For 8 kilowatt equipment 220V, how big a voltage regulator you have to use

Updated on technology 2024-05-04
9 answers
  1. Anonymous users2024-02-09

    First of all, you must understand what kind of equipment you have, if there is no high-power motor in the general equipment, you can choose 12-15kva, if there is a high-power motor, it is best to choose 20kva!

  2. Anonymous users2024-02-08

    If the starting power is large, it is calculated by 3 times, and the voltage is low, and the ultra-low voltage regulator can be driven by a larger voltage.

    Choose a method. First of all, it depends on what type of electrical equipment it belongs to, and in general, the load is not purely resistive. Therefore, in the actual selection, the regulated power supply should be reasonably selected according to the specific conditions such as rated power, power factor and load type of electrical equipment, and the output power should leave an appropriate margin, especially when the impact load is selected, the margin should be larger, and the specific selection is as follows:

    For purely resistive loads such as incandescent lamps, resistance wires, electric furnaces and other equipment, the power of the voltage regulator should be twice the power of the load equipment.

    Inductive and capacitive loads such as fluorescent lamps, fans, electric motors, water pumps, air conditioners, computers, refrigerators, etc. The regulator power should be 3 times the power of the load device.

    In the environment of large inductance and capacitive load, the starting current of the load should be considered to be particularly large (up to 5 8 times of the rated current), so the power of the voltage regulator should be more than 3 times of the load power when selecting the voltage.

  3. Anonymous users2024-02-07

    Voltage range 160-250V with 15kVA is fine.

  4. Anonymous users2024-02-06

    Voltage regulators. How many watts of electrical appliances can you bring with 5000va on it? ”

    This mainly looks at the two parameters on the regulator, which is the power factor of the regulator.

    and its efficiency, <>

    Using 5000 is the actual output power of the regulator.

    3600(w)。

    It is also important to emphasize here that if your appliance is an inductive load.

    For example, air conditioners, refrigerators, washing machines, etc., the power output of the voltage regulator should be not less than 3 times of the inductive load, so that it can work safely and stably for a long time, because the starting current of these inductive loads is very large, generally the load rated current.

    of 3 7 times. For ordinary resistance loads, such as electric heating appliances, a 1:1 power output can be taken.

    Generally speaking, the voltage regulator of 5000VA can carry an inductive load of 3600 3=1200 (watts);

    3600 (watts) with resistive loads, such as electric water heaters, etc.

  5. Anonymous users2024-02-05

    The voltage regulator is marked with 5000VA, which means that the output power is 5000W, so it can be equipped with 5000W appliances.

  6. Anonymous users2024-02-04

    Summary. Hello dear, glad to answer for you 80kva regulator with 80 kW. An 80kVA regulator is equivalent to 80 kVA and 1000V.

    Since power = current voltage, the output power of this regulator is 80 kilowatts.

    Hello dear, glad to answer for you 80kva regulator with 80 kW. The 80kVA stabilizer is comparable to a current of 80 kVA and a voltage of 1000V. Since nuclear power = current voltage, the output power of this regulator is 80 kW.

    Extended Correlation : Input Voltage Range: Different models of voltage regulators have different input voltage ranges, so when selecting and using a voltage regulator with pure ridges, it is necessary to determine the applicable input voltage range according to actual needs.

    Output current: The output current of the voltage regulator also has a certain limit, which cannot exceed its rated current range, otherwise it is easy to cause burnout or output voltage fluctuations. Thermal Protection:

    Long-term high-load operation will cause the regulator to heat up, so some regulators have a thermal protection function, when the temperature exceeds their tolerance range, it will automatically stop working to protect the equipment. Wiring method: Yeyin voltage regulator has different wiring methods, including in-line type, SMD type, etc., and it is necessary to choose the appropriate wiring method according to your own needs and actual situation.

    Installation location: The voltage regulator should be placed in a well-ventilated location when in use to avoid long-term operation in a high-temperature environment.

    700 kilowatts is no problem.

    No, oh kiss.

    The 80 kVA regulator has a maximum output capacity of 80 kW, and the 700 kW Bivol is beyond the carrying capacity of the CPA regulator. Therefore, the regulator cannot support such a large load and is not recommended.

    How big the cable and the main switch to be.

    800kva

    To determine the size of the cable and the main switch, you need to know the specific situation of the load and how it is used. If you provide more detailed information, such as the voltage, current, and power of the load, as well as the number and type of electrical equipment required, I can better help you determine the appropriate cable size and total switching capacity

    The 400V voltage 60 meters long cable is about 700 kilowatts.

    800kVA regulator.

    According to the information you provide, a 400V voltage, a 60 meter long electric roller pin cable and an 800kVA voltage regulator need to be installed for a 700 kW load. In this case, it is recommended to use a copper core cable of at least 10 square millimeters, because the length of this cable is longer, the resistance of the repentant will increase, so a larger cable cross-sectional area is required to reduce the cable loss. At the same time, the 800kVA regulator needs a master switch to control the power input, and the minimum capacity should be 1600A.

    Isn't a 10 square copper core cable small?

    Not a small kiss, because the length of this cable is longer, the resistance will increase the cluster, so a larger cable cross-section seepage code is required to reduce the cable loss. At the same time, the 800kVA regulator requires a master switch to control the power input, with a minimum capacity of 1600A.

  7. Anonymous users2024-02-03

    Summary. A voltage regulator of 80kVA comes with a rated capacity of 80 kVA, while kilowatt is a unit of power, which is equal to voltage multiplied by current. Therefore, to determine the number of kilowatts of a voltage regulator, it is necessary to know the values of its input and output voltages.

    Assuming the input voltage is 220V and the output voltage is 220V, then the output power of the regulator is: p = V x i where V is the voltage and I is the current. Because the voltage regulator is used to stabilize the voltage, the input voltage and the output voltage are the same, thus:

    p = 220V x I And because the regulator has a rated capacity of 80 kVA, so: 80 kVA = 80,000VA Substituting the above equation gives us: 80,000VA = 220V x II = 80,000VA 220VI Therefore, an 80kVA regulator carries about a kilowatt of power.

    It should be noted that this is only a theoretical value, and factors such as the efficiency of the voltage regulator need to be considered when actually used.

    How many watts does an 800 kV regulator bring.

    A voltage regulator of 80kVA comes with a rated capacity of 80 kVA, while kilowatt is a unit of power, which is equal to voltage multiplied by current. Therefore, to determine the number of kilowatts of a voltage regulator, it is necessary to know the values of its input and output voltages. Assuming that the input voltage is 220V and the output voltage is 220V, then the output power of the voltage regulator is:

    p = v x i where v is the voltage and i is the current. Because the voltage regulator is used to stabilize the voltage, the input voltage and the output voltage are the same, so :p = 220V x i and because the rated capacity of the voltage regulator is 80kVA, so:

    80kVA = 80,000VA Substituting the upper or described formula yields: 80,000VA = 220V x II = 80,000VA 220VI Therefore, an 80kVA regulator carries about kilowatts of power. It should be noted that this is only a theoretical value, and factors such as the efficiency of the voltage regulator and the rate of the voltage regulator need to be considered when actually used.

  8. Anonymous users2024-02-02

    Summary. Hello dear, glad to answer for you, 80kva regulator with 8 kW. KVA (kilovolt amperes) and kilowatts (kW) are two units commonly used in electricity, and the conversion relationship between them is:

    1kVA = Therefore, an 80kVA regulator can drive 80 times equal to 64kW electrical load to operate. It should be noted that the rated capacity of the voltage regulator should be selected according to the load power to be driven, and should not exceed the multiple of the load power to ensure the stability and reliability of the voltage regulator.

    Hello dear, glad to do your answer for the macro, 80kva voltage regulator with 8 kW. KVA (kilovolt-ampere) and kilowatt (kW) are two units commonly used in electricity, and the conversion relationship between them is: 1kVA = Therefore, an 80kVA regulator can drive 80 times equal to 64kW electrical load to work.

    It should be noted that the rated capacity of the voltage regulator should be selected according to the load power to be driven, and should not exceed the times of the load power, so as to ensure the stability and reliability of the voltage regulator.

    How many kilowatts is 800 kV A belt.

    The power factor, if yes, is 640 kilowatts.

    700 kilowatts is no problem.

    Isn't that overloaded.

    According to the actual situation.

    How big the cable is.

    Determining what size of cable is needed is calculated on a case-by-case basis. The cross-sectional area of the cable will affect the characteristics of the cable, such as heat dissipation, resistance, voltage drop, etc., which will further affect the efficiency and safety of power transmission. In order to calculate the required cable specifications, you also need to know the following information:

    1.The voltage and current of the power supply. For example, if the power supply is a three-phase alternating current, its rated voltage is 380V, and the rated current is 1000A, then the total power is 700kW, and the current value should be 700kW (3 380V) cable length and laying method.

    The longer the cable length, the greater the cable loss, so it is necessary to choose a cable with a larger cross-sectional area. The way the cable is laid will also affect the heat release and loss of the cable, for example, in the case of direct burial laying and empty laying of the erection section, the required cable specifications will be different. 3.

    Ambient temperature. The load rating of the cable is also affected by the ambient temperature. It is common practice to take into account the degradation coefficient of the cable at different temperatures when checking the current.

    Generally speaking, such high-power cable laying requires professional calculation and scheme design to meet the requirements of safety, reliability and economy. Consultation and engineering communication with a professional electrical engineer are required.

  9. Anonymous users2024-02-01

    The 10kva regulator can withstand a power of 10 kilowatts. The 10kva regulator is marked with direct power slag back, that is, the maximum power that can be withheld, and there is a power factor in the electrical appliance, and the actual power of the voltage regulator marked with 10kva cannot reach the meeting. The output power of the 10kVA regulator is related to the input voltage, and if the regulator has an input voltage range, the voltage can only be stabilized within the range.

    The amount of power that a 10kVA regulator can handle depends on the type of load.

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