2 way fractional equations, 2 way fractional equations

1. (x+3) (x+7)+(x+7) (x-3)=2 solution: multiply both sides of the equation (x+7) (x-3) to obtain:

x+3)(x-3)+(x+7)(x+7)=2(x+7)(x-3) The solution yields x=-41 3

Test: (x-3)(x+7) is not equal to 0 when x=-41 3, so x=-41 3 is the solution of the original fractional equation.

2. (6x-2) (2x-1)-(6x-3) (3x-1)=1 solution: multiply both sides of the equation by (2x-1) (3x-1), and obtain:

2(3x-1)(3x-1)-3(2x-1)(2x-1)=(2x-1)(3x-1)

Solution: x=2 5

Test: (2x-1)(3x-1) is not equal to 0 when x=2 5, so x=2 5 is the solution of the original fraction equation.

In (x+8 x)2+x=42-8 x, move the x on the left side of the equation, (x+8 x)2=42-x-8 x, and then put a - sign on the right, that is, (x+8 x) squared = 42-(x+8 x) and then treat x+8 x as a whole, let x+8 x=a, solve the unary quadratic equation about a, and solve a=6 or a=-7 (rounded), that is, x+8 x=6 solves x=2 or x=4

The second one uses the same solution, the holistic method.

1: Calculate the distance between ab and the two places as an integer hail 1. Set: Meet after x hours.

Solution: x 8+x 6=1 Multiply both sides by 24 to get: 3x+4x=24 7x=24

x=24 7 x source clearance hour Answer: Met after hours.

2: Suppose the hydrostatic velocity is x km/h. Solution: x=(10+14) 2 x=24 calendar 2

x = 12 km A: The speed of the boat in still water is 12 km/h.

Solution: A completes 1 A of the project every day

B completes 1 b of the works every day

B worked for three days and did 3 B

Then A and B did 1 day of work together (1 a+1 b) because the total amount of work was 1

So 3 b + (1 a + 1 b) = 1

You can get the answer you need.

By the inscription 1 a+4 b=1

1/a=1-4/b=(b-4)/b

a=b/(b-4)=(b-4+4)/(b-4)a=(b-4)/(b-4)+4/(b-4)a=1+4/(b-4)

First of all, a is an integer.

So 4 (b-4) is an integer.

So b-4 is a divisor of 4.

b-4=1,-1,2,-2,4,-4

a=1+4/(b-4)>=1

So 4 (b-4)>=0

So B-4>0

So b-4 = 1, 2, 4

b=5,6,8

a=5,3,2

So a+b=5+5

a+b=3+6

a+b=2+8

So a+b = 9 or 10

From the known 1 a+4 b=1, and because a and b are both natural numbers, a=b=5, that is, a+b=10

lz All I know is...

4/b + 1/1 = 1

I can't solve this equation... You can only find the relation between a and b. There is no specific solution.

(x-8)(x-8)(x-8)-(x-8)(x-8)(x-8)=(x-8)(x-8)(x-8)-(x-8)(x-8)(x-8)(x-8) and then merge similar terms to obtain (x-8-x+8)(x-8)(x-8)=(x-8)(x-8)(x-8-x+8) -x-8)(x-8)=-(x-8)(x-8) x 8-88x+81=x