Is there a relationship between the loss of the grinding wheel and the speed of the motor?

If you are referring to the motor speed of the grinding wheel, then: The grinding wheel speed increases: It is like the grinding wheel hardening. It is not conducive to rough grinding and cutting, and is conducive to fine grinding and glossy surface. However, the grinding wheel life is extended.

Grinding wheel speed slows: Similar to the grinding wheel becoming softer. It is conducive to rough grinding and cutting, and is not conducive to fine grinding and glossy surface. However, the grinding wheel life is shortened.

The flat bed moves faster left and right and the outer round bed moves back and forth faster

It is similar to increasing the feed cutting of the workpiece to the grinding wheel. Reduced grinding overlay area. It is conducive to rough grinding and cutting, and is not conducive to fine grinding and glossy surface.

The flat bed slows down the left and right movement and the outer round bed moves back and forth

This reduces the amount of feed cutting from the workpiece to the grinding wheel. Increased grinding overlay area. It is not conducive to rough grinding and cutting, and is conducive to fine grinding and glossy surface.

The flat bed moves forward and backward and the outer round bed moves left and right faster

Reduced grinding impedance and grinding repetition area. It is conducive to rough grinding and cutting, and is not conducive to fine grinding and glossy surface.

The front and back movement of the flat bed is slowed down and the left and right movement of the outer round bed is slowed down

The grinding impedance and grinding repetition area have been increased. It is not conducive to rough grinding and cutting, and is conducive to fine grinding and glossy surface.

Outer circle. The speed of the workpiece without a heart is accelerated

It is similar to increasing the feed cutting of the workpiece to the grinding wheel. Reduced grinding overlay area. It is conducive to rough grinding and cutting, and is not conducive to fine grinding and glossy surface.

Outer circle. Unintentional workpiece speed slowdown:

This reduces the amount of feed cutting from the workpiece to the grinding wheel. Increased grinding overlay area. It is not conducive to rough grinding and cutting, and is conducive to fine grinding and glossy surface.

Note: When the grinding wheel or workpiece speed is used to achieve the rough grinding effect, the grinding wheel is also cut and the loss is relatively fast. On the contrary, fine grinding.

The grinding wheel life will be longer.

The grinding wheel is a high-speed running part, and it is safe to replace it if it is damaged and high, and it is also in line with the maintenance of the grinder.

If it's not round, you can change it. Or wear it to the half-point, depending on the occasion of use.

Constant loss means that the loss does not change with the change of load. Mechanical losses include ventilation losses, bearing friction losses, and brush friction losses. The main determining factor is the rotational speed n.

For synchronous motors, there is n=n1=60f p, and since f and p are not the same, the speed is not the same. For asynchronous machines, there is n=(1-s)n1=(1-s)60f p.When there is no load, S = 0, when the rated load ns, S does not change much, and it is also considered that the speed is unchanged.

For DC motors, there is n=e (ce) un (ce), so it is also believed that the speed is basically the same. To sum up, for all motors, n is constant, and the mechanical loss is also constant, i.e., the mechanical loss is constant.

Of course, it does, in general, the speed increases, and the efficiency also increases, but this is also a suitable range, and exceeding a certain range may be counterproductive.

The relationship between motor torque, efficiency and rotational speed.

Motor torque: The amount of force that rotates.

The power is fixed, and the speed is inversely proportional to the torque.

p=t/ω

p is the electromagnetic rotation distance.

2 *nn is the rotational speed.

Hehe, it's a bit complicated to explain, it is recommended that you go to read motor-related books, or look up the principle of the motor on the Internet, so that you can understand.

Number of poles p = 2 * number of poles q

If p=1 can be seen as.

The stator is a bar magnet p=1

But the magnet has a south pole and a north pole, and q is the magnetic pole, so q=2

'n=60f p' is the rotational magnetic field speed generated by the stator winding, and the rotation speed minus the slip rate is the rotor speed 'n1=n-(n*s)', which is called the asynchronous speed.

The speed of the three-phase asynchronous motor has a relationship with the slip rate, but it has little relationship.

For three-phase asynchronous motors, p=q 2

p is the number of pole pairs, q is the number of poles of the motor, for example, the number of pole pairs of the common 4-pole motor is 2

The synchronous speed of the motor is equal to the frequency multiplied by 60 minutes divided by the number of poles in half.

q (number of poles of the motor) = 2p (number of pole pairs).

It is the relationship between the number and the logarithm.

Like 2 socks = 1 pair of socks.

It does not slow down the rotational speed, but it may affect efficiency.

This increases the power consumption per unit of time.

If the motor is overloaded and heated, the insulation layer of the coil will age prematurely.

So that it is not good to use.

It is best to clear the obstacles, and how long it will take depends on whether your motor is good or not, how big the motor is, how much resistance, and how much work it is.

It should be said that there is no impact, but the mechanical parts deteriorate, which will increase the efficiency and loss of the motor, and the impact on the speed is very small and can be ignored.

Somewhat, after a long time, the insulation will age, so the resistance is not good.

It has nothing to do with the speed, it will only cause insulation aging after a long time.

The no-load loss is mainly iron loss.

The magnitude of the iron loss can be considered to be independent of the size of the load, i.e., the loss at no load is equal to the iron loss at the load, but this refers to the situation at the rated voltage. If the voltage deviates from the rated index, because the magnetic induction intensity in the transformer core is in the saturation section of the magnetization curve, the no-load loss and no-load current will change sharply, so the no-load test should be carried out at the rated voltage.

For electrical installation engineering, the circuit is in a standby state, and the standby state can be divided into two states: hot standby and cold standby. No matter which part of the circuit is described, there is voltage on the supply side, but no current flows as hot standby; If there is neither voltage nor current flowing on the power supply side, it is cold standby. The most obvious feature is that there may be voltage in the circuit, but there is absolutely no current flowing, and there is no conversion between electrical energy and other energy.

The loss of the motor consists of copper loss of the coil, iron loss of the core, and mechanical loss (bearing and fan). The economic operation of the motor refers to the operating condition that the ratio of the output shaft power to the input electrical power is the maximum value (the highest efficiency). If the highest efficiency of the transformer is when the copper loss is equal to the iron loss, and the motor has the factor of mechanical loss, it is not when the copper loss is equal to the iron loss.

Because the motor coil needs to be excited, of course, there is reactive power loss.

The main loss of power consumption when the motor is at no load is the excitation current loss.

The power consumption of the motor when it is stalled is mainly the loss of copper wire.

The no-load loss of the motor is mainly the core loss, which is composed of hysteresis loss and eddy current loss. The hysteresis loss is proportional to the permeable material and to the second quadratic of the magnetic flux density. The eddy current loss is proportional to the quadratic of the magnetic flux density, the quadratic of the thickness of the magnetic permeable material, the quadratic of the frequency and the thickness of the permeable material.

The power consumption of the motor when it is stalled mainly includes winding resistance loss, electromagnetic loss of the core, dielectric loss, eddy current loss, etc.