I have been bothered for a long time by high math problems, math problems, I have been bothered for

The same operation on both sides of the equal sign still holds, what is there to doubt?

If both sides do the same operation, the properties of both sides change, and the properties of both sides change, then it's troublesome!

Shouldn't all calculations have to be reconsidered!

I don't know how you thought of this problem, but this is actually what everyone thinks is an axiom!

See what you mean.

But according to you, I think it's easy to explain.

Since you say that y is a function of x, it means that as long as x is constant, y must be constant, and we can easily understand this according to the property that the value of the function and the independent variable are one-to-one! According to the possibility that x is a constant and y is not a constant, there is no such thing as a constant!

That's just a coincidence. You can't overturn a mathematical theory with occasional coincidences.

Not every formula is true.

hhhh!I know here!

An integral is the number before a derivative is reduced to a derivative, if a(x)=b(x).

The derivative of a(x) = the derivative of b(x), and conversely, the derivative of a(x) = the derivative of b(x).

a(x)=b(x),xdx =2ydy,see xdx,2ydy as two equal numbers,xdx= 2ydy,

First-order differential form invariance.

Solution: Share a solution.

k^3+6k^2+11k+5=(k+3)(k+2)(k+1)-1，∑[k^3+6k^2+11k+5]/(k+3)!=∑[(k+3)(k+2)(k+1)-1]/(k+3)!=∑1/(k!)-1/[(k+3)!]

Control e x= (x n) (n!).)(n=0,1，……e=∑1/(n!)。

k=1,2，……n, n, 1 (k!)=e-1，∑1/[(k+3)!]=e-1-1/2!-1/3!, original = (e-1)-(e-1-1 2!-1/3!)=1/2+1/6=2/3。

FYI.

Subtract the small area from the big one. Large areas are easy to calculate.

aqui te amo。

The odd function f(0) = 0.

x→0，lim f(x) =f'(0)

But f(x) is undefined at point 0.

You can go to the break point.

bf(x) is an odd function, so f(0)=0, and limf(x)=f when x approaches 0'(0) with Lobid.

And f(0) is meaningless, so it is a class of discontinuities.

1) If 0

Let the original = a

lna = 1 n ln [ 1+x n +(x 2) n ] by the signifier of the law of Lopida.

lim(n→+∞lna

x^n lnx + x²/2)^n ln(x²/2) ]1+x^n +(x²/2)^n ]

If 12, then 0

2, original = x 2

It can be combined and is the original = max

Suppose there are 12 numbers in total, and you know that the result is 78, and you say that the result is that the last number is 78

Or is the sum of 12 numbers 78?

The first digit is compared to the latter digit.

Is the previous number incremented gradually, is it increased randomly, or is it the same number each time?

Average 78 12=

The last number.

Mean difference (I won't write about it later, because it's not an integer.) Maybe you're having the wrong number. Let's take a look.