Do superconducting motors still consume electrical energy

Yes. Alternating current can also pass through the coil, but the inductance of the coil has a hindrance effect on the alternating current, and this obstacle is called inductive reactance. The more difficult it is for the alternating current to pass through the coil, the greater the inductance and the greater the obstruction effect of the inductor; The frequency of alternating current is high, and it is difficult to pass through the coil, and the inductor has a large obstruction effect.

Experiments have shown that the inductive reactance is directly proportional to the inductance and the frequency. If the inductive reactance is denoted by XL (L is the subscript), the inductance is denoted by L, and the frequency is denoted by F, then.

xl＝ 2πfl

The unit of inductive reactance is ohm. Knowing the frequency f of the alternating current and the inductance l of the coil, the inductive reactance can be calculated using the above formula.

When f, the inductance is equivalent to an open circuit. For direct current, the frequency f=0, so the inductive reactance is equal to 0, so in the DC circuit, the inductive element is equivalent to a short circuit.

Consumption Superconductivity means that the resistance disappears, and the heat loss is gone, but the mechanical energy of the workmanship consumes electrical energy.

Consumes less electrical energy and outputs more power. The efficiency is much higher than that of ordinary motors.

Theoretically not consumed.

But it must be done in an ideal space (low temperature).

It should consume power, at least it does its work.

Look, none of them can make a complete explanation based on scientific evidence, it's all! The so-called superconductor reaches zero resistance in a specific environment (i.e., ultra-low temperature), that is, no resistance. A safety circuit consists of a power supply, a conductor, and a resistor (i.e., a load).

If there is no resistance, if there is no resistance, like a short circuit, it will destroy the power supply, who can explain it?

Basically agree with 403525951 that superconductivity does not mean that the resistance disappears, but is so small that it is almost negligible. When comparing superconducting materials, there are also resistance levels.

If the city is a constant current, of course does not consume electricity. If the current is not constant, such as alternating current, changing the current will produce a magnetic field, which in turn will produce an electric field, and so on, generating electromagnetic waves. Electromagnetic waves have energy.

In other words, if the current is changed, there is a loss of electrical energy.

Superconductivity means that the resistance is 0, which avoids the loss caused by the resistance, but does not exclude the loss due to reactance.

First of all, it is important to understand that alternating currents have different properties from direct currents. Direct current can flow through the inductor coil, but the AC is hindered by the inductance coil.

The higher the AC frequency, the greater the obstruction. DC cannot pass through capacitors. But AC can pass through capacitors.

The higher the AC frequency, the less obstruction the capacitor and the easier it is for the AC to pass through. In AC transmission, reactance (i.e., the inductance and capacitance obstruction) causes greater losses than resistance. This is because the wire frame is in the air, forming a capacitance with the earth, and the AC can pass through the capacitor, so a part of the electrical energy runs into the earth and is lost.

The wire is self-inductive, which is equivalent to the inductance coil, and the communication will be hindered by the inductance coil, and part of the electrical energy will be lost.

Knowing this, you can understand that superconductivity avoids losses due to resistance, but does not exclude losses due to reactance.

Even if it itself has no resistance, it is bound to generate a magnetic field, through which some energy is lost.

Since it is called superconductivity, it can be used without losing electricity.

Today's superconductivity has not yet reached that point, it is just a reduction in resistance.

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No, superconductors are completely diamagnetic, and magnetic inductance lines do not enter the superconductor. In fact, the most popular way to demonstrate the properties of superconductors today is to use this principle. Put a magnet under the superconductor, before the superconducting temperature is reached, the magnetic inductance line passes through the superconductor, and when the superconducting temperature is reached, it becomes a completely diamagnetic, thereby generating an induced current, and the magnetic force makes the superconductor float.

Of course.

Transmission also compounds the law of conservation of energy.

Regardless of the energy loss of buck-boost transformers, busbars, various switches and other related equipment, the total power transmitted from the perspective of line energy conduction q = wire loss of electric energy (mainly for wire heating) + available electric energy.

The wire heat loss electric energy = i square RT, which is related to the current and wire resistance and time, then the resistance of the superconductor is very small, which can greatly reduce the heat generated, so it means that the power loss is reduced.

Superconducting generators make high-capacity generators, and the key components are coils and magnets. Due to the resistance of the wire, the coil is severely heated, and how to cool the coil becomes a problem. If a superconducting generator is made of superconducting material, the coil is wound with a non-resistive superconducting material, which does not heat up at all, solves the cooling problem, and reduces power loss by up to 50%.

If superconductivity can be achieved at room temperature, it can reduce the loss of electrical energy transmission. But now it's too expensive to create a superconducting condition.

Of course it works.

Saving the loss of power in the transmission composition.

Connecting the positive and negative poles is a short circuit, and the battery is short-circuited and does not consume electricity? Does the neutralization of positive and negative charges not consume electricity?

So what do you think consumes electricity?

The ideal application for superconductors is as a cable strip in urban commercial power transmission systems. However, due to the high cost and the difficulty of the cooling system to meet the existing requirements, it could not be put into practical use, but some sites have already been put into trial operation. In May 2001, about 150,000 inhabitants of Copenhagen, the capital of Denmark, were connected to domestic electricity powered by superconducting materials.

In the summer of 2001, Pirelli completed three 400-foot-long high-temperature superconducting cables capable of delivering 100 million watts of electricity for an energy subdivision in Detroit. It is also the first commercial cable in the United States to deliver electrical energy to users through superconducting materials. In July 2006, Sumitomo Corporation Electronics, with the support of the U.S. Department of Energy and the New York Energy Research and Development Council, conducted a teacher training project in which the superconducting Di-BSCCO cable was put into operation for the first time.

So far, the cable has been powering 70,000 homes without any problems.

Superconducting materials can also be used in superconducting DC motors, transformers, and magnetofluid generators, where they will significantly improve energy efficiency and significantly reduce weight and volume. In addition, superconducting computers, superconducting energy storage coils, nuclear magnetic resonance imaging, superconducting quantum interferometers (squid), switching devices, high-performance filters, military superconducting nano-microwave antennas, electronic bombs, superconducting X-ray detectors, superconducting light detectors, and 160 GHz superconducting digital routers are all very attractive applications.

If superconductors can be used in practice, they will reduce transmission losses, improve efficiency, and bring many other benefits to mankind.

At present, superconductors are only used in scientific experiments and high-tech applications, because the superconducting critical temperature of general metals or alloys is low.

The ability of superconductors to work at room temperature is a greater breakthrough in superconducting technology, which can significantly reduce the transmission loss of the distribution system and save a lot of power.

When an electric motor is working, electrical energy is converted into mechanical energy (and inevitably thermal energy) In fact, energized straight wires are subjected to ampere force in a magnetic field, which is how electric motors work. And the ampere force is actually a macro manifestation of the Lorentz force (it's all nouns, just ignore it).

As for the changes in the circuit, there is also the issue of back EMF, so let's not talk about it. If you care, I'll come back and talk about it

It should be said that there is a problem with the question you asked, when electrical energy is consumed, the electrical energy is converted into mechanical energy, and it changes like this.

The electric motor has internal resistance, which will consume some electrical energy, but most of the electrical energy is converted into mechanized energy.

At the moment when the motor starts, the current is very large, and the voltage drop of the line is also very large.