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The frictional force of the ground towards b is static friction. The force analysis of B shows that the gravitational force is vertically downward, the tension of the rope (in the direction along the rope), the gravitational force of magnitude A, the support force of the ground facing the object vertically upward, and the horizontal leftward friction of the ground facing B. Can be decomposed orthogonally.
In this way, the frictional force of the ground facing b is the component of the tensile force along the horizontal direction, and the magnitude is 4*10*1 2=20 N.
The magnitude of the pressure of b on the ground is equal to the support force of the ground on b.
The gravitational force equal to b minus the component of the tensile force in the vertical direction.
The size is 100-40 * half of the root of 39 is equal to 100 minus 20 times with three.
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As it is at rest, the horizontal net force is zero.
There is f=sim30*ma*g=
The resultant force in the vertical direction is zero.
The pressure of b on the ground is equal to the elastic force of b on b and is set to f1, f1 = mb * g - sim60 * ma * g = 10kg * 10n
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The force component of the rope along the vertical direction at 1 b is less than 10 N, so it can be stationary when changing the state. Then only consider the horizontal force balance, the component of the rope along the horizontal direction is 40n 1 2=20n, so the friction is 2o.
2 You can do the force analysis again, and the ground support force + vertical component force = gravity, that is, n + 40 3 2 = 100 can get the answer.
Hope it helps.
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The weight and width force can be decomposed into the force along the inclined plane downward and the pressure on the inclined plane Medium The pressure on the inclined plane is obviously not right The effect of several components is the same as the resultant force, so the object acting is also the same Since the acting object is the same, why can gravity be decomposed into the force along the downward slope and the pressure on the inclined plane, the force on the inclined plane is the inclined plane, and the force on the gravitational force is the object, so it is wrong, only the cautious object or right, so choose A
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First of all, the answer is yes.
Second, its strength cannot be decomposed, a force is a force, and the so-called decomposition of force is actually a convenient consideration, in order to make it easier to calculate. For example, if a force is oblique, it is not easy for you to calculate, but if you break it down into two forces, vertical and horizontal, sometimes it is much easier to calculate. So if one is horizontal or vertical, theoretically it can be decomposed into the sum of two oblique forces, but this is to do it yourself.
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Theoretically, yes, but in combination with the specific situation, otherwise it may be a meaningless decomposition!
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The same weight, because that is to say, the work of overcoming gravity is the same.
The moment of f1 is less than that of f1, and the moment of f2 is greater than that of f2.
Therefore f1> f1, f2< f2
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Tell the landlord that I will regret not accepting me.
The decomposition of forces is like a triangle.
Like the diagram you gave.
As the weight does not change. One side of the triangle remains unchanged.
The other two changes, you will be very clear.
I don't need to point it out.
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The resultant force between OA and OB must be equal to G, and as OA becomes longer, the force it generates in the vertical direction will be smaller, and the force required for OB will be greater. (According to the parallelogram law of force).
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Decomposition of forces. Physical terms.
1.What is the decomposition of force? If a force acts on an object, it has the same effect on the object as several other forces acting on the same object at the same time, and these forces are the components of that force.
For example, fix two rubber ropes to a wooden board and tie two thin wires at the knots of the two ropes. As shown in Figure 3-65, pull the node to a certain position O with a vertical downward force f, and pay attention to the effect produced by the tensile force f. Then, the tensile force F1 along the Bo direction is used to stretch the OB, and the tensile force F2 along the AO direction is specially stretched OA, when F1 and F2 are the appropriate values, the joint effect of the node is also pulled to the position is the same as the effect of the action of F, F1 and F2 are called the components of the tensile force F.
Finding the component of a force is called the decomposition of the force. In the decomposition of force, the force that is decomposed (the resultant force) is actually present and has a corresponding force object; Component forces, on the other hand, are several forces that are conceived and do not have a corresponding force object. 2.
How to decompose the force? The decomposition of a force is the inverse of the synthesis of a force, again following the parallelogram rule: if a known force is taken as the diagonal of the parallelogram, then the two adjacent sides of the parallelogram where the forces are known to have a common point represent the two components of the known force.
However, if there are no other restrictions, an infinite number of different parallelograms can be made for the same diagonal. For this reason, when decomposing a force, the following two methods are often used: Decompose according to the actual effect of the force - first determine the direction of the component force according to the actual effect of the force, and then find the magnitude of the component force according to the parallelogram rule.
Decomposition is carried out according to the "orthogonal decomposition method" - the Cartesian coordinate system is selected reasonably, and then the known force is projected onto the coordinate axis to find its two components. Regarding the first decomposition method, we will make further discussions in the "development level" later, here we will focus on the typical problems of several elimination schools that decompose the force according to the actual effect: the decomposition of the oblique upward tension force of the object placed on the horizontal plane Put the object on the spring scale, pay attention to the indication of the spring scale, and then act on a horizontal tension, and then make the direction of the tension slowly deflect upwards from the horizontal direction, and the indicator of the scale gradually decreases, indicating that the tension force has the effect of pulling the object forward horizontally. There is also the effect of lifting objects vertically.
Therefore, the diagonal upward tensile force can be decomposed in both horizontal and vertical directions. Decomposition of the gravity of the object on the inclined plane As shown in Figure 3-68(a), a layer of sponge is laid on the inclined plane and a cylindrical weight is placed, and the weight can be observed to roll down at the same time, and the sponge deformation can also be deformed with pressure, thus explaining why the gravity is decomposed into two bridges, such as f1 and f2, which are prepared as a component.
2 triangle rule, that is, the two components of the force end to the end of the Min bridge is destroyed, then the resultant force is a directed line segment with the head end of F1 pointing to the end of F2.
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Let the pulling force be f
Then, according to the decomposition of the auspicious land force, it is necessary to dismantle it to a vertical upward component fsin 30° and a horizontal to the right component fcos 30°
The original weight of the wooden box is 183N, and after subtracting the vertical upward component, his actual weight is (g-fsin30°).
then its sliding friction is .
Because it is moving at a uniform speed, it is.
Solve the equation to get f=
3. Force (common force, force synthesis and decomposition). >>>More
There is no hypotenuse or right-angled edge, because the decomposition is whatever you want. As long as it is a closed graph, you can break it down into many sides. Just for the convenience of calculation, it is generally necessary to decompose a vector into two vectors perpendicular to each other, just like 10 can be equal to 1+9, 2+8, can also be equaled, and so on, there are infinite kinds of decomposition results. >>>More
It's because there is static friction when it's stationary and sliding when it's sliding, and the two frictions aren't the same, and the maximum static friction is the same as sliding friction (note that static friction is not a fixed straight, but sliding friction is straight.
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The first belongs to rolling friction, the essence of rolling friction is to produce a drag moment, that is, the support force of the ground is no longer directed to the axis of the wheel, but there is a forward offset in one direction, this offset produces a moment that hinders the rotation of the wheel, making the rotation slower, if the wheel and the horizontal plane are ideal rigid bodies, if they do not deform, they are not subject to rolling friction and move forever, even if the contact surface is rough. >>>More