Problems with the CF China Railway Bridge

The shovel is with a feint, the axe is not brought, the shovel is 180 degrees can kill people, the axe range is small, the left click of the shovel is 30 blood, the axe is 70, the shovel is slow and the axe is fast, the axe is 1 headshot, and the shovel cannot.

Trouble, thanks!

Three ways! ~

1: The simplest is to stick directly to the box, hold down W and S without letting go, and then press the jump and squat keys at the same time. The speed is slow, of course, you will be faster when you are proficient in jumping.

2: It is also in front of the box or only a little distance, the first is a jump, note that it is an ordinary small jump, at the moment when it is about to land at the same time press the jump and squat button, this speed is fast, it is 1 success.

3: When moving, the first is a small jump or a big jump, jump to a place very close to the box, how close can it be, press the jump and squat key at the same time at the moment when it is about to land, pay attention not to hit the box, because there will be a delay if you hit it, it is not a jump.

The three ways are like the connection method when jumping, if you can jump you know how to jump when you jump, with the connection method of jumping, it is to change the key, and the way to move and jump must also master the distance!

Jumping is to grasp the timing, you have nothing to do with jumping there, looking for a feeling, that is, when the previous jump did not land, quickly press another jump, just grasp the feeling.

Wish! Give me a vote if it's good.

W+S hold down and squat, one second after the squat, and then the second one, about two or three times to go up.

The landlord said that the bandits came out to b into the box in front of the suspension bridge.,You can jump on it with a super jump.,I used it when I played yesterday.,But it's not a very good yin person.,If you can't super jump.,Then learn which even jump.,It's to jump twice in a row and press the squat at the same time as the second jump.,There is ** tutorial on the Internet.,The landlord can learn it.,Or search from above.,Or look at this directly.。

There's someone in there who has some explanations for both jumps, and I hope it can help you

You can jump to another box and then jump over it.

Press and hold the WS key (that is, the forward and backward buttons) together, change the knife, click the heavy knife first (you can also click it), press the space bar (jump), and it will get stuck on the top of the box for a while, and then release it, don't let go, and it will go up!! You can press twice at second intervals without squatting!

Do you think someone can give it to you for nothing? Please, it's all RMB.

I have M4-X, M4-S, cursed grenades, grenades, grenades, body armor, black mirrored pistols, camouflage pistols, Nepalese, these things, I got them for free, my brother doesn't mind.

CF doesn't stipulate that minors can't buy shovels, can't you buy them yourself?

The speed of the train is 10 meters per second, so the second iron bridge is 5x10=50 meters longer than the first iron bridge, and if the length of the first iron bridge is x meters, then the second iron bridge is 2x-50, so 2x-50-x=50

Solution: x = 100 meters.

Therefore, the first iron bridge is 100 meters and the second iron bridge is 150 meters.

Solution: If the length of the first iron bridge is x meters, then the length of the second iron bridge is (2x-50) meters, and the time required to cross the first iron bridge is minutes

The time required to cross the second iron bridge is min

Depending on the topic, the equations can be listed.

Solve the equation x+50=2x-50

Get x=100

2x-50=2×100-50=150

Hello, I am Mr. Fang Tengfei! I have seen your question, and it will take 3 minutes to sort out the answer now, please wait a moment If my answer is helpful to you, please give it a thumbs up, thank you

Hello, the length of the first iron bridge is 100 meters, and the length of the second iron bridge is 150 meters.

The train speed is 600 meters per minute; 1 minute = 60 seconds, 600 60 = 10, the speed of the train is converted to 10 meters and seconds.

The train crossed the second iron bridge, which took 5 seconds longer than the first iron bridge.

If the train runs at a speed of 5 seconds, it is 10 x 5 = 50 meters.

The second iron bridge is 50 meters longer than the first.

The length of the second bridge, which is 50 meters shorter than twice the length of the first bridge, is combined with the results of the analysis just now.

The length of the second iron bridge is the length of the first iron bridge plus 50 meters, which is also twice the length of the first iron bridge minus 50 meters, and the length of the first iron bridge plus 50 meters is equal to twice the length of oneself minus 50 meters.

At this point, let's take the length of the first bridge x and the length of the second bridge x + 50, and the equation is obtained.

2x - 50 = x + 50

2x - x = 50 + 50

x = 100

x + 50 = 150

The length of the first iron bridge is 100 meters, and the length of the second iron bridge is 150 meters.

Set up the first iron bridge x meters, and the second iron bridge (2x-50) meters.

2x-50）-x=50

2x-50-x=50

x=50+50

x=1002x-50=150

The first iron bridge is 100 meters, and the second iron bridge is 150 meters.

The speed of the train is 10 meters per second, so the second iron bridge is 5x10=50 meters longer than the first iron bridge, and if the length of the first iron bridge is x meters, then the second iron bridge is 2x-50, so 2x-50-x=50

Solution: x = 100 meters.

Therefore, the first iron bridge is 100 meters and the second iron bridge is 150 meters.

Set the first bridge X, the second bridge Y

2x-50=y

y-x=50 (if the train is 600m per minute, then it is 10m per second, and 5 seconds more is 50m more).

How can you connect one yuan at a time without a system of equations? It's to use y as x.

Then it's 2x-50=50+x. Huh

The second bridge is longer than the first: 5 60 * 600 = 50 meters.

The length of the first bridge: (50+50) (2-1)=100 meters.

The length of the second bridge: 100 + 50 = 150 meters.

Solution: Let the time of passing through the first iron bridge be x, then the time of passing through the second iron bridge is (x+5)600m min=10m s

The second iron bridge is 50 meters shorter than twice the length of the first iron bridge.

The length of the first iron bridge is 10x, and the length of the second iron bridge is.

10x*2-50=10(x+5)

The solution is x=10s

The length of the first iron bridge is: 10m s*10s=100m, and the length of the second iron bridge is: 100m*2-50m=150m

x/10-(2x-50)/10=5

x=1002x-50=150

The first is 100 meters long and the second is 150 meters long.

Solution: Let the length of the first bridge be x meters.

According to the title, the length of the second bridge is 2x-50 meters (500 decimeters = 50 meters), and according to the second bridge, which is 10 meters longer than the first bridge, 5 seconds, the list relationship is:

2x-50）-x=10×5

Solve the equation to find x = 100 meters.

then 2x-50 = 150 meters.

The length of the first bridge is 100 meters, and the length of the second bridge is 150 meters.

The speed of the train is 10 meters per second, so the second iron bridge is 5x10=50 meters longer than the first iron bridge, and if the length of the first iron bridge is x meters, then the second iron bridge is 2x-50, so 2x-50-x=50

Solution: x = 100 meters.

Therefore, the first iron bridge is 100 meters and the second iron bridge is 150 meters.

There is a train that has to cross the first and second iron bridges at a speed of 600 meters per minute, and it takes 5 seconds longer to cross the second iron bridge than the first iron bridge, and the length of the second iron bridge is 50 meters shorter than twice the length of the first iron bridge.

1.The train travels 600 meters per minute x 5 minutes longer than the first bridge = the second bridge is 3,000 meters longer than the first bridge.

2.The second iron bridge is 3000 meters longer than the first iron bridge, and is 50 meters shorter than the length of the first iron bridge twice the length of the second iron bridge, then the length of the second iron bridge is: 3000x2-50 = 5950 meters 3It takes 5 minutes to cross the second iron bridge than the first iron bridge, and the length of the first iron bridge is: 5950-3000 = 2950 meters.

Set the first iron bridge x meters, the second iron bridge y meters.

y-x)/600=5

y=2x－50

then x=3050, y=6050

The first bridge is 1225 meters.

The second bridge is 4225 meters.

Hehe, that should be right.

The first is 3,050 meters long and the second is 6,050 meters long.

Ahem, what grade are you?