500KVA transformer, using 3 phase 4 wires for 220V users, how much load can each phase carry

500kVA transformer, using 3-phase 4-wire for 220V users, each phase can carry 167kw.

The calculation method is:

The current per phase is i=p (, so the conformance of the energy band of each phase is p0=ui=.

A transformer is a device that uses the principle of electromagnetic induction to change the alternating voltage, and the main components are the primary coil, the secondary coil and the iron core (magnetic core). The main functions are: voltage conversion, current conversion, impedance.

Conversion, isolation, voltage regulation (magnetic saturation transformer), etc. According to the use, it can be divided into: power transformer.

and special transformers (electric furnace transformer, rectifier transformer, power frequency test transformer, voltage regulator, mine transformer, audio transformer, intermediate frequency transformer, high frequency transformer.

You look at the transformer nameplate, which has the rated current on it. Rated current*220V. It is the load (kw) of each phase energy band

First, calculate the current of each phase, according to the formula p=u*i* i=p u*current of each phase i=500kva

Each phase can carry a resistive load.

In the case of inductive loads, the power factor should also be considered.

If the power factor is yes, the load is 167kw*

The lower the power factor, the smaller the load.

It can be considered as 500kva 3, and it is reasonable to discount the calculated value by 85%.

You can go to the Internet to find Huapunuo Electronics, he has been making transformers for many years, I believe you can find the answer there.

Summary. What is the maximum power of a 400kva power transformer?

Generally, the 400 kVA transformer can band about 320 kilowatts, and the economic operation range of the general transformer is 60%-80% of the capacity, so 240 to 320 kilowatts is the most suitable, of course, the maximum power depends on the site conditions, such as cooling measures, the power factor of electrical equipment, the efficiency of the transformer, etc., which will affect the conversion efficiency of the transformer.

What is the maximum power of a 400kva power transformer?

What is the maximum power of a 400kva power transformer?Generally, the 400 kVA transformer can band about 320 kilowatts, and the economic operation range of the general transformer is 60%-80% of the capacity, so 240 to 320 kilowatts is the most suitable, of course, the maximum power depends on the site conditions, such as cooling measures, the power factor of electrical equipment, the efficiency of the transformer, etc., which will affect the conversion efficiency of the transformer.

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Summary. How many kW electrical appliances can be carried by a 4000kVA transformer, and the maximum allowable current of the line is 4000kva, and the allowable maximum apparent power of a multi-pro 4000kVA transformer is 4000kVA. If it is a three-phase 400 volt system with an output voltage, then the maximum current it allows for a load is 5774 amps.

In this case, the apparent power output of the transformer is 4000K A. If its load is an inductive load of a three-phase motor with a power factor, then its output active power is 3400kw. Hope it helps!

How many KW electrical appliances can be carried by a 4000kVA transformer, and how much is the maximum allowable current of the line.

How many kW electrical appliances can be carried by a 4000kVA transformer, and the maximum allowable current of the line is 4000kva, and the allowable maximum apparent power of a multi-pro 4000kVA transformer is 4000kVA. If it is a three-phase 400 volt system with an output voltage, then the maximum current it allows for a load is 5774 amps. In this case, the apparent power output of the transformer is 4000K A.

If its load is an inductive load of a three-phase motor with a power factor, then its output active power is 3400kw. Hope it helps!

Hello dear! Generally speaking, the load factor of the transformer is 80%, and there is an electrical appliance of 3200kva. The current of the line varies depending on the electrical appliance.

Motor triangle connection I=P (380 * efficiency * power factor)Motor star connection I = P (220 * 3 * efficiency * power factor) General electrical I=P 220 hope to help you!

What is the rated working current of 3-phase high voltage 35kv-capacity 500kva transformer?

Dear, I am glad to answer for you the 3-phase Gao He Qi defense voltage 35kv - capacity 500kva transformer rated working current is 760 amps. If the rated current is calculated according to the shortage of 2A per kilowatt, 500kVA, the current of the car is about 1000A. If the rated current is calculated according to the kilowatt, 500kVA, the current is about 750A.

So, 750-1000A can be loaded

According to your description, the output power p of a transformer with an input of 380V, an output of 220V, and a total capacity of 400KVA can be calculated using the following formula: P = S x Cos where P represents the output power of the transformer, and the unit is kilowatts (kW); s represents the capacity of the pressure swing object, measured in kilovolt amperes (kva); Cos represents the power factor, which is usually equal to 1 for purely resistive, capacitive loads. From this, the output power of the transformer is:

p = 400 (kva) x assuming a power factor of = 320 (kw) Therefore, the transformer has a maximum output of 320 kW. It is important to note that the actual output power should also be adjusted appropriately depending on the load type and power factor.

Dear, hello, I'm glad to answer for you: 320kw, because the transformer converts the voltage from 380V to 220V, the electricity is quietly buried and the voltage is reduced, but the power remains the same. Therefore, a transformer with a total capacity of 400kVA can carry the maximum power that is:

p = 400kva * = 320kw where is the power factor of the transformer, this value can usually be taken between the qi clan, here is taken as the basis calculation. In actual operation, it is also necessary to consider the power factor of the circuit, load situation and other factors, and adjust according to the actual situation.