Asking for a 6th grade math problem solution, in a hurry

First of all, it is clear how much distance the two cars have traveled in the process of the two encounters, that is, A and B have each walked a whole journey, and then walked a whole journey together, a total of 3 full distances. When they met for the first time, A and B walked a whole journey together. The second time they met, A and B walked two full journeys.

Assuming that the first encounter takes time, then the distance from the east station is 40x, and the distance between the east and west stations is (40+32)x, and the second encounter is 2x because A and B have walked two whole journeys, that is, A continues to walk 80x, that is, he walks to the west station and returns to the east for 8x, which is the second encounter. The second meeting point is 72x-8x=64x from the east station. According to the conditions, 64x-40x=80, then the time x=80 24, the distance between the east and west stations is (40+32)x=72*80 24=240 km.

Solution: From the meaning of the question: V A = 40km h

then v B = 32 km h

Set the distance to xkm

x+x÷(40+32)×32+80]÷40×(40+32)=3x13/360x+2)×72=3x

x=360A: The distance between the east and west stations is 360km

Look at my picture. This kind of drawing is easy to do.

I don't know how to ask again. If you don't understand anything in the future, you can ask me.

First of all, according to the title, it can be seen that selling a workbook can make a profit of 10 20 2 yuan.

Because: selling four-fifths of the exercise books can make a profit of 120 yuan.

Therefore, it can be known that if you sell all the exercise books, you can make a profit of 120 5 4 (150 yuan) and because: 1 exercise book can make a profit of 2 yuan.

So: there are a total of 120 5 4 2 150 2 75 workbooks

Solution: There are x volumes.

According to the meaning of the topic, the equation is obtained.

1+20%) 10 x 4 5-10 x=120, yield: x=-300

There is a problem with the topic.

1. There are two known conditions: defective product **=1 9, (defective product + 1) (**-1) = 3 22, 9 defective product = 1** substituting into the second formula, obtaining 22 defective product + 22 = 27 defective product -3, obtaining defective product = 5, then **=45

Sugar weight, sugar weight = 400

3.(1 6 soap number - 15 boxes) soap number = , i.e. soap number = 2 soap number - 120, soap number = 120 boxes.

4.It is known that male + female = 52, 1 4 male + 1 = 1 3 female, then 13-1 4 female + 1 = 1 3 female, 14 = 7 12 female, female = 24, male = 28.

5.It is known that slow train fast train = 5 7, that is, 7 slow train = 5 fast train, slow train mileage + 36 = fast train mileage - 36, that is, fast train mileage - slow train mileage = 72, because at the same time 7 slow train mileage = 5 fast train mileage, multiply the second formula by 5, that is, 5 fast train mileage - 5 slow train mileage = 360, then 2 slow train mileage = 360, slow train mileage traveled 180 kilometers, fast train mileage = 180 * 7 5 = 36 * 7 = 252 kilometers.

, the total number of positive and defective products is 50

2.（500-340）/（2/5)=4004.Female: (52+4) (1+4 3)=24 male; 52-24=28

1:50

4: Male 28 female 24

You don't need a system of equations, do you? The first problem is (x 10+1) (9x 10-1)=3 22 solution x=50

In the fourth question, let the male be x, then x 4+1=(52-x) 3 solves x=28

But I can solve most of them with a system of equations?

The number is 1856 100

Approximately divided into 464 25

12 7 = and 5 head point loops).

The cycle bar is 6 long

2003 divided by 6 and 5, so the same as the 5th, the gesture is 820 days to complete the work of unit 1.

30 days to complete.

So the answer is.

464 25 (or write 18 and 14 Jane 25) 12 7 = and 5 head point loops).

1.The number of students in a class who meet the physical education standard is a quarter of the number of students who do not meet the standard, and if there are two more students who meet the standard, then the number of students who meet the standard is one-third of the number of people who do not meet the standard, and the number of students in the class is the number of students.

Solution: The number of people who fail to meet the standard is x

1/4x +2) / (x-2)=1/3

x=32 There are 1+4=5 parts in the class, and those who do not meet the standard account for 4 5, so 32 (4 5)=40 people. There were 40 people in the class.

2.A ribbon, after cutting off 40 centimeters, what remains is three-fifths of the audience, how many centimeters is this ribbon originally long?

Subtract 40cm, first find the unit 1, the unit 1 is the full length, then find the full length to use division, 40 divided by its corresponding fraction, the column formula is:

40 (1-3 5) = 100 (cm).

In the second question, let the total length be x, 3 5x+40=x, and get the total length of 100 cm.

Solution: Set the person who meets the standard x does not meet the standard y

Columnable equation: x=1 4y

x+2=1 3y Solve x y x+y is the class size.

2.Columnable equations: x-40=3 5x Solve x.

If I give you 10 kilograms, we will have the same amount, then I will have 10*2=20 kilograms more than you, so my apples have 20 (1-90%)=200 kilograms, and you have 200-20=180 kilograms.

A total of 200 + 180 = 380 kg.

That's not right, my apples are already less than yours, I give you another 10 kilograms, how can it be the same?

Set my x your y

x=90%x-10=y+10

It doesn't come out that you only have someone else's in the first place, how can you give it to someone else, it's the same, he gives you almost the same question.

Solution: Let the brine with a brine rate of 8% have xg.

400*15%=x*8%

x = 750g

Water with a salt rate of 8% has 750 * (1-8%) = 690g, and there is water in the original brine 400 * (1-15%) = 340g, and 690-340 = 350g of water needs to be added

Solution: Add x grams of water.

Because the quality of the salt doesn't change, so :)

400×15%=（400+x)×8%

x = 350 A: 350 grams of water should be added to prepare brine with a brine rate of 8%.

Solution: Weight of salt = 400 15% 60 grams.

When the brine rate is 8%, the weight of the brine = 60 8% = 750 grams.

To add water = 750-400 = 350 grams.

A: Add 350 grams of water.

Solution: Add x grams of water.

400×15%=（400+x)×8%

x=350A: To add 350 grams of water.

400 (Brother 2+3) = 80

Grade 5 task: 80*2=160

Trees planted in Grade 5: 160 + 20 = Trees planted in Grade 1806: 400-180 = 220

The original major plan is:

Fifth grade: 400 2 (2+3)=160 (seeds) Sixth grade: 400 3 (2+3)=240 (trees)

5th grade: 160+20=180 (trees) 6th grade: 240-20=220 (trees)}

5-year-old Oak Laugh 400x2 (2+3)+20=400x2 5+20=160+20=180 trees.

Grade 6 400-180 220 limbs.

A: 220 trees were planted in the 6-year calendar.

2:3 is to divide 400 trees into 5 portions, each of which is 80 trees.

There are 160 potatoes in the fifth grade and 240 in the sixth grade.

In the fifth grade, 20 more trees were planted, and in the sixth grade, 20 fewer trees were planted, which is 220 trees by the end of the year.