Grade 6 Math 5

Let a and b be separated by x km, then.

x7/8=x1/8+(x-16)

x6/8=x-16

x2/8=16

x = 64 A: A and b are 64 km apart.

If you can't use x, you can also think of it like this:

At 1 8 when they met, the two traveled twice the whole way, A traveled 7 8 the whole way, and B traveled 9 8 the whole way, that is, there are two more 1 8s, A and B have the same speed, and B travels more than A is the first 16 kilometers, then 16 2 8 = 64 kilometers.

Solution: Let a and b be separated by x kilometers, then.

x7/8=x1/8+(x-16)

x6/8=x-16

x2/8=16

x = 64 A: A and b are 64 km apart.

2 x 16 km is 1+1 8 for the whole journey

The total distance is 256 9 km.

According to the title, if A starts at 16 kilometers and then the time is equal to B's, and their speed is the same, then it follows that A's distance after 16 kilometers is equal to B's total distance. Let A and B be y kilometers apart.

The columnable equation: y - 16 + 1 8y = y - 1 8y yields: y = 64 (km).

The 1 8 above does not indicate the direction, if the 1 8 is on the left, it is:

y - 16 + 7 8y = y - 1 8y gives the following result: y = 64 7 (km).

1 8 is 16 km, 16 1 8 = 128 km, and the whole journey is 128 km.

64 km with a and b separated by x km; Then the equation 9 8x-16=7 8x can be solved to obtain x=64, that is, the distance between a and b is 64 kilometers, or the road difference method 2*1 8x=16 can obtain x=64ok, if you feel that it is okay, you can use it

60 3 = 20 square centimeters.

60 4 = 15 square centimeters.

60 5 = 12 square centimeters.

94 square centimeters.

60 3 = 20 square centimeters (product of length and height).

60 4 = 15 square centimeters (width and height of the product).

60 5 = 12 square centimeters (product of length and width).

94 square centimeters (surface area of a cuboid).

From the known length * height = 20 width * height = 15 length * width = 12

So the surface area is: 20*2+15*2+12*2=94 (square centimeters).

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