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Solution: a*b+(b-a)*b=ab+a-b+(b-a)b+b-a-b
ab+a-b+b^2-ab-a
B 2-B I'm a math know-it-all, I can't figure out math problems, hurry up and get on math know-it-all!
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Because a times b ab + a-b, a times b(b-a) times b {ab(b-a)+a-b(b-a)}*b+ab(b-a)+a-b(b-a)+b(b-a)+b answer supplement.
Solution: The original formula ab a b (b b ab a ab a b) ab a b should be subtracted b from the last b squared, but I won't square b so that's it.
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Simple Yes: ab+a-b+(b-a)b+(b-a)-b=ab+a-b+(b-squared)-ab+b-a-b=b-squared-2b
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Let's figure it out for ourselves.
Let x be the first milestone tens, and y be the first milestone units.
10y+x)-(10x+y)=(100x+y)-(10y+x)9y-9x=99x-9y
18y=108x
y=6xx, where y is the number between 1 and 9.
Only x=1, y=6
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Answer: These three numbers are:
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The answer has been sent Attention checks.
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Solution: a=a -2a b+ab ,b=3a b+2ab -a ,a 2b c
c=a-2b
a³-2a²b+ab²-2(3a²b+2ab²-a²)=a³-2a²b+ab²-6a²b-4ab²+2a²=a³-8a²b-3ab²+2a²
9x -(4x +x-3) 5x 6x 1 5x=9x -4x -x+3 5x +6x-1-5x=(9x -4x 5x)+6x-x-5x)+(3-1)=2Since there is no x term after the original simplification, the answer has nothing to do with how much x is equal to, so his result is still correct.
Original = 3x y - (2xy -2xy + 3x y + xy )+3xy = 3x y-2xy +2xy-3x y-xy +3xy = (3x y-3x y) + (3xy -2xy -xy )+2xy = 2xy
Substituting x=3, y=-1 3 into it.
Original = 2 3 (-1 3) = -2
May it help you!
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Because the result of the calculation has nothing to do with x.
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Question! Let's put 。。 Don't abuse me ... Let's start with the simple ones.
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If I'm not mistaken, the correct answer is -5
Then the wrong answer is 12 between 7 and -5
That is to say, the 6x 5 symbol was read wrong.
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-10+9-8+7-6+5-4+3-2+1=-5-10+9-8+7+6+5-4+3-2+1=76x 5 is wrong.
If I'm not mistaken, the correct answer is -5
Then the wrong answer is 12 between 7 and -5
That is to say, the 6x 5 symbol was read wrong.
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The boy in the middle is 85, 5=17, and 13, 15, 17, 19, 21
The girl in the middle is 80, 5=16, and 12, 14, 16, 18, 20
The principle is that more supplies are less, and 5 people are exactly averaged, so divide by 5 to get the middle number.
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I only thought of this method, so I'll talk to you.
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