The sum of the three numbers is 51, and the second number divided by the first number gives an incom

Solution: If the second number is x, then the first number is 2x+5, and the third number is 51-x-(2x+5).

Because the quotient of the third number is 3 and 2 when the second number is removed, there is:

x=3 [51-x-(2x+5)] +2 is turned into x=138-9x+2 solution: x=14 then 2x+5=33 51-x-(2x+5)=4 So the first number is 33, the second number is 14, and the third number is 4 even accounts in the primary school graduation exam task, and there are still 2 left to complete, please give the landlord that!

The sum of the three numbers is 51, the quotient of the second number is 2 and 5 when the first number is removed, and the quotient of the third number is 3 and 2 when the second number is removed, and these three numbers are found.

Solution: Let the first number be x, the second number be y, and the third number be z, then.

Figure 1 A: The three numbers are 33, 14, and 4

Summary. Calculation: Dividend Divisor = Quotient Dividend Divisor Quotient Quotient = 956 Dividend = 28 Quotient Dividend Quotient = 956-28 = 928 Quotient = 928 (1+28) = 32 Dividend = 928-32 = 896

In the absence of remainders, the sum of three numbers is 956, and the divisor is 28, find the quotient of the sum of the dividends.

Calculation: Dividend Divisor = Quotient Divisor Split Age Divisor Divisor Quotient = 956 Dividend = 28 Quotient Dividend Quotio Auction = 956-28 = 928 Quotient = 928 (1+28) = 32 Dividend = 928-32 = 896

The answer is that the dividend is 896 and the quotient is 32 ha.

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丨What does 1 in 10 28 mean?

It means that the dividend = divisor 28, the divisor 28 + the divisor = 928, so the divisor = 928 (1+28).

That's it. I don't understand.

is the divisor of the dividend = 928, so the divisor 28 + divisor = divisor (1 + 28) = 928

So the divisor is equal to 928 (1+28).

That's it, dear.

1.The original title is roughly correct: this number =

2.Column equation failure: Let this number stool return to x

x-3）÷6=

x-3=x-3=135

x=135+3

x=138

Summary. Hello dear, I've been waiting for a long time, I'm glad to answer for you. The two numbers are divided, the quotient is 52, the remainder is 5, the divisor is the smallest, this is the dividend is I hope mine is helpful to you

What is the quotient of two numbers is 5 and two numbers are 52 to find the dividend of these two numbers?

Hello Loose Banquet Wide Family, Jiu Xiang trembling and waiting, I am happy to answer for you. The two numbers are divided, the quotient is 52, the remainder is 5, the smallest divisor is, this is the dividend is [Chongliang 317] I hope mine is helpful to you

Can the teacher send me the teaching process?

The divisor is greater than the remainder, so the divisor is 6

The dividend is equal to the divisor quotient + remainder.

A + B = 63 to find A = A B = 6 to find B =

A is 54 and B is 9

Set the first number copy.

is x, and the second number is.

Raid, third.

The number of bai is z

From the title: x+y+z=51

y-5)÷x=2

z-2)÷y=3

where duy=2x+5 z=6x+17 is substituted into the equation zhi

Available: x+2x+5+6x+17=51

Then unravel. daox、y、z

Let the first bai number be x, and the second.

The number of dus is y, and the third one.

The zhi number is z

From the meaning of the title dao:

x+y+z=51

y-5)÷x=2

z-2)÷y=3

In y=2x+5 z=6x+17, substitute into the equation to obtain: x+2x+5+6x+17=51 and then dissolve.

out x, y, z

Let the first number of bai be x, the second number be duy, and the third number be z by the title

x+y+z=51

y-5)÷x=2

z-2)÷y=3

The daoy=2x+5 z=6x+17 substitute party can get the return trip: x+2x+5+6x+17=51 and then solve x, answer y, z

I'm also doing it、I'm from Xicheng, Beijing...

The quotient of two numbers is 52, and if both the dividend and the divisor are expanded by a factor of 3, the quotient is 52; If the dividend is enlarged by a factor of 5, the divisor should be enlarged by a factor of 5 to keep the quotient constant; If the dividend is divided by 6, to keep the quotient constant, divide the divisor by 6

So the answer is: 52, enlarged by 5 times, divided by 6

Solution: Let the third number be x

Then the second number is 3x+2

The first number is (3x+2) 2+5=6x+9

According to the question of the German equation.

x+（3x+2）+（6x+9）=51

10x+11=51

10x=51-11

10x=40

x=4so.

The second number is 3 4 + 2 = 14

The first number is 6 4 + 9 = 33

A: These three numbers are:

Let the three numbers be abc in order

Known to be available.

b/c=2…5

2*c+5=b

c/b=3…2

3*b+2=c

The two-way solution is solved.

b=。。。c=。。。

a+b+c=51

Then a=...

Do the math yourself.

Set: This number is the remainder of 5. Then x is equal to, 630 25 + 5 = 15755