There is one chemistry topic in the first year of high school, and one topic in the first year of hi

Updated on educate 2024-05-07
8 answers
  1. Anonymous users2024-02-09

    Pick A, your data is wrong. It should be CO2

    The amount of 4gnaoh is.

    2naoh+ co2=== na2co3+ h2ona2co3+ co2+ h2o*****== =2nahco3mol

    Finally, the ratio of the amount of Na2CO3 to NaHCO3CO3)2- and (HCO3)- is about 1:3

  2. Anonymous users2024-02-08

    The amount that should be NAOH is.

    It can be based on the principle of conservation of elements.

    Na ions should be.

    The C element should be.

    CO3)2- is a, (HCO3)- is b, and 2a+b=,a+b=. can be concluded.

  3. Anonymous users2024-02-07

    Carbon dioxide should be for it!

    These problems are best done with the conservation of atoms. Let the amounts of carbonate and bicarbonate be x and ymol, respectively

    Conservation according to carbonaceats: x+y=; According to the conservation of sodium atom: 2x+y=4 40, and then find x and y, x=, y=, so choose a.

  4. Anonymous users2024-02-06

    hf>hi>hbr>hcl

    For some substances with similar structures, the relative molecular mass is proportional to the molecular size, so the larger the relative molecular mass, the greater the intermolecular force and the higher the boiling point.

    However, due to the strong non-metallic properties of element F, hydrogen bonds will be formed in HF, and the force of hydrogen bonds is much greater than that of van der Waals force, so HF has the highest boiling point.

  5. Anonymous users2024-02-05

    Elevated. Molecular crystals, the higher the molecular weight, the higher the boiling point.

  6. Anonymous users2024-02-04

    The boiling points of HC1, HBR and H1 increased sequentially, and the relative molecular weight of molecular crystals with similar structure increased, the higher the boiling point.

    Hf has hydrogen bonds, and its boiling point is hcl

  7. Anonymous users2024-02-03

    Na2CO3 in 20 g sample: (20*

    After complete reaction with hydrochloric acid, the volume of CO2 (standard condition) is such that the amount of Na2SO3 in the sample reacts with acid to form SO2 is:

    Since 1molNa2SO3 reacts with an acid to produce 1molSO2, there is a mass of .

    The mass fraction of Na2SO3 in the sample is:

  8. Anonymous users2024-02-02

    x could be zno al2o3 mgo

    The reason for this is that the metal element in the six metal oxides is becoming more and more active, so the metal element in X is definitely between Fe and Na, and it may be Zn Al Mg

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