Please help my daughter solve two 6th grade application questions, thank you

Solution: Let this batch of parts be x.

Equation idea: A's daily workload - B's daily workload = 50A's daily workload: x*(

B per day: (x 2 + 54) 6

Column: x*( x 2 + 54) 6 = 50 solution: Let B take x hours to reach place a.

Equation idea: the velocity of A + the velocity of B = the sum of the velocity of A and B.

The sum of the speed of A and B: Let the distance between ab be in units of 1. Because A and B meet for 6 hours, so.

The sum of the speeds of A and B is 1 6

The speed of A: Because looking at A alone, it takes 6+4=10 hours from A to B, so the speed of A is 1 10

B's speed: Looking at B alone, the shared time from B to A: 10 + x hours.

So B's velocity is 1 (10+x).

Column: 1 10 + 1 (10+x) = 1 6

The following * sign represents the multiplier sign.

1.Let's make a total of x parts in this batch.

Just solve x.

2.It will take B another 9 hours to reach place A.

A takes 10 hours to complete the ab distance, set the speed of A as A, then the ab distance is 10a, and then set the speed of B as b

This relationship is obtained: 6a+6b=10a Note: When A and B meet, 6a+6b is the distance between ab and b=2 3a

Because B's remaining distance = A's previous journey, i.e., 6a, 6a (2, 3a) can be concluded.

Total*(

Total 656.

2.B's 6-hour walk is equal to A's 4 hours, so A's speed is twice that of B, so A's walk for 6 hours and B's need to walk for 6 hours.

If the difficulty of drawing is high, it will be exempted.

a (white) = b (black) that is.

a (black) = b (white).

c (white) = "1" times 2 5 = 2 5

I hope that everyone will encourage and encourage to vote for it

Divide a bunch of oranges among several children, if each person divides 3, then there are 8 more oranges, if each person divides 5, then the last person gets no less than 3 oranges, ask how many children, how many oranges?

Solution: If there are A children, then there are 3A+8 oranges.

According to the title. 5≥3a+8-5（a-1）≥3

5≥3a+8-5a+5≥3

8≥-2a≥-10

4 a 5a = 4 or 5

So there are 4 or 5 children.

Then there are 20 or 23 oranges.

If you haven't learned about inequalities, you can do so.

The last person gets no less than 3 oranges, that is, 3, 4, 5 oranges.

When you get 3.

3a+8-5（a-1）=3

2a+13=3

a=5 when 4 are obtained.

3a+8-5（a-1）=4

2a+13=4

a=9 2 (off-topic.)

When 5 are obtained.

3a+8-5（a-1）=5

2a+13=5

a=4 or so, let the last child get b.

3a+8-5（a-1）=b

b=13-2a

a=（13-b）/2

b = 3, 4, 5 are substituted separately, and only when b = 3 and 5 a has a positive integer solution.

There are x children. Not less than three, but not more than five, so, if each person divides five, then the last person gets three or four oranges.

Equations can be listed according to the title:

3x+8=5(x-1)+4 (if there are four) solves: x=

But there can't be half a person, so if each person is divided into five, then the last person can only get three oranges.

Equations can be listed according to the title:

3x+8=5（x-1)+3

Solution: x=4

Then, oranges have 3x+8=5 (pcs).

Elementary school students' application methods are used to solve application problems, and students are not yet able to list equations to solve application problems.

From the original 3 per person to 5 per person, each person has increased by 2, and the original 8 more can be divided into 8 2 = 4 people, so the child should have 4 + 1 = 5 or 4 people, and the orange should have 3 * 5 + 8 = 23 or 3 * 4 + 8 = 20.

There are x children with y oranges.

y-3x=8 y-5（x-1）>=3

Simultaneous equations are fine, and there may be a couple of possibilities, which I didn't calculate.

1. Hydrogen accounts for 1 9, oxygen accounts for 8 9, and multiply by the weight of hydrogen and oxygen respectively.

2. If the length, width and height are 5x, 4x and 3x respectively, then 5x+4x+3x=48 obtains x=4, then the volume = 5*2*4*2*3*2

3. The total number of ducks is 45 * 5 9 = 25, then the duck is 3 5 * 25 = 15, and the child is 2 5 * 25 = 10

4. Set 8x for science books and 5x for storybooks, then 8x-5x=90, calculate x=30, 240 for science and technology, and 150 for storybooks

5. The speed of vehicle A is 5x, the speed of vehicle B is 4x, then (5x+4x)*3=270, and the speed of vehicle A is calculated to be 50, and the speed of vehicle B is 40

(1) Let this digit be x, then there is.

x×（1+x=10/3

2) Let A and B be 2s kilometers apart.

then s-30=(s+30) (3 5).

Solution s=120

A and B are 240 km apart.

The sum of the eldest and the second is 2+1=3 times that of the second.

The third child picked at least 6, and no more than 11.

46 minus the third, and the rest should be divisible by 3.

1) The third child picked 7.

The second picked: (46-7) 3=13.

The boss picked: 13 2 = 26.

2) The third child picked 10.

The second picked (46-10) 3=12.

The boss picked 12 2 = 24.

Suppose the boss picks 2x the second and the third (y is greater than 5), and there are two possibilities: y=7, so x=13

The second picked: (46-7) 3=13.

The boss picked: 13 2 = 26.

y=10 x=12

The second picked (46-10) 3=12.

The boss picked 12 2 = 24.

The eldest is 26.

The second 13.

There are 7 of the third. Total 26 + 13 + 7 = 46.

There are 26 bosses, 13 seconds, and 7 thirds.