High School Biology Dwarf Analyze it, right?

First of all, you have to be clear:

1) From the perspective of energy**, 2870kj of energy can be released for every 1mol of glucose decomposed by aerobic respiration. Anaerobic respiration, on the other hand, breaks down 1mol of glucose, which can only release energy. (Anaerobic respiration is not completely decomposed, part of the energy is stored in alcohol or lactic acid, only of which energy is stored in ATP, and nearly 69% of the energy is lost in the form of heat).

2) Total reaction formula of aerobic respiration: C6H12O6 + 6H2O + 6O2 enzyme 6CO2 + 12H2O + a lot of energy.

3) Anaerobic respiration of the human body: lactic acid fermentation: C6H12O6 enzyme 2C3H6O3 + a small amount of energy.

Then you have to understand the diagram, the energy of running 50 in 1500m is powered by aerobic respiration, and 50 is supplied by anaerobic respiration, therefore, option B, anaerobic respiration consumes much more glucose than aerobic respiration; Option D, the marathon is almost entirely powered by aerobic respiration, with a 1:1 ratio of CO2 to O2. (In fact, anaerobic respiration consumes neither O2 nor CO2, so the ratio of CO2 to O2 for other types of running is also 1:.)

1) Hopefully).

Anaerobic respiration The rate of aerobic respiration should be the amount of carbon dioxide produced.

Then at 1500 meters, the rate is the same, and the ratio of sugars consumed is 3:1

d, the marathon is basically aerobic breathing, so it is about 1:1

A: The longer the distance, the greater the proportion of aerobic respiration energy supply.

B: At 1500, aerobic respiration and anaerobic respiration provide the same energy, but consume the same glucose, and anaerobic respiration produces less energy, so anaerobic respiration consumes more glucose (1mol glucose aerobic respiration releases 2870kj of energy, while anaerobic respiration only ji).

C: 100 meters is mainly anaerobic respiration.

D: When running a marathon, it is mainly aerobic respiration, and anaerobic respiration is basically negligible, so CO2:O2 is about 1:1

Hello, glad to answer for you!

Personally, I think the answer is wrong, and I choose A correctly. The disease is recessive in both parents of normal offspring of both males and females. There is a daughter who is sick, but the father is normal, and it is autosomal inheritance.

I checked the answer to the original question for you, and it was indeed A

If you need a detailed explanation, please ask, you will be happy if you have heard it.

Plus, Happy New Year!

The answer is b

1. Because families with normal parents still have children with high myopia, recessive inheritance can be ruled out;

2. In families where the mother has unilateral high myopia and both parents have high myopia, the proportion of myopia in daughters is basically higher than that of boys, and when the mother's vision is normal, the proportion of daughters with myopia is less than or equal to that of boys. So it can be seen that it is the X chromosome dominant inheritance.

This individual is tetraploid and produces twice as many gametes as normal A or A because the number of gametes is a set of homologous chromosomes divided by 2, and AAAA represents a set of homologous chromosomes. In fact, it obeys the law of segregation because there is only 1 trait. Due to the different proportions of gametes produced, the proportion of offspring produced with the diploid trait will look a little different, but they are essentially the same, they are all gametes freely combined.

The middle coefficient is 16, and it should be 16aaaa!

First of all, because it is inbred, it produces the number of gametes. The gametes are all the same. See the first row and the first column for details. Then multiply the rows and columns and write them in the corresponding grid.

Tetraploid aaaaa is self-bred, and they produce three kinds of gametes in the ratio: 1aa:4aa:

1aa.This is according to the law of permutation and combination, if not, first number aaaa in order as 1234, and then take two of the four, there can be 6 combinations: 12, 13, 14, 23, 24, 34, and finally replace the serial number with the gene symbol should be the above type of proportion.

Next, press the checkerboard ** to complete it, beginners give it a try, it's very useful.

Cells synthesize and transport secreted proteins:

First, ribosomes on the surface of the rough endoplasmic reticulum synthesize proteins, enter the endoplasmic reticulum for glycosylation, then enter the Golgi apparatus for processing, and then excrete them outside the cell.

After the endoplasmic reticulum and the Golgi apparatus, they all bud and form spores, or vesicles, which do not cross the membrane.

I hope it can help you, and if you still have any questions, just ask me!

Why layer 0, the answer is not right.

I choose B, where A is the legacy of the previous year, not the total energy inflow per year, where N1 is greater than N2 and W1 is greater than W2

c b and d can represent the energy used by the decomposer and the energy that is not utilized, respectively, and d is similar to c.

b, excluding a, because a is the previous year.

To select a haploid, it must be manually doubled in order to have the ability to reproduce. Because haploids cannot produce gametes.

Artificial doubling makes the alleles homozygous, so that the inbred offspring of such plants do not have trait separation.

b；There is no indication of manual doubling.

c；Two haploids cannot be hybridized.

d；Mistake.

Homozygous is obtained directly, without multi-generational culture.

1. This experiment proves that Darwin said that "the signal generated by the tip is unevenly distributed in the elongation zone, resulting in bending growth".

Darwin's experiment was carried out under one-sided light, and the Bayer experiment proved that Darwin was correct when he said that the direct cause of the curved growth was indeed "the uneven distribution of the signal generated by the tip in the elongation zone", and that the one-sided light was only an indirect factor. So choose A

2. Due to the different sensitivities of different organs of plants to auxin, point e only has no effect on the organs shown in the figure, but not necessarily on the whole plant. Therefore, item c is incorrect. The ground growth of horizontal plant roots is due to the high concentration of auxin near the ground, which inhibits growth, and the CF segment illustrates the function of auxin to inhibit growth.

。From the information in the title, it can be seen that the total amount of organic matter decomposed has been increasing as the temperature rises to 40°, indicating that the enzyme is active, but the total amount remains unchanged at 40-80°, indicating that the enzyme has lost its activity. Reducing the inactive enzyme from 80 to 0 did not work, so the relationship is flat.

It can also be automatically decomposed by heating without adding enzymes, and cannot be used for the effect of temperature on enzyme activity; Due to the bell-shaped curve of enzyme activity, the activity of the enzyme may be the same at different temperatures; The mechanism by which enzymes increase the rate of reaction is that they can reduce the activation energy of the reaction, rather than increase it.