Math problems: Please pay 55555 on the 30th and 31st 5555

1 Is every call cut? In that case, the intersection of each polyline is a hole, then (10-1-2+1)*2 squared, 16*16=256 holes.

2 Every 4 times a reincarnation, 73 times to change, in fact, 72 times are invalid, then it is only 1 time to change, so A sits on No. 3.

3 2 into 120, ten achievements is the original price, 120 * 5 = 600

4 When it comes to the second subparagraph, the original price is the current price after the addition, so the original price is the same as above, 600, and the final current price is the current price after the addition, so 600*120%=720

5 Each triangle becomes 4 when divided, then one is removed, and 3 are left, and the next time it is removed, the process is repeated in the remaining 3 triangles, so how many triangles are left is how many triangles will be removed next time, and the remaining triangles multiplied by 3 is how many triangles will be left next time

The first time 1 is removed, and 3 are left; So the second time, remove 3, leaving 3x3=9; The third time 9 are removed, leaving 9x3=27; The fourth time 27 are removed, leaving 27x3 = 81

So by the fourth time, remove 1 + 3 + 9 + 27 = 40.

The length of the side first looks at the unilateral side, each time the triangle is equally divided, and the length of the side is exactly half of the length before the division So the length of the unilateral side of the triangle removed each time is half of the original triangle Don't forget the number

So 3x=

Question 1: Fold in half twice - 1 hole;

Fold in half four times - 4 holes;

Fold in half six times – 16 holes;

Fold in half eight times – 64 holes;

Fold in half ten times - 256 holes.

Question 2: Revert to the original state every four times. Therefore, 73 times is equivalent to one change, that is, up and down.

Question 3: Let the original price be x, then (1+20%)x-x=120Get x=600Therefore, the original price is 600.

Question 4: Unclear and unanswerable.

Question 5: Number Series.

The fourth time a total of 1 + 3 + 9 + 27 triangles are removed.

The sum of the length of the removed triangles: 1*(3 2)+3*(3 4)+9*(3 8)+27*(3 16).

1. The relationship between the number of sheared holes x and the number of folds n is: x=2 (n-2).

So, the number of holes folded in half 10 is: 2 8 = 256

2. It will be repeated every four times.

1st time: D C 2nd time: B A 3rd time: A B 4th time: C D 5th time: D C.

B A D C C C D A B B A.

So the position at 73 times is the same as after the first exchange. A is in position 4.

3. Set the original price to be x yuan, and the current price is (1+20%)x=

x=6004, 5, remove 1 for the first time The side length is 1 2 The circumference is: 3*1 2=3 2

The second time I remove 3 The side length is 1 2 * 1 2 = 1 4 The perimeter length is: 3 * 3 * 1 4 = 9 4

The third time to remove 9 side length is 1 2 * 1 2 * 1 2 = 1 8 perimeter length is: 9 * 3 * 1 8 = 27 8

The fourth time to remove 27 side length is 1 2 * 1 2 * 1 2 * 1 2 = 1 16 circumference is: 27 * 3 * 1 16 = 51 16

Cut out a total of triangles: 1 + 3 + 9 + 27 = 40.

The sum of the side lengths of all triangles is: 3 2 + 9 4 + 27 8 + 51 16 = 165 16

1. Stacking 10 times is 256 holes (stacking 2 times is a hole, 3 times is 2 holes, 4 times is 4 holes, 5 times is 8 holes, 6 times 16 holes Therefore, it is a multiple relationship of 2. Therefore, 10 times is 2*2*2*2*2*2*2*2*2*2=256 holes).

2. On the second side, you will find that it will be restored once after 4 times. 73 4=18 surplus 1 is actually equivalent to the first time.

No. 1 C No. 2 D.

No. 3 A No. 4 B.

3. Current price x original price y

x-y=120

x=y+20%y

Solve the equation and you'll find out.

The current price is 720 and the original price is 600

4. Current price x original price y

Seems to be the same as question 3.

The current price of 720 triangles is removed (1+3+9+27=40) and s=3*(1*1 2+3*1 2*1 2+9*1 2*1 2*1 2+27*1 2*1 2*1 2*1 2*1 2*1 2) too lazy to calculate.