Difficult problems, difficult math problems to solve

-You think everyone is a god.,You don't say anything because of what.。。 What's this called?,Guess the riddle?。。。

Generally speaking, if there is no expression in this statement, I said it lightly. That's miserable.

If it's coquettish, or angry, it's fine.

Don't panic when you encounter this. Look at you typing, you can't speak. To apologize, I don't know what to apologize for, I have to go to the road, buy flowers and the like, girls, I enjoy the process of chasing men, and it's over.

Facing it normally, what should be yours is yours, and what shouldn't be not.

You just say that you like her very much, tell her what is in your heart, and love someone sincerely!!

Do what you can do to make her happy.

Say you love him and buy something for him.

My girlfriend said: You said, you don't like me anymore.

If a car travels from A to B and increases its speed by 20%, it can arrive 1 hour earlier than scheduled. If you drive 120 kilometers at your original speed and increase your speed by 25%, you can arrive 40 minutes earlier. How many kilometers are A and B apart?

The speed after the acceleration is the original: 1 + 20% = 6 5, the time after the acceleration is the original: 5 6, and the time saved than the original is: 1-5 6 = 1 6

The planned time is: 1 1 6 = 6 hours, the speed after the second acceleration is the original: 1 + 25% = 5 4, the time used will be the original: 4 5, which will save time than the plan: 1-4 5, if the whole process is speeded up, it will save time: 6 (1-4 5) = 6 5 hours, the actual only saving: 40 60 = 2 3 hours, therefore, the distance of speeding up the journey accounts for the whole journey: 2 3 6 5 = 5 9, 120 kilometers is equivalent to the whole journey: 1-5 9 = 4 9, so the whole journey is: 120 4 9=270 km.

80 60 = 4 3 hours = 80 minutes.

80 10 = 8 minutes between each stop.

Stop for 2 minutes at each stop.

Xiao Ming set off from place A at 6 o'clock in the morning to prepare to go to place B, and got off the bus when he passed the third stop, and the time at this time was 2*10+8=28, which was 6:28, and it was 6:33 after buying pancakes.

Buses run every 4 minutes.

Xiao Ming sat at 6:36 (6:28+8).

7 stops away from place b.

It takes 6 * 10 + 8 = 68 minutes to arrive at this station from station B.

5 o'clock + 68 minutes + 4 (n-1) minutes.

n=1 represents the first trip.

n=8, exactly 6:36.

Xiao Ming sat at 6:36 and met the time when Xiao Ming arrived at B on the 8th bus from B.

6:36 a.m. + 68 mins.

7:44 a.m.

Departs at point B: +4 (M-1) at 5 hours

7:44 = 5 hours + 4 (42-1).

The 42nd train departed from place B.

Along the way, Xiao Ming can encounter 36 subways from B to A (including those encountered when he first got on and off the train).

The total time of a trip from A to B = 80 60 * 60 + 8 * 2 = 80 + 16 = 96 minutes.

5/4=1……1 Xiao Ming takes the third train, and the interval between the third and first trains is 2*4 minutes.

Xiao Ming's total time = 96 + 2 * 4 = 104 minutes.

104 minutes from B to A: Subway 104 4 = 26 flights.

Xiao Ming encountered a total of 26 subways from B to A.

80km each way has 10 stops per way, then it is nine sections, 80 9m is not easy to calculate, I'm afraid it is evenly set up with 11 stops, if it is 11 stops, then it is easy to do.

The one-way journey is 80km, with a total of 11 stations, there are 10 sections, 8km between the two stations, and the subway takes 8 minutes between the two stations.

Xiao Ming gets on the bus at 6 a.m. and gets off at 6 a.m. when he passes the third stopPoint 18, 6Point 20 split and the car immediately behind is 6

Point 22 to 6Point 24 and go separately and Xiao Ming came back after buying things is 6Point 23, so it can catch up with 6

The car from place A at point 04 (6Point 24 separated).

The departure time of the subway in B is 5 o'clock in the morning, and the stop time from the first train to Xiao Ming is 6Point 18 minutes [7 * (8 + 2) + 8 = 78 minutes] 6Walk at 20 a.m. and arrive at the station at 5:04 a.mAt 22:22 a.m., we will go at 6:24 a.m.

Xiao Ming got on the bus from 6:23 and drove to B at 6:24 It took 78 minutes (that is, 7:42 to B) from 5:42 to 7:42, during which a total of (162 4+1=41) 41 buses were sent out from B.

Xiao Ming has to encounter 41 subways from B to A (2 of which are at the third stop).

Xiao Ming went to the supermarket 1000 meters away at a speed of 3 meters per second, it is known that the wind speed is 5 meters per second, and the red light has to wait for 30 seconds, and there will be 4 traffic lights along the way.

The one-way journey is 80km, a total of 10 stations, 8km between each station, in the case of a constant speed of 60km hr, it takes 8 minutes to complete the distance between each station, plus 2 minutes for each station to stop, that is, it takes 10 minutes to send the departure from the previous station to the next station, and the whole journey is 100 minutes (1hour40mins). The first train is 5am, and the distance of 6 stations has been completed when Xiao Ming departs, that is, it is 4 stations away from Xiao Ming, so the train that Xiao Ming takes and the first train at station B will meet at the second station from A to B, that is, 6:20am.

And because Xiao Ming took 5 minutes at the third station, that is, he could not take the train from station A at 6:04am (the departure time of this train at the third station is 6:34am), that is, Xiao Ming could only take 6:

08AM train departing from station A. The bus arrives at B at 7:48am.

Xiao Ming saw that the first train departed from B and arrived at station B took a total of 1 hour and 28 minutes, that is, 88 minutes, and in 88 minutes, a total of 22 trains departed from station B, plus the first car, Xiao Ming met a total of 23 trains.

If the time it takes for two people to meet is 11 (6 5) = 1 hour, then the dog runs for 1 hour, and it runs 20 meters per hour, then the puppy runs a total of 20 meters.

I'm x, simple.

The dog has been running, to know how far it has run, just to know how long it has been running The time for the dog to run is the time when the two people meet from the beginning, the two meet and walk, the time is 11 divided by 6 plus 5, and then the distance the dog runs is 20 times that time, calculate it yourself...

Such a simple question is also asked, tangled...

11 (6+5)=1 (hour)...Time of Encounter.

20 1 = 20 (m)Puppy runs the distance.

Since the triangle ABC is a right-angled triangle, AC2=AB2-BC2 is obtained from the Pythagorean theorem, and the area of AC=3 triangle ABC is obtained s=(1 2)xabx

cd=(1/2)xacx

BC so 5xcd=4x3 gives cd=12 5

Use the area method: first use the Pythagorean theorem to find ac=3, and then sδabc 1 2 cd ab 1 2 ac bc

So CD 12 5cm

This question is solved using the dog's time being the same as the amount of time they run.

It takes time for Xiao Ming and Xiao Hong to meet: 11 (6+5)=1 hour, so the dog ran for 1 hour.

So the dog ran 1*20=20 meters.

The total weight left after eating 40g per pack is the total weight of the previous 3 packs, so the weight eaten is the total weight of the original two packs.

So it turns out that each pack weighs 40 5 2 = 100g

It is also possible to set the original weight of each pack x

5×(x-40)=3x

Solution x=100