Elementary 1 math problem, about integer process .

1. 1-3a²+a- 2（5a²+3a-2）1-3a²+a-10a²-6a+4

1+4)-(3a²+10a²)+a-6a)5-13a²-5a

2.Solution: If x = -2, the original formula = 7 and 4 9-2m if x = 2 original formula = -59 9 + 2m

59/9+2m=67/9-2m

Solution: 2m+2m=67 9+59 9

4m=126/9

m=7/23.Solution:

m+（2m-4）+1/2（2m-4）+3

m+2m-4+m-2+3

m+2m+m）-4-2+3

4m-3

1.（1-3a²+a）-2*（5a²+3a-2）=5-13a²-5a2.According to the meaning, x=-2, y=2 3 and x=2, y=2 3 are substituted into polynomials, respectively, and they are equal:

2m+7+12/27=2m-7+12/27 m=7/23.Xiao Ming Age: m Xiao Hong Age: 2m-4 Xiao Hua Age: 1 2 (2m-4) + 3

The sum of the ages of the three people: m+2m-4+1 2(2m-4)+3=4m-3

1、（1-3a²+a）-2（5a²+3a-2）=1-3a²+a-10a²-6a+4=-13a²-5a+5

2、mx-2（x-1/3y²）+3/2x+1/3y²）=（m-7/2）x+y²

Because x=-2 is considered x=2, the result is correct, and the calculation process is correct.

So m-7 2 = 0 i.e. m = 7 2

3. Xiao Ming: m Xiaohong: 2m-4 Xiaohua: (2m-4) 2+3m+2m-4+(2m-4) 2+3=4m-3

Column: 1 1-3a²+a- 2（5a²+3a-2）1-3a²+a-10a²-6a+4

1+4)-(3a²+10a²)+a-6a)5-13a²-5a

2.When x=-2, the era enters: -2m-2(-2-4 27)+(3+4 27).

2m-4+8/27+3+4/27

2m-1+4/9

2m-5/9

When x=2: 2m-2(2-4 27)+(3+4 27)2m-4+8 27-3+4 27

2m-7+4/9

2m-59/9

So -2m-5 9=2m-59 9

Get m=16 9

3. m+(2m-4)+1/2(2m-4)+34m-3

bai 1.Polynomial ( about x,y (

dua-2)x +(5+5b)xy-x+2y+7 does not contain the second term dao, find the value of a-2b.

The polynomial (a-2) x + (5+5b) xy-x+2y+7 with respect to x,y does not contain quadratic terms, and yields a-2=0, and 5+5b=0, thus a=2, b=-1

The value of A-2B is:

2-2x(-1)

It is known that the polynomial x y to the power of 2m+1 -3x y + xy -1 is a fifth degree polynomial about x,y, and the magnitude of n+1 of the monomial about x,y 2 3xy is the same as the degree of this polynomial, find the value of m,n.

From the 2m+1 power of the known polynomial x y -3x y + xy -1 is the fifth degree polynomial with respect to x,y, we get 2+(2m+1)=5

m = 1, from the monomial 2 3xy about x,y by the same degree of n+1 as this polynomial, we get 1+(n+1)=5

n=3.

1.Multiple items about x, y.

The source formula (a-2) x + (5 + 5b) xy-x+2y+7 does not contain two bai du terms, and the value of a-2b is obtained.

The nominomial zhi formula does not contain a quadratic term, so the coefficient of the quadratic term is dao0

a-2=05+5b=0

a=2,b=-1

a-2b=2-2×(-1)=4

2.It is known that the polynomial x y to the power of 2m+1 -3x y + xy -1 is a fifth degree polynomial about x,y, and the magnitude of n+1 of the monomial about x,y 2 3xy is the same as the degree of this polynomial, find the value of m,n.

The first polynomial is a fifth-order polynomial, while none of the following terms are fifth, so only the first term is a 5

2+2m+1=5,m=1

And the second mononomial should also be a five-degree monomial, so the sum of all letter exponents in this formula is equal to 51 + n + 1 = 5, n = 3

1. (a-2)x and (5+5b)xy are quadratic terms, and the title says that there is no quadratic term, that is, let a-2=0, 5+5b=0, that is, a=2, b=-1. i.e., a-2b = 4

2. 2m+1 power of x y.

-3x y+xy -1 is a fifth-order genus polynomial with respect to x,y, i.e., 2+(2m+1)=5, that m=1, and by the monomial 2 about x,y, the degree n+1 of 3xy is the same as the degree of this polynomial, then 1+(n+1)=5, i.e., n=3

1. Excluding quadratic terms, a-2=0, 5+5b=0So a=2, b=-1, so a-2b=4

The second question is a bit problematic, right? 1 4 is a coefficient?

1 Solution There are many things that can be known from the meaning of the question.

The copy formula does not contain cubic terms, so (a-2) and (5+5b are used as system bai numbers, du, because the polynomial does not contain 2 terms, so (a-2) and (zhi5+5b) are both = 0, so a-2=0 5+5b=0 so a=2 b=-1 so bring in.

daoa-2b=2-2*（-1）=0

It should be (a+c)-(b-d).

a+c）-（b-d）

a+c-b+d

a-b)+(c+d)

Choosing D opens the brackets, and then after some processing (merging similar terms, general points, factorization, etc.), it should be possible to simplify the factors related to the known conditions, and then it can be calculated.

Did you make a mistake? Probably (a+c)-(b-d).

Remove the brackets and put them back together.

a-b）+(c+d)=-1

If the question is correct, then there is an error in the option.

（a+c）-(a-d)

a+c-a+d

c+d, so there is no right one in the options.

The answer is 2(a+c)-(a-d) can be reduced to, that is, without parentheses: a+c-a+d

A and -a are inverse numbers to each other, so 0 is left, then c+d. remainsAccording to the title, c+d is equal to 2, so (a+c)-(a-d) is equal to 2

This is something like a 2+--2ab+b 2 that can be squared (a-b) and replaced by a number that is squared (2010-2009).

2010x（2009+1）-2x2010x2009+2009x2009

2010x2009+2010-2x2010x2009+2009x2009

2010-2010x2009+2009x2009=2010-(2009+1)x2009+2009x2009 is to piece together and then eliminate, the specific steps are like this, you can simplify it. If you don't understand, you can continue to ask me.

(a-b) squared is equal to a square minus 2ab + b square.

This becomes (2010-2009) squared

There's an easy way to do this.

For example: a -2ab+b = (a-b) Putting the number in it equals 1

Khan was the first to see it, but then it was because the square keyboard didn't know how to square it, and when he typed it, he found that there were already so many people who sent it...

2010 square + 2010 square - 2010 + 2009 square + 2009 square + 2009 equal to.

a²-2ab＋b²=(a-b)²

Here's the formula. The specific is calculated according to the formula:

Solution: Because x+2y-1=0, x+2y=1

3 to the 2x power of 81 to the power of y-8=9 xx9 (2y)-8=9 (x+2y)-8=9-8=1

Explanation: 3 to the 2x power becomes 9 to the x power, 81 becomes 9 2, use the inverse operation of the power of the square and the multiplication operation of the same base meter, and then substitute it as a whole.

Compare sizes. 7 to the 60th power and 48 to the 30th power: This problem can be converted in this way to the 60th power of 7 can be equal to the 30th power of 7 times the 30th power of 7, then it can become 49 to the 30th power, so the 60th power of 7 is greater than the 30th power of 48.

3 to the 2x power 81 to the y power -8

9 to the x power 9 to the 2y power of 8

9 to the power of (x+2y) -8

9-8 (x+2y-1=0 to x+2y=1) = 60 power of 17 = 30 power of 49.

It is larger than the 48 to the 30th power.

81 can be written as 3 to the 4th power x+2y=1

The above equation is equal to the power of (2x+4y) of 3 -8=1

7 to the 60th power = 49 to the 30th power and 48 to the 30th power.

1.Re-evaluation: -2(mn-3m2)-[m2-5(mn-m2)+2mn], where m=1 and n=-2

2.Simplify the following equation first, and then evaluate: 5(3a2b-ab2)-4(-ab2+3a2b), where a=-2 and b=3

3.Simplify, then evaluate: (4a2-3a)-(1-4a+4a2), where a=-2

4.Simplify, then evaluate: (3x2y-xy2)-3(x2y-2xy2), where x=

1/2，y=-1/3

5.Simplification evaluation: 3x2y-[2x2y-3(2xy-x2y)-xy], where x=-1 and y=-2

6.Simplification and then evaluation: -(x2+y2)+[3xy-(x2-y2)], where x=-1, y=2

7.Simplify, then evaluate: 5x2-[3x-2(2x-3)+7x2], where x=-2

8.(2a2b+2ab2)-[2(a2b-1)+3ab2+2], where a=2 and b=-2

Let's give you a few first, anyway, this simplification evaluation is a must! ​​

Here's a little bit more detailed.

（x+y）²=x²+y²+2xy=1

x²+y²=2

2xy=1-2=-1 xy=-1/2 x 4th power + y 4th power = (x +y) 2(xy) = 4-2 -1/4 =

Hope it helps!!

Solution: From the square of x is equal to 5, the square of x is known to be 5 = 0

Original = x (x's square - 5) - 3 (x's square - 5) + 6

x2=5,x3-(3x)2-5x+21=?

In the equation, the square of x x2 is extracted: x2(x-9)-5x+21x is substituted into the square: 5*(x-9)-5x+21=5x-45-5x+21=-45+21=-24

Forgive me, the landlord, the superscript can't be typed, and the numbers in the formula are several times square after the x.