The concept of buoyancy in the first three years, the detailed practice,

Updated on delicacies 2024-05-25
11 answers
  1. Anonymous users2024-02-11

    The force received by the object in the liquid is buoyancy.

    The most famous is Archimedes' experiment: the gravitational force of an object discharging water is equal to the buoyancy experienced by the object.

    i.e. float v drain p liquid g

    When an object is suspended in water or floats on the surface of the water, f floats = g object.

  2. Anonymous users2024-02-10

    Are all objects suspended in water have the same density as water?

    It seems like yes, otherwise it will either float up or sink.

  3. Anonymous users2024-02-09

    Isn't it okay for an object to be suspended at any depth in the water? If there are other factors that determine the depth, please advise!! Thank!!!

  4. Anonymous users2024-02-08

    You're thinking too much, and your questions don't need to be thought about

  5. Anonymous users2024-02-07

    40cm below the water surface, so the cork density: water density = 40:100, cork density is 400kg m.

    The cork weighs 400*, and the buoyancy is 1000* when fully immersed, plus 600* force.

  6. Anonymous users2024-02-06

    Hello! A steamship has a displacement of 20000t, its dead weight is to the power of 7 n, he can load ---1

    9 10 7---kg cargo.

  7. Anonymous users2024-02-05

    I want to sell some exam books in Paipai and **, and I want to choose a store name, which must not only have a literary atmosphere, but also let people see that I am selling books, what is the best name.

  8. Anonymous users2024-02-04

    The buoyant force experienced by the object is equal to the gravitational force exerted by the dislodged liquid. The buoyancy of the object does not change, i.e., the g-row does not change. And because g liquid = density multiplied by volume multiplied by g the density and g are unchanged, so f float is unchanged.

  9. Anonymous users2024-02-03

    Because the flask is always floating on top of the water or suspended in the middle, according to the principle of equilibrium of force, g = f floats, and because g does not change, the buoyancy force also does not change in magnitude. (This is when considering that the air quality is negligible!) If air quality is taken into account, there is a change

  10. Anonymous users2024-02-02

    Yes, you're right, the volume of the liquid drained is not changing. Don't assume that the part of the flask is not the water that the flask is discharging just because there is gas in the flask. The liquid molecules are still present on the contact surface; The effect of blowing is only to use the force of the gas to lift the flask, and it does not have any effect on the buoyancy.

  11. Anonymous users2024-02-01

    In fact, buoyancy is difficult to say, and for most students, buoyancy in junior high school physics is indeed a difficult point. Here I would like to share my opinion.

    To solve the buoyancy problem, first find out the known conditions, such as: the mass, volume, density or gravity of the object, the density of the liquid, whether the object is fully submerged in the liquid or partially in the liquid, and then determine the float and sink of the object, and then determine the calculation method according to these known conditions and float and sink conditions.

    The methods for determining the float and sink are as follows: comparing the F float with the G object (Sinking: F float G matter; Levitation and floating:

    f, floating, glossy); Comparison of m-row with m-matter (sinking: m-row m-matter; Levitation and floating: m row m matter); Compare V-row and V-object (sinking and suspension:

    V row V object; Floating: V row V object); Compare p liquid and p matter (I can't type the letter of density, so I have to replace it with Xianxiaotan P) (sinking: p liquid p matter; Hover:

    P liquid P substance; Floating: p liquid p matter) (here refers to the average density of the object), there are 4 ways to calculate buoyancy: experimental method:

    f float g object - f show (or f pull) (for sinking objects); Differential pressure method: f float f down - f up; Equilibrium method: f-float g-object (suitable for suspended and floating objects); Principle Method:

    F, float, g, m, p, liquid, v, g. But I still have to be cautious and be able to use it flexibly.

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Look at the syllabus, it's all there.