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NaOH + H2S (excess) ====NaHS+H202NaOH + H2S (small amount) ====Na2S + 2H2OH2S === Heat H2+S
2h2s+so2====3s↓+2h2o
2H2S+O2 (a small amount)====Ignite 2H20+2S H2S+CuSO4===Cus +H2SO42H2S+3O2 (sufficient)===Ignite 2H2O+2So2Cl2 br2 I2 SO2 can oxidize H2S2FeCl3+H2S (a small amount)==2FeCl2+2HCl+S I don't know if these are or not.
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At room temperature, hydrogen sulfide itself is a gas, and there is no volatilization.
The truth is like a dead man who does not die again.
However, the aqueous solution of H2S, hydrosulfuric acid is volatile.
About the chemical properties:
-2 valent s are present in H2S
So: Reducible, H2S is reducible and can react with highly oxidizing substances.
For example, Cl2, O2, Hno3, KMno4, etc.
Acidic, although H2S is a weak electrolyte, there are also some freely movable H+ in the aqueous solution that can react with alkali to form salts and water.
Regarding the reaction with O2, there are two cases:
O2 sufficiency is: 2H2S + 3O2== Ignition ==2H2O + 2SO2
When O2 is insufficient: 2H2S + O2====2H2O + 2S, which is about the same
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H2S is volatile, rotten egg smell, high school has such a reaction, he has a relatively strong reduction, negative monovalent S is easy to be oxidized by Cl2 or O2 into S elemental.
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Hydrogen sulfide is a gas, right? Volatilization is generally used for liquids.
Hydrogen sulfide reacts with oxygen.
2h2s+o2===2h2o+2s↓
2H2S+3O2==Ignition==2H2O+2SO2
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When SO2 is introduced into the H2S solution, it will appear yellowish and turbid, which proves that SO2 is oxidizing.
Chemical equation: 2H2S + SO2 ===3S + 2H2O
The ionic equation is the same as the chemical equation, and all the substances in this reaction cannot be taken apart.
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Illustrate the oxidizing properties of sulfur dioxide.
so2+2h2s=3s↓+2h2o
This is the ionic equation because the reactants are all non-electrolytes (weak electrolytes) and the products are insoluble and weak electrolytes (water).
SO2 is introduced into the H2S solution, and a yellow precipitate (S) is formed and disproportionation reaction, at this time, sulfur dioxide is used as an oxidant, and hydrogen sulfide is used as a reducing agent, indicating the oxidation of sulfur dioxide.
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It becomes cloudy and has a yellow precipitate.
so2+2h2s===3s↓+2h2o
Proven to be oxidizing; The ionic equation is the same as the chemical equation (both are weak acids).
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2H2S + SO2 = = 3S (precipitation) + 2H2O
The ion equation is also this.
The oxidation of SO2 was demonstrated as its valency dropped to 0 valence.
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In the saturated solution of H2S, the correct relationship between the concentrations of each substance is (). Stuffy holes.
Correct answer: c(hs-) c(h+).
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Summary. It reflects the strong oxidation of concentrated nitric acid, and the reaction belongs to the redox reaction, and the reaction equation is: 2Hno3 (concentrated) + H2S = 2H2O+S + 2NO2 (appropriate amount of nitric acid).
8Hno3 (concentrated) + H2S = 8NO2 + H2SO4 + 4H2O (nitric acid excess).
What are the properties of H2S and concentrated nitric acid reaction?
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It reflects the strong oxidation of concentrated nitric acid, and the reaction belongs to the redox reaction stove, and the reaction buried mu equation: 2Hno3 (concentrated) + H2S = 2H2O + S + 2NO2 (appropriate amount of nitric acid) 8Hno3 (concentrated) + H2S = 8NO2 + H2SO4 + 4H2O (excessive nitric acid bending).
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2Hno3 (concentrated) + H2S = 2H2O+S +2NO2 Fiber beam (nitrate ante erection Yu stuffy rock.
Appropriate amount) 8Hno3 (concentrated) + H2S = 8NO2 + H2SO4 + 4H2O (excessive nitric acid).
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