Specific methods for the removal of sulfur impurities in iron ore. Analytical experiments. 20 urgent

In general, it can be burned and calcined in the air.

As can be seen from the reaction equation given in the title, the consumption of O2 by the S element in FeS2 is the same regardless of which reaction is carried out (because it is all generated by SO2), and the key to the amount of oxygen consumption is to see what the Fe element is finally converted into.

If it is converted to Fe3O4 with less O, less oxygen is consumed; Conversely, if it is converted into Fe2O3 with more O, more O2 will be consumed.

The amount of 480gfes2 is 480g 120g mol=4mol, which contains 8mols atoms and 4molfe atoms, S is converted into SO2 and consumes 8molO2, and the O2 consumed by FE is (b-8)mol, according to the title, we know n(fe) :n(o) 4 : a = 4:

2(b-8), solution: 2b = a+16.

When FeS2 all produces Fe2O3 with a large oxygen content, the oxygen consumption is the highest, and N(Fe) :N(O) 4 : A = 2 :

3, i.e. a = 6, where 2b = a + 16 = 22 and b = 11.

When FeS2 all produced Fe3O4 with a small oxygen content, the consumption of hypoxia was the least, and N(Fe) :N(O) 4 : A = 3 :

4, that is, a = 16 3, at this time 2b = a + 16 = 64 3, b = 32 3.

This is because the relationship between a and b is to be explained, and if the sum only requires the minimum value of oxygen consumption, it can be calculated according to the reaction equation.

3fes2＋8o2→fe3o4＋6so2

4 xx = 32/3

4fes2＋11o2→2fe2o3＋8so2

4 yy = 11

Analysis: It can be seen from the chemical formula that the factors affecting the change of the lack of the solution are the iron mountain participating in the reaction and the hydrogen generated. For every 56 parts of iron that "enter" the solution, 2 parts of hydrogen can be generated and the mass of the solution is increased.

56-2=54 (parts). The difference given by the problem is gram-50 gram = gram, and the proportion can be calculated accordingly.

Fe + H2SO4 = FeSo4 + H2 (gas) The mass of the solution increases.

x56/54=x/

x = so the purity of this iron = choose c.

Let the mass of iron be x grams, and the reaction with sulfuric acid can produce Y grams of H2Fe + H2SO4 = FeSO4 + H2

x y56y=2x

The mass of the solubilized dry friend liquid: 50 + x-y = , x - y = solution obtained: x = grams.

y = grams. Then the purity of the iron =

Ferrous sulfate is to be removed.

The essence of the copper sulfate impurities contained in the disturbance is to remove copper ions.

Copper sulfate solution can be used to react with sufficient amount of slow iron powder to generate ferrous sulfate solution and copper, which can be filtered after full anti-filial piety, which can remove impurities and no new impurities are introduced, in line with the principle of impurity removal, and the chemical equation of the reaction.

For: Fe+CuSO4

feso4cu．

So the answer is: a sufficient amount of iron powder; Filtration; fe+cuso4feso4cu．

In fact, every step is to seek the quality score and rent.

It's very simple. Write equations in the form of a table.

S elemental. Then find the sulfuric acid.

Bird Liang couldn't read it. Anytime hi