Why is f X 5 an even function?

According to the definition of even function: f(-x) = f(x).

f(x)=5 is a constant value, that is, no matter what value x takes, f(x) is always 5f(-x)=5 f(x).

Of course, the definition of an even function is satisfied!

f(x)=5 is a straight line parallel to the x-axis, and after (0,5), this line is symmetrical with respect to the y-axis, so it is an even function, and the formula proves that f(-x)=f(x)=5, so it turns out to be an even function.

It doesn't have to be an even function! This kind of problem should be judged first by defining the domain! If the defined domain is not symmetric with respect to the y-axis, it is a non-odd and non-even function!

If the domain is symmetrical with respect to the y-axis, it is also in the definition, no matter what x takes, f(x)=5, so it can be seen as a function of y=5, a straight line parallel to the x-axis, so it is an even function....

1.It should be symmetrical on the function image with respect to the y-axis.

2.It should be that by definition, f(-x)=f(x) is equal to 5, so it is an even function.

f(x)=f(-x), satisfying this condition is an even function, the original function f(x)=5, f(-x)=5, so it is an even function.

The even function defines f(-x) = f(x).

For f(x)=5

f(-x)=5=f(x)

So it's an even function.

Define or wither pure domain r with respect to origin symmetry.

f(-x)=(-x)defeated mountain (2 5)=x (2 5)=f(x), then f(x)=x 2 5 is an even function.

For even functions.

It will definitely satisfy the nature of Ji Tanfeng.

f(x)=f(-x)

Then for this f(5)=2 in the Divination

You can definitely get it.

f(-5)=f(5)=2

Since the function f(x) is an even auspicious imaginary number, it is in the definition domain of the branch.

The simple x in the inner has f(-x)=f(x), because f(5)=-2, so f(-5)=f(5)=-2

Even function, then f( x) = f(x) is true for all x's in the defined domain, then:

f(－5)=f(5)=8

f(x)=-f(-x) is not an odd dust function. The definition of an odd function is that if any x in the definition domain of the function f(x) has f(-x)=-f(x), then the function f(x) is called an odd function. x is not equal to 0, that is, the definition domain of f(x) is the prudence index that does not include 0, then in its definition domain, there are -f(x)=-f(-x)]=f(-x), so f(x)=-f(-x) conforms to the definition of the simple filial piety Zen Qi function.

Odd function propertiesThe difference between the sum or subtraction of two odd functions is the odd function. The difference between the sum or subtraction of an even function and an odd function is a non-odd and non-even function. The product of two odd functions multiplied or the quotient obtained by division is an even function.

The product of an even function multiplied by an odd function or the quotient obtained by division is an odd function. The integral of the odd function on the symmetry interval is zero.

If the function is even, then the celebration code is positive f(x) =f(-x) if the function is the odd function of repentance.

then f(x) = f(-x).

This is the definition of a parity function, so the macro is based on your problem.

If the function is even, then f(-x)=f(x).

The domain is defined as rf(-x)=-5x+2 and -f(x)=-5x-2

f(-x)≠ f(x) and f(-x)≠-f(x).

The f(x) is neither an odd function nor a trouser wheel even source infiltration function.

Because f(x) is a celestial function of the Qingran even.

So: f(x) = f(-x).

Let t=x+6

So the even function of :f(x+6) is:

f(x+6) state differential rent = f(t) = f(-t) = f(-x-6).