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Problem description: We have three computers in our dormitory.

If you don't turn on the fluorescent lights, three computers can be turned on at the same time; If you turn on a computer, it doesn't matter if both lights are on; The strange thing is that if you turn on two or three repentant computers, you will also trip if you turn on one light (only in the dormitory), so we usually don't turn on the lights in our dormitory, and if you calculate the total power, this should not happen.

Please tapped it with high fingers and see if you can find a solution, thank you!

Analysis: At the moment when the light is turned on, especially during the flickering period of the fluorescent lamp, the current is very large and positive, but in the process of brightening, the current is very small.

The power of a computer is about 200W to 400W, if all three computers are turned on, the current is already at the limit of the protection circuit, as soon as the light is turned on, the current will trip if it is too large, you can try to change the order of opening, maybe it will be fine.

Turn on the fluorescent lamp first, then the computer monitor, and finally the main unit.

If the computer has been turned on first, you need to turn off the monitor first (don't turn off the switch directly, turn it off in the power management of Windows - that is, let the monitor standby, turn off the monitor switch directly, and the current will be too large when you turn it on again), turn on the fluorescent lamp, and then wake up the monitor.

Whether it will work or not depends on your actual situation. Try more.

The 4 ohm resistor does not form a closed circuit for code operation, the current is 0, and the voltage is 0

So the power leakage on the wire between 4 ohms and 2 ohms is 12V

2. The voltage on the ohmic resistor is 12-6=6V

The 2 ohms on the left and the remaining two resistors are in parallel, and the parallel circuit shunts the common dry liquid, which formula can know that there is no code track 4 ohm circuit on the current is.

1 a * 2 ambush (2+2+4) =

uab = 4 * =1v

Summary. Hello dear, college circuit questions:1

How do you calculate resistance in a circuit? Resistance can be calculated by Ohm's law, i.e., r=v i, where r is the resistance, v is the voltage, and i is the current. 2.

How do you calculate the capacitance in a circuit? Capacitance can be calculated by the law of capacitance, i.e., C = Q V, where C is the capacitance, Q is the charge, and V is the voltage. 3.

How do you calculate the inductance in a circuit? The inductance can be calculated by the law of inductance, i.e., l=n* *a l, where l is the inductance, n is the number of coil turns, is the permeability, a is the coil cross-sectional area, and l is the coil length.

Hello dear, college circuit questions:1How do you calculate resistance in a circuit?

The resistance can be calculated by the ohm law of the elder brother's number, i.e., r=v i, where r is the resistance, v is the voltage, and i is the current. 2.How do you calculate the capacitance in a circuit?

Capacitance can be calculated by the law of capacitance, i.e., C = Q V, where C is the capacitance, Q is the charge, and V is the voltage. 3.How do you calculate the inductance in a circuit?

The inductance can be calculated by the law of inductance, i.e., l=n* *a l, where l is the inductance, n is the number of coil turns, is the permeability, a is the coil cross-sectional area, and l is the coil length.

Related information: College circuit problems refer to the problems in the study of electric stupidity in universities, including the basic principles of circuits, the analysis and design of circuits, the experiments and applications of circuits, etc. Rotten.

Kiss, Wan Ping.

Kiss, we can't see clearly here**Oh. Can you describe it in more detail in words?

Kiss, choose A.

Kiss, choose C.

Dear, choose B.

Kiss, choose A.

Kiss, choose C.

This is not a college difficulty, it should be a high school physics ......

To understand this, you need to understand that a power supply is just a thing that converts other forms of energy into electrical energy, and it can raise the voltage at both ends or it can lower the voltage. Therefore, there is never a hard and fast rule that current must flow out of the positive electrode and into the negative electrode. The direction of the current flow depends only on the potential difference between the two ends of the wire, if the left potential is high, the current will flow in even if the right side is positive.

The specific calculation method uses Kirchhoff's law, and the actual current is of course true at all times, otherwise we would ...... what we would do if we studied physicsThe voltage source and current source are abstract models in physics problems, which exist in reality, but the internal circuit diagram is far more complex than that symbol.

Feel free to ask.

I don't know if there are any negative numbers in the current primary school curriculum.

The power supply in the circuit of the university, you can think of it as algebra in mathematics.

The positive or negative of the power supply actually represents the reference direction of the power supply. When positive, the true voltage direction is the same as the reference direction, otherwise it is the opposite. The same goes for electric currents.

In fact, it is absolutely possible to do so, and the power supply at that time (as an active resistor).