Is 2Cu 02 heating 2CuO a reduction reaction? 5

The concept of junior high school is very narrow, in fact, as long as there is a change in valence, the reaction is a redox reaction.

Specifically, Cu increases the valency, loses 2mol of electrons, and generates 1molCuo, where Cu acts as a reducing agent and O2 acts as an oxidizing agent, and Cuo is both an oxidation product and a reduction product. Cu is oxidized.

If you are not clear, put your address.

I'll give you something more specific.

The definition of redox reaction in junior high school is narrow.

As you will learn later, the occurrence of oxidation reaction refers to an increase in valency, and the opposite is true for reduction reactions.

If there is an increase in valency, there will naturally be a decrease in valency. It's like if there is oxygen, there must be hypoxia.

The oxidation reaction and the reduction reaction occur at the same time, and if one reaction is an oxidation reaction, then it is also a reduction reaction.

You see, the price of that cu is 0 price, and when you get to cuo, it is +2 price, and there is a mantra you remember.

Loss-of-liter redox agent.

Reduction oxidant.

Loss of redox agent, you look at the word "loss" of the cu, you don't care about it Look at the second word "liter", the valence state has increased (cu in cuo is +2), he is the reducing agent, oxidation reaction occurs.

This is from high school.

It's a redox reaction, you see, the valency of Cu goes up from 0 to +2, and the valency of oxygen goes down from 0 to -2

So Cu is the reducing agent and oxygen is the oxidizing agent.

So it's a redox reaction.

The redox reaction is characterized by an increase in valency and a decrease in valency.

Cu is oxidized and O2 is reduced.

The essence of the so-called redox reaction refers to: the gain and loss of electrons of the element, the reduction of the gained electrons, and the oxidation of the lost electrons.

In this reaction: Cu loses two electrons from the atomic state to Cu2+, and O2 changes from the molecular state to the O2- ionic state. So Cu is oxidized and O2 is reduced.

Oxidation reaction! "Reduction" refers to the loss of oxygen by the object! There is no loss of oxygen in this!

It is indeed a redox reaction.

Note: It is CU that rises from 0 to +1 valence, O from 0 to -1 valence, Cu reducing agent, and O2 is the oxidizing agent. When Cuo is formed, it has to go through many steps of the intermediate halogenation reaction, and finally CuO

Of course, it is an oxidation reaction, where oxygen is reduced.

Redox reactions.

The reducing agent CU is oxidized, and the oxidant O2 is reduced!

Redox reactions only consider who has an increased or decreased valency.

Redox reactions.

Cu is the reducing agent and O2 is the oxidizing agent.

In the redox anti-cherry blossom response, the oxidant loses oxygen and is reduced, and the reduction reaction occurs. It is an oxidant It is also guessed that the oxygen obtained from the jujube agent was oxidized, and an oxidation reaction occurred, so it can be analyzed accordingly;

Analysis] From the chemical equation, it can be seen that carbon obtains oxygen in the reaction of C+2CuO<>2Cu+CO2, and an oxidation reaction occurs, which is the pure agent of this reaction, so C is chosen

2cu+o2=2cuo

It can be seen that participating in the anti-nuclear fight should change the oxygen mass gram of the auspicious and generate copper oxide.

Mass bridge staring 16 grams.

I don't write a book of ode to the macro state.

2cu-cu2o=cu2o-2cuo, that is, 2cu+2cuo=2cu2o, k=k1 k2

Because of the excitement, this cu+cuo=cu2o, k=root number (k1 k2).

Answer] D Answer Analysis] Test Question Analysis: Cu2S+2Cu2O=6Cu+SO2 In the anti-search banquet, the valency of the Cu element decreases from leakage or +1 valence to 0, and the valency of the S element increases from -2 valence to +4 valence, a From the reaction, it can be seen that 6molCu is generated to transfer 6mol electrons, and Yanyin is generated to 1molCu and 1mol electrons are transferred, so it is wrong; If the valency of the B Cu element decreases, then Cu is a reduction product, so it is wrong; c If the valency of Cu element decreases in the reaction, Cu2O and Cu2S are oxidants, so it is wrong; The valency of the D Cu element decreases and the valency of the S element increases, so Cu2S is both an oxidant and a reducing agent, so it is correct. The answer is D

Test site: Redox reaction.

2Cu +S (ignition) Cu2S Oxidant S Reducing agent CuH2+Cl2 2HCl Oxidant Cl2 Reducing agent H22CO+O2 2CO2 Oxidant O2 Reducing agent CoCl2+2Nai NaCl+I2 Oxidant Cl2 Reducing agent Naimno2+4HCl (concentrated) MnCl2+Cl2 +H2O Oxidant Mno2 reducing agent HCl

2NaOH + Cl2 NaCl + NaCl + H20 Oxidant Cl2 Reducing Agent Cl2

cu;Reducer.

s；Oxidant.

h2；Reducer.

cl2；Oxidant.

co；Reducer.

o2；Oxidant.

cl2；Oxidant.

nai；Reducer.

mno2；Reducer.

hcl；Oxidant.

naohcl2；It is both an oxidizing agent and a reducing agent.

From the chemical equation, it can be seen that carbon is high at C+2Cuo.

Oxygen is obtained in the CO2 +2Cu reaction, and an oxidation reaction occurs, which is the reducing agent of this reaction

So choose A

From the chemical equation, it can be seen that carbon is high at C+2Cuo.

Oxygen is obtained in the reaction of 2Cu+CO2, and an oxidation reaction occurs, which is the reducing agent of this reaction, so C is selected