High School Mathematics, !!!!!!!!!!!!!!!

If y=x, a is a power function, and there can be nothing in front of x.

I can be sure that what is said in the book is called odd and even functions and so on and what they do

Example 9The characteristic equation of differential equations r 3-r 2 = 0, r = 0, 0, 1

The solution should be y = x 2(ax 2+bx+c) = ax 4+bx 3+cx 2,y' = 4ax^3+3bx^2+2cx, y'' = 12ax^2+6bx+2c, y''' = 24ax+6b

Substituting the differential equation yields 24ax+6b-12ax 2-6bx-2c = 3x 2

12a=3, 24a-6b = 0, 6b-2c = 0

The solution gives a = -1 4, b = -1, c = -3

The special solution is y = -(1 4)x 2(x 2+4x+12).

For example, in your question, =0 is a double eigenroot, and the following 3x 2 happens to be the case where the eigenroot is 0, so the special solution is set to x 2 (ax 2+bx+c), and select the c term.

I guess you put so many exclamation marks because the number of words is not enough, and the symbols are made up so that they can be published.

- infinity) and (0,1) minus intervals.

1,0) and (1,+infinite) increment intervals.

Let me give you a little feasible advice I just finished the college entrance examination Science candidates in Shandong Province Mathematics 125 I think I have a little idea.

Look at the way you speak, you've just graduated from junior high school, and you're about to face high school math, and the biggest difference between junior high school math and junior high school math is that junior high school math can be done by translating the conditions, and a lot of high school problems need to be memorized by the teacher, and then recorded in the error book, and chewed slowly after class.

Let's give a few points of caution.

1. Listen carefully in class.

Don't miss any class, if you really want to learn math well, don't worry that high school math will not have nothing to do with junior high school math You can rest assured that as long as you can understand the teacher's lecture in your own ability at the last moment of your first year of high school, you will definitely have a chance to get a high score in the college entrance examination.

2. Make any definition of the concept very well.

High school mathematics is well known, as soon as it comes up, it is a set, there are a lot of things that are easy to confuse, you must understand, if you don't understand the definition, you will suffer a lot later, this kind of problem generally does not come out, but after a long time, another one will open the gap.

3. If you don't, just ask.

There must be enough people in the class to think that they are like gods, and this kind of person is a good learning resource for themselves, so you must ask.

4. Wrong question book!!

And that's the most important thing I think, because we have a very good math master, and he even knows a little bit about calculus (he barely studied it in high school, but you'll understand it by then) and his secret book is a good enough book to use as a teaching aid, and he sorts out all the classic questions and analyzes the core steps, and my own book is written down when the teacher is lecturing, and this record can record all the teacher's emphasis, and our class has the best memory book, and I didn't remember it when I read my error book I'm still a little proud that I make the most of my eyes, ears and hands in every class, and I can write at least two textbooks in a semester, and then you'll see how much you've accomplished.

5. Computing ability requirements.

In the second semester of the second year of high school, you will start to train your numeracy skills to a large extent, and when the time comes, derivatives and conic curves will test your numeracy skills very much.

6. Temporary strategy.

This question cannot be said to have a unified method, but it can only be said that first look at the difficulty of the question, the amount of questions is generally 22 questions, and you have a general understanding, and then remember to sit back from the beginning, and you will not be willing to let go.

It is very likely to get a high score, and junior high school math is very different from high school math, and the subtle way is also different! But you have to lay a good foundation from the first year of high school.

If you can study hard and are not afraid of hardship, you will definitely get good grades, which is certain, and the grades will be higher than you think.

Believe that you will succeed and you will do it.

Of course, middle school math and high school math are not on the same level at all. As long as you study seriously, junior high school will hardly affect high school or anything.,I think all science subjects are.,But English may be basic.。。

Believe in yourself! As long as the deep iron pestle is sharpened into a needle! Usually do more questions, of course, there must be a method to learn, so that you can get twice the result with half the effort, confidence is also indispensable, and you need not to be discouraged!

··· High school math, eh, knowledge is very large. When I was a sophomore in high school, I could score 90 in mathematics, and I made up four or five classes to more than 120... Just look at the question type...

< 4 3 —— 3 —— 0<2 <

Multiply both sides by -1 to get: 3< -get: 4 3<2 <7 3 -- 7 6<- 2 3 -- get:

Solve with linear programming.

I won't draw the picture, the phone can't play the process, take the minimum and maximum values in (0, pi), (pi 2, 5pi 6). i.e. -pi<2a-b

1.Let the tolerance be d, then s7=7a1+(7·6 2)d, s15=15a1+(15·14 2)d, and s7=s15 can be obtained: 7a1+21d=15a1+105d, 84d=-8a1

a1<0, d>0 and a1 d=-21 2

sn=na1+(d/2)n(n-1)=(d/2)n²+(a1-d/2)n

With the help of the unary quadratic function f(x)=(d 2)x + (a1-d 2)x, its minimum value is in x=-(a1-d 2) [2·( d 2)]=1 2-a1 d=11.

So the minimum value of the available sn is S11

2.∵sn=3n-2n²，∴a1=s1=1，na1=n>0

Obviously, when n 2, sn=n(3-2n)<00

Therefore, when n 2, na1 > sn>nan, c should be chosen

3.Let a4=a, then a1=a-3d, a5=a+d, a6=a+4d

a1a8-a4a5=(a-3d)(a+4d)-a(a+d)=12d²<0

a1a8

∵a∪b= a∩b=

A b must contain 3

Case 1: Assuming a= then it is known from Vedica's theorem.

3+5=-a,3 5=b Solve a=-8 b=15 c=-8 Case 2: Assuming b= then it can be seen from Veda's theorem.

3+5=-c,3 5=b solution a=-8 b=15 c=-8 case 3: a=, then you need to know that when =0, x has a solution. So =a 2 - 4b=3 9+3a+b=0 you can solve abc, and the same goes for b=, and so on.

I hope my answer is helpful to you.