed perpendicularly to the earth's axis, and this centripetal force can only be provided by the earth's gravitational force on the object, and we can decompose the earth's gravitational force on the object into two components, one component f1, which points to the earth's axis, and the magnitude is equal to the centripetal force required for the object to move in an approximate uniform circular motion around the earth's axis; The other component g is the gravitational force on the object, where f1 = mw2r (w is the angular velocity of the earth's rotation and r is the radius of rotation of the object), and it can be seen that the magnitude of f1 is zero at the poles, increasing with the decrease of latitude, and the maximum f1max is in the equatorial region. Because the centripetal force of the object is very small, in general, it can be approximated that the gravitational force of the object is equal to the gravitational force, that is, the influence of the rotation of the earth can be omitted in general. >>>More
In two cases, the increase is obvious on the main road, and the increase on a certain branch road will also increase the resistance of this part, as in the example of 1 ohm and 100 ohms: the original resistance is 100 101 ohms, if it increases by 1 ohm, then it will be closer to the increase (he to a few ohms), this is the trend, if it increases by 100 ohms, then it also increases, this is less obvious than the former, the amplitude is not very high, you can use the mathematical formula to push down r=r1r2 (r1+r2), so that it is clearer.
The conversion between volume and weight units must introduce the density p. ** and the density of refined oil PT indicates that at a certain temperature, the volume of oil per cubic meter is P tons. The conversion relationship is: >>>More
As the temperature increases, the spacing between gases increases, i.e., the density decreases. But since the balloon is sealed, the gas cannot escape. Its mass does not change, but its density decreases, so the volume of the gas becomes larger. The pressure will be greater than the outside world. So the balloon will become bulging.
There are two hybrid modes of BYD, one is the sports mode, the engine is always on regardless of any working conditions, and can cope with intense driving at any time; The other is ECO mode, which turns the engine on or off depending on the load at the time (most of the time reflected in the speed). So in order for you to experience acceleration when you test drive, the sales should use the sport mode. Switch to EC