How many tons of hematite containing impurities 20 can be used to smelt 50 tons of pig iron containi

1.Theoretical calculation: If a ton of hematite containing 20% impurities is used, 50 tons of pig iron containing 4% impurities can be smelted. According to the law of conservation of mass, the mass of iron in iron ore is equal to the mass of iron in pig iron.

80%a=50×96%

a=602.Actual production: It is impossible to smelt 100% of the iron in the iron ore in the actual production, so the iron content in the smelted pig iron must be less than the iron content in the iron ore, which is also related to the yield, so there are:

80%a yield = 50 96%.

Therefore, the tonnage of iron ore required in actual production is: 60 yield.

In actual production, there will also be losses of iron ore, such as iron loss caused by iron-making workers in the process of sending iron ore into the smelting furnace, iron loss caused by molten iron or pig iron transfer. Probably, the final tonnage of iron ore required is greater than the calculated tonnage!

The size of the yield is related to the excellence of the factory's production process, the advanced degree of equipment, and the ability of workers.

Superior technological process, advanced equipment, good workers + good management play a very important role in the improvement of productivity!

To actually conclude that it is "pig iron containing 4% impurities", the production department and the quality inspection department must cooperate closely!

Good luck with you! Note: Smelting rarely directly requires 20% of the ore, and it is necessary to let the concentrator process it. Processing:

20% 30% 40% 50% 60% 65%, the loss of multiple processing is huge, to process more than 60% of the ore and then smelt 96% of the pig iron, how much ore is lost, you have to calculate the accurate tonnage of 20% of the raw ore to be invested at the beginning is not easy!

In my opinion, if the ** rate of the concentrator is 20%, and the smelting rate is 35%, about 580-600 tons of 20% of the raw ore must be invested!

20% of iron ore is of very little value unless it is readily available! It is difficult to sell it even if it is opened, or it is sold for very little money, and it is a loss-making ......

The impurities are: 50x4%=8 tons.

So: 8 20% = 40 tons.

Answer: With 40 tons of hematite with 20% impurities, 50 tons of pig iron with 4% impurities can be smelted

It's as simple as that.

According to your current content, 4 tons of iron ore can produce about 1 ton of 65% iron ore powder after repeated grinding and magnetic separation, and then 3 tons of iron ore powder with 65% content can make 1 ton of pig iron.

Basically, 12 tons can produce 1 ton of iron.

You need 50 tons x 12 = you need 600 tons of iron ore.

The main orange good component of Chiji Wuzhou iron ore: Fe2O3

Set up the need for hematite x tons.

According to the iron quality is unchanged, that is, the mass of iron in the iron mask ore is equal to the mass of iron in pig iron.

x * 112 / 160) *1 - 20 ％）50 * 1 - 4%)

Get. x= tons.

So it takes tons of hematite.

It is a simple method to set the quality of raw sail iron that can be smelted at most 4% with impurities. Conservation according to the element iron.

1600 * 80% *112 / 160 = x * 1 - 4%)

Get. x= tons.

Therefore, Wang Kuan can obtain tons of pig iron containing 4% impurities.

There is Fe2O3 mass fiber per mu = 2000 80% = 1600t;

It can refine the mass of Fe = 1600 112 160 = 1120T (according to the mass fraction of Fe in Fe2O3, or according to the square cluster program).

Mass of smelted raw iron = 1120 97% =;

fe＝fe2o3*（56*2/160）

Pig iron Fe 95

So: Pig Iron Cavity 600*75 Sell Companion Shirt*(112 160) 95 Random Omen

The sock key is calculated to be 40 tons, and the solution: let the mass of pig iron containing 20% impurities in the refining cave be x high temperature + 2fe + 160112200t 80% (1-20%) xx = 140t Answer: The quality of pig iron containing 20% impurities can be refined and 140t is 140t

Hematite. Main ingredients:

Fe2O3200 tons containing impurities, 20% hematite containing Fe2O3 mass.

200x1-20%) = 160 tons.

The mass fraction of Fe in Fe2O3 is 56x2 (56x2+16x3)=112 160

160 tons of Fe2O3 mid-limb hall staring calendar and Fe content is 160x112 160 = 112 tons.

Analysis From the mass of sorghum of hematite wide cracking, the mass fraction of iron oxide, and the mass fraction of iron in pig iron, the mass of smelted raw iron can be calculated according to the chemical equation of hematite ironmaking

Answer: Suppose the mass of hematite containing 80% iron oxide is X Fe2O3+3CO high. Lukewarm.

High. Lukewarm. 2fe+3co2

80%x 200t×（1-2%）

TT should be cautious. x=350t

A: 350t of hematite containing 80% iron oxide is required

Solution: Let the vertical search quality of raw fiber town iron containing 20% impurities be coarse x high temperature +2fe + 160112200t 80% (1-20%) xx = 140t Answer: The quality of pig iron containing 20% impurities can be refined is 140t

Let the amount of pig iron containing 20% impurities be refined and the amount of dust is x high temperature +2fe + 160112200t 80% (1-20%) xx = 140t Answer: The quality of pig iron containing 20% impurities is 140t

200 tonnes of hematite with impurities is required.

Solution 1:

Among the 80t hematite containing 20% impurities, there is hematite (Fe2O3) 64T, and the exercise process is 2Fe2O3+3C, high temperature 4Fe 3CO2

64 xx= that is, pure iron, the actual product, contains 4% impurities, so the actual pig iron solution method 2: 80t of hematite containing 20% impurities, there is hematite (Fe2O3) 64t, which contains Fe elements, the mass is 112 160 * 64 = because the actual product contains 4% impurities, so the actual pig iron =

X tons of pig iron containing 4% impurities are smelted.

Fe2O3 + 3Co = high temperature = 2Fe + 3CO2160 2 * 5680 * (1-20%) x (1-4%) column proportional solution x = = tons.

It can smelt tons of pig iron containing 4% impurities.

The mass of ferric oxide = 100t * 80% = 80t Among them, the mass of iron = 80t * 48 160 = 24t, so in the pig iron after smelting, there is 24t of iron element.

So the total mass of pig iron = 24t (1-3%)

X tons of pig iron containing 4% impurities in the liquid are refined.

Fe2O3 + 3Co = high temperature trapped front = 2Fe + 3CO2x (1-4%)

The proportional solution of the column gives x==tons.

That is, the loss of the ruler can be smelted into tons of pig iron containing 4% impurities.