Similar puzzles, similar math puzzles

order 2000x = 2001y = 2002z = k 3;

2000x²=k^3/x;

2001y²=k^3/y;

2002z²=k^3/z

x^3=k^3/2000

x=k 3rd root number 2000

y=k 3rd root number 2001

z=k 3rd root number 2002;

1 x + 1 y + 1 z = (3 times root number 2000 + 3 times root number 2001 + 3 times root number 2002) k

3rd root (2000x +2001y +2002z) k3 root [k 3 (1 x+1 y+1 z)] k3 root [(1 x+1 y+1 z)].

1/x+1/y+1/z)^3=1/x+1/y+1/z;

1/x+1/y+1/z)^2=1;

1/x+1/y+1/z=1(xyz＞0)

order 2000x = 2001y = 2002z = k 3;

2000x²=k^3/x;

2001y²=k^3/y;

2002z²=k^3/z

x^3=k^3/2000

1 x + 1 y + 1 z = (3 times root number 2000 + 3 times root number 2001 + 3 times root number 2002) k

1/x+1/y+1/z)^3=1/x+1/y+1/z;

1/x+1/y+1/z)^2=1;

1/x+1/y+1/z=1(xyz＞0)

(1) Unchanged, 45 degrees.

2) The area ratio is 1:2

APQ is similar to AEF.

Perpendicular line through A to EF, perpendicular foot is m, AME and ABE congruence or AMF and ADF congruence.

ao:am=ao:ab=1:√2

So the area ratio of APQ to AEF is 1:2

A person who only has gray Shijian Concession and has color on his body will be buried and will regret being a righteous person.

Wrong title, right? Is the front 2a+3b-2c=10?

Let a=2x, then b=3x, c=4x, Xunyuan.

Substituting 2a+3b-2c=10 obtains:

4x+9x-8x=5x=10

x=2, the ground state of the mu is a=4, b=6, c=8

Isn't there a problem with remorse? There is no c in the formula, as long as the unknowns in 2a+3b-2a=10 are rolled into the same according to the ratio, it will be good for Bibeiji, and then find the others in turn.

Observing the triangle ACD and the triangle BCE, both triangles are RT triangles, and the angle C is a common angle, so the two triangles are similar.

Therefore, ce:cd=bc:ac, and cecca=cdxcb is obtained

According to this conclusion, it can be obtained that the triangle cab is similar to the triangle cde, so de ab=ce bc=5 13

The triangle ABC is similar to the three-annihilation angle A1B1C1 and the similarity ratio is two-thirds, two-thirds is four-sixths, the triangle is similar to the shape of A1B1C1 and the triangle A2B2C2 is similar and the similarity ratio is five-quarters, the triangle ABC and the triangle A1B1C1 and the triangle A2B2C2 have a similarity ratio of 6:4:5, so the similarity ratio of the triangle ABC to the triangle A2B2C2 is 6:

5, that is, five out of six.