To solve the fractional equation, as follows, solve the following fractional equation

Solution: 1 x-1) = (1 x -1) Both sides of the equation are multiplied by the simplest common denominator (x -1).

x+1=1x=0

Test: Substituting x=0 into the simplest common denominator x -1=0 -1=-1≠0

x=0 is the root of the original equation.

1 x-2)+3=(x-1 x-2) multiplies both sides of the equation by the simplest common denominator (x-2).

1+3(x-2)=x-1

1+3x-6=x-1

3x-x=6-1-1

2x=4x=2

Test: Substitute x=2 into the simplest common denominator x-2=2-2=0

x=2 is the root of the original equation, which has no real solution.

2-x 3+x)=(1 2)+(1 x+3) The simplest common denominator is multiplied by the simplest common denominator 2(x+3) on both sides of the equation

2(2-x)=x+3+2

4-2x=x+5

2x-x=5-4

3x=1x=-1/3

Test: Substitute x=-1 3 into the simplest common denominator 2(x+3)=2 (-1 3+3)=16 3≠0

x=-1 3 is the root of the original equation.

Solution: (1 4)x--[1 2)x--(3 4)y 2]+[7 4)x+(1 4)y 2].

1/4)x--(1/2)x+(3/4)y^2--(7/4)x+(1/4)y^2

2x+y^2

Because x=2 points? ，y=?, so I can't solve it.

Answer; Changing this shape yields: (11 2x+2) (11 2x)+(15 2x 2) (15 2x)=(17 2x 2) (17 2x)+(9 2x 2) (9 2x) 1 (11 2x) 1 (15 2x)=1 (17 2x) 1 (9 2x) (26 4x) [11 2x)(15 2x)]=26 2x) [17 2x)(9 2x)] x1=13 2 (11 2x)(15 2x)=(17 2x)(9 2x) solution: no solution x=13 Mori Zhiyou2

The equation is left and not right while the dust is minus 2

2/(11-2x)+2/(15-2x)=2/(17-2x)+2/(9-2x)

Simplification and merge (26-4x) refers to ((11-2x)(15-2x))=26-4x) (17-2x)(9-2x)).

Denominator (11-2x) (15-2x) - (17-2x) (9-2x) = 0 no solution.

Molecule 26-4x=0 x=13 2

(11 2x+2) (11 2x)+(15 2x 2) (15 2x)=(17 2x 2) (17 2x)+(9 2x 2) Defeat the Sinchakra (9 2x) number of handicap 1 (11 2x) 1 (15 2x)=1 (17 2x) 1 (9 2x) (26 4x) [11 2x)(15 2x)]=26 2x) [17 2x)(9 2x)] x1=13 2 (11 2x)(15 2x)=(17 2x)(9 2x)Solution: No solution x=13 2

First pass. Resolves the two sides into the same.

They are all multiplied by x at the same time, and they are regarded as a solution to a quadratic equation.

x-1/x-1=1

x-1 =x-1

x has an arbitrary real solution.

I didn't understand your question below.

Use brackets to make the question really incomprehensible.

x(x-1)=(x+1)(x-3)

x²-x=x²-2x-3

x=-3If the problem is solved, please remember to give a good review or a point

Solution: x (y+z)=y (x+z+1)=z (x+y-1)=x+y+z

x+y+z) (2x+2y+2z-1+1)=x+y+z (the nature of proportion).

x+y+z)/[2(x+y+z)]=x+y+z1/2=x+y+z

So x (y+z)=y (x+z+1)=z (x+y-1)=1 22x=y+x

2y=x+z+1

2z=x+y-1

It is sufficient to solve the ternary equation.

Both sides are multiplied by 2x (x+1) at the same time

So 2(2x+1)=5x

The x=2 test: when x=2 and 2x(x+1)=12≠0, the solution of the equation is x=2

Solution: Multiply the simplest common denominator 2x (x+1) on both sides of the fraction

Get: 4x+2=5x

Solution: x=2

Test: Substituting x=2 into 2x(x+1), the value is not zero, then x=2 is the root of the original equation.

The denominator is not 0, so x + x ≠ 0, 2x + 2≠0, x ≠ 0 and x≠-1(2x+1)(2x+2)=5(x +x).

4x²+6x+2=5x²+5x

x²-x-2=0

x+1）（x-2）=0

x=2 or x=-1 (rounded) x=2

The denominator of the bipartite equation is converted into an integral equation, and the value obtained by the solution of the integral equation is obtained, and the solution of the fractional equation can be obtained after testing.

Solution: denominator is obtained, and the merger of terms is judged: , and the solution is obtained: , and the solution is the solution of the fractional equation after testing; Remove the denominator to obtain:,Sort out:,Shift merge to obtain:,Solution:,After testing, it is to increase the root, and there is no solution to the fractional equation.

This question examines the understanding of fractional equations, and the basic idea of solving fractional equations is:"Transform your mind"to convert the fractional equation into an integral equation to solve. Solving the fractional equation must be based on the intention of the friend.