For the calculation of computer network construction and maintenance, please help! Thank you

Question: Your IP is: This is the IP of class C, and the default mask:

The last segment is the host number, and now you have to divide 6 subnets, which is to take the first 3 bits in the host bit to make the network number, so there are: 11100000 (the last segment is the host number), so there are 8 subnets, and 2 can't be all 0 and all 1 of the other subnets

The host number also does not have all 0s and all 1s, so each subnet has 30 hosts, and finally a new mask.

Question 2: It doesn't make sense from the title: if you insist on drawing, you can only use all 0 and all 1 of the subnet:

Now you want to divide 4 subnets, that is, in the host bits, take the first 2 digits to make the network number, so there are: 11000000 now becomes a subnet, and the host number is also not all 0, all 1, so each subnet has 62 hosts; Finally a new mask.

1) 1. Decimal representation of IP address.

2. The subnet mask is.

b) Because it is a Class C address, the standard subnet mask is.

So the number of host bits + the number of subnet bits = 8

If each department is separated (4 departments), 2n(n power of 2)-2>=4 (4 means 4 departments, one subnet for each department), 2(8-n)(8-n power of 2)-2 =60, n represents the number of subnet bits, and the result n is not solved. The first equation -2 is because the subnet number cannot be all 0 and all 1. So the second question is unsolvable.

There is a solution to the second question.

4 departments and 4 network segments, each network segment 50 60 hosts can choose each block 64 segments:

The broadcast addresses are ., in order

It is recommended that you use the "Subnet Mask Calculator" to calculate.

1. Multiple choice questions.

2. True/False Questions (Why are they also multiple-choice questions?) ）

If there are no more than 15 computers in each subnet, then the host bit is 5 bits and the mask is 0000, that is.

The 4 subnets are:

Available IP address ranges from broadcast addresses.

Available IP address ranges from broadcast addresses.

Available IP address ranges from broadcast addresses.

Available IP address ranges from broadcast addresses.

Judging as a Class C IP, according to the number of subnet hosts, it can be concluded that the n-power of 2 -2>15 (n is the host bit) needs to be greater than or equal to 5, that is, the network bit borrows up to 3 bits and is a 27-bit subnet mask.

If you borrow 3-bit network bits, you can divide 2 to the 3rd power = 8 subnets, and the increment of the subnet is 2 to the 5th power = 32 (the host bit is 5), which meets the requirements of the problem. So.

You can select any 4 subnets.