The master helps solve 6 ternary equations

1）3x-y+z=3

2x+y-3z=11

5x+4z=14

3x-y+z=3

x+y+z=12

4x+2z=15

8x+4z=30

3x=16,x=16/3,z=(15-64/3)/2=-19/6y=12-16/3+19/6=(72-32+19)/6=59/62)8x+2y-2z=24

3x+2y+z=5

5x-3z=19

3x+2y+z=5

2x-2y+10z=2

5x+11z=7

5x-3z=19

14z=-12,z=-6/7,5x=19+18/7=151/7,x=151/35

y=x+5z-1=151 35-150 35-1=-34 35z=3x-1,y=3z-4=9x-3-4=9x-72x+63x-49=3,65x=46 inverted.

x+y=3 2x-y+2z=2 x-y-z=3y=3-x,x-3+x-z=3,z=2x-62x-3+x+4x-12=2,7x=15+2=17, pour again.

x-2y-3z=-18 x+3y-2z-8=0 x+y+2z-24=0

x+y+2z=24

3y+5z=42

x+3y-2z=8

x+y+2z=24

2y+4z=16

6y+10z=84

6y+12z=48

22z=132,,z=6,,3y=42-30,y=4x=24-4-12=8

That's okay.

x=2y 2x+y+2z=1 2x-z=7z=2x-7,y=x/2

4x-14+2x+x/2=1

13x 2=15, x=30 13, halo.

y=15/13

z=60/13-7=-31/13

It's really a kung fu practice, I'm sorry

All of them only need to be eliminated, if you are too lazy to do it, then don't do it, there is no novelty.

If you can't do it, it is recommended to carefully understand the binary equation and substitute it into the elimination process to complete the problem.

I'm not typing fast, I don't have enough time right now, if you want to help, please send an email.

Let's sort it out first.

2x-3y+4m=11①

3x+2y+5m=21②

x+3y+7m=20③

Solution: +Good Bush:

3x+11m=31④

3-2, gotta talk about it:

7x+m=23⑤

Result: m=23-7x

Substituting , get:

3x+11（23-7x）=31

3x+253-77x=31

3x-77x=31-253

74x=-222

x=3 substitute x=3 into , and get:

m=23-7×3=2

Substitute x=3, m=2 into the socks to obtain:

3+3y+7×2=20

3y=20-3-14=3

y=1。

Solution: There are x people for male concealment, y for women, and (100-x-y) for children.

4x+3y+(100-x-y) 2=100, simplified 7x+5y=100

Because x and y are integers.

5y=100-7x

1) When x=5, y=13

2) When x=10, y=6

Answer: The first division of the hall is 4 * 5 = 20 loaves for men, 3 * 13 = 39 loaves for women, and (100-5-13) 2 = 41 loaves for children

The second division is 4*10=40 loaves for men, 3*6=18 loaves for females, and 2=42 loaves for children (100-10-6).

The parties are numbered in the order in which they are written. (1) x+y+z=26, y-z=1, x+2y-z=18(1)+(2):

x+2y=27.Substituting x+2y=27 into (3) obtains: z=9

Substituting z=9 into the matching stool (2) yields y=10Substituting y=10, z=9 into (wide socks 1) obtains: x=7

Therefore, the solution of the original system of equations is: x=7, y=10, z=9(2) 4y+3z=7,3x+2z+17,9x-7y=17

1)*2+(3)-(2)*3: y=-20Substituting y=-20 into (1) yields:

z=29.Then substitute y=-20 into (3) to obtain: x=-41 3

Therefore, the solution of the original equation is: x=-41 3, y=-20, z=29(3) x-7y+3z=17, 5x-6y-z=24, 3x+7y-2z=1

1) + (2) * 3 gets: 16x-25y=89[(1)+(2)+(3)] 3 get:

3x-2y=14.The solution of the binary system of linear equations: 16x-25y=89, 3x-2y=14, gets:

x=4,y=-1.Substituting x=4, y=-1 into (2) yields: z=2

Therefore, the solution of the original system of equations is: x=4, y=-1, z=2(4) 2x+4y+3z=9,3x-2y+5z=11,5x-6y+7z=13

1) + (2) * 2 gets: 8x+13y=31[(2)*3-(3)] 4, get:

x+2z=5.The solution of the binary system of linear equations: 8x+13y=31, x+2z=5, gets:

x=-1,z=3.Substituting x=-1, z=3 into (1) Peiqiao Travel: y=1 2

Therefore, the solution of the original system of equations is: x=-1, y=1 2, z=3

1/x+2/y+1/z= -1(1)

2/x - 4/y - 9/z= -1(2)4/x+6/y - 9/z=2 (3)

4/x-2/z=-3(4)

2/x+2/y=-3(5)

2/x+13/z=-6(6)

2/z-26/z=-2+12=10

28/z=10

z=-14/5

4/x-2/(-14/5)=-3

4/x+5/7=-3

4/x=-26/7

x=-14/13

Bring x=-14 13 into (5) to find y

In addition, you can convert 1 x, 1 y, 1 z to abc, which should be relatively simple, you can try it yourself.

x+y+z=30 （1）

2*50x=80y （2）

3*50x=80z （3）

From (2): y=5 4x

From (3): z=15 8x

Substitute y=5 4x, z=15 8x into (1):

x+5/4x+15/8x=30

Solution x=80 11

y=5/4x=5/4*80/11=100/11z=15/8x=15/8*80/11=150/11

From 2*50x=80y 3*50x=80z, we get: y=5 4x, z=15x 8Substituting x+y+z=30 yields: x+5 4x+15x 8=30

The solution is x=80 11 y=5 4x=100 11 z=15x 8=150 11

From 2*50x=80yyy=x*5 4 from 3*50x=80z, z=x*15 8

Substituting x+y+z=30 respectively, x+x*5 4+ x*15 8=30 is obtained, and the solution is x=80 11, y=100 11, z=150 11

1 All a+2b = 13

As long as you meet this equation, you can algebra as you like.

a=1,b=6,c=-18……

There are only two equations in a ternary equation that can only be related, and the solution of each element cannot be calculated.

①3x+4z=7

2x+3y+z=9

5x-9y+7z=8

Multiply both sides of the equation by 3 and add y to the equation to get 11x+10z=35 2-5 to get 7x=35 x=5

Bring x=5 in to get 15+4z=7 4z=-8 z=-2 and x=5,z=-2 to get 10+3y-2=9 3y=1 y=1 3 and this is the end of x=5,y=1 3,z=-2