What does the synchronous display of error messages in Chinese and English mean in programming?

Updated on technology 2024-05-23
12 answers
  1. Anonymous users2024-02-11

    Can you be more elaborate?

    1: In the encyclopedia, search for "C C++ Programming Learning and Experimental System", which has an explanation of "synchronous display of Chinese and English compilation error information":

    The compilation error information in Chinese and English is displayed simultaneously, which is helpful for students with poor English to learn C language, and can find more detailed error causes and correction methods by clicking the "Common Error Information Table" in the resource tree in Figure 3 with the mouse.

    2: In the search "C language programming after the operation of the display error name is "Chinese and English error information synchronous display function", so what is wrong?? "What is inside is a correction of the source program.

    Hope it helps.

  2. Anonymous users2024-02-10

    You're using Unicode, and the settings on the compiler can also cause this problem.

  3. Anonymous users2024-02-09

    Sometimes, some other problem, it will also say that it is a mixture of Chinese and English, and you can see if there is anything wrong near it.

  4. Anonymous users2024-02-08

    It just means that there is an error in the program, and it is modified according to the information that the compilation error occurred, and it is not necessarily a problem of mixing Chinese and English punctuation.

  5. Anonymous users2024-02-07

    You'd better post the compiler.

    Printed information, let me guess, how can I guess.

  6. Anonymous users2024-02-06

    What's going on with the last bracket error?

  7. Anonymous users2024-02-05

    Post the error message.

  8. Anonymous users2024-02-04

    #include "

    void main()

    int n1,n2;

    printf("iupnt the frist number");

    scanf("%d,&n1");

    printf("iupht the second number");

    scanf("%d,&n2");

    if(n1>n2) has an extra semicolon here.

    printf("min=%d",n2);

    elseprintf("min=%d",n1);

  9. Anonymous users2024-02-03

    All I know is that QQ can do it.

  10. Anonymous users2024-02-02

    To the one you love the most.

    Don't laugh and listen to me.

    I love you or something, though it's hard to believe.

    But I just want to tell you about it.

    Although I don't know if the life you choose will be wonderful because of me.

    But in the days of weeping and laughing.

    Stand by your side.

    It's the meaning of my existence.

    Dedicated to you. This love song.

    Hey, what did we say that day? 」

    The coldness of the first meeting.

    And then from time to time.

    It's all about the moment of mutual understanding.

    Under our vast sky.

    met and fell in love all the time.

    But in the days of weeping and laughing.

    Stand by your side.

    It's the meaning of living with you.

    Dedicated to you. This love song.

    I'm sorry for causing you trouble all the time.

    Glue-like together.

    Create memories that will be engraved on both of us.

    This clumsy song is sent to you.

    Just like you! I swear to God.

    Hold your hand from this moment on.

    As long as there is a sound.

    I'll be there for you.

    Sing this song of love.

    When I get old and have a hoarse voice.

    I'll always hold your hand.

    But I can't express enough my gratitude.

    Crying, laughing, sad, joyful.

    We all share the time together.

    After countless nights.

    I'll sing this song of love for you.

  11. Anonymous users2024-02-01

    int max(int x,int y);

    int z;

    if(x>y)z=x;

    else z=y;

    return(z);

    Remove";Change to oak.

    int max(int x,int y)

    int z;

    if(x> or y)z=x;

    else z=y;

    return(z);

  12. Anonymous users2024-01-31

    Your C source program should write this rock block method as follows, and you can try again.

    #include

    int main()

    int max(int x,int y);

    int a,b,c;

    scanf("%d %d",&a,&b);

    c=max(a,b);

    printf("max=%d"jujube slow, c);

    return 0;

    int max(int x,int y)

    int z;

    if(x>y)z=x;

    else z=y;

    return(z);

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