Ask two questions from a 6th grade math book

You're in the sixth grade, and like me, I've done both of these questions, and we've learned the interest of percentages (1/3 + 1/2) 1/3 1 and 1/5 = 2/5 = 40% 1 5/6 1/2 1 1 and 1/5 = 3/5 = 60% 1 and 1/5

500 (pages).

1. A completes 1 3 per day, and B completes 1 2 per day, and cooperation is required.

1 (1 2+1 3) = 6 5 days completed.

A completes 1 3 * 6 5 * 100% = 2 5 * 100% = 40%.

B completes 1-40% = 60%.

120%-1) = 150 copies sold on the first day.

A total of 150 30% = 500 copies.

Or, set up a total of x copies.

x = 500

1. According to the topic, this work is 1, A does 1 3 every day, and B does 1 2 every day.

Then: (1) It takes 1 (1 3 + 1 2) = 6 5 days to complete the cooperation between two people.

2) When finished, A made 1 3*6 5=2 5 and B made 1 2*6 5=3 5.

That is, A did 2 5 and B did 3 5.

2. Suppose there are x number of storybooks.

Column equation: x*30%*120% = x*30%+30 (number of books sold on the next day).

Solve x=500 copies.

That's a total of 500 books.

A completes 1 3 of the work every day, and B completes the work 1 2 of the day, so the cooperation completes the work of 1 3 + 1 2 = 5 6 per day, and it takes 1 (5 6) = days in total.

When the work is completed, it is clear that A has completed the work: (1 3) (1 3+1 2) = 2 5, and B has completed the work 1-2 5 = 3 5.

On the first day x book, on the second day of the book, there is: , x=150So there are 150 copies.

A day's workload is a, then the workload of this piece is 3a, B's day's workload is b, then the workload of this piece is 2b, and 3a=2b, get a=2 3b

This work takes 3a (a+b) days, substituting a=2 3b to get the day, about one and a half days to complete.

Let the total amount be x, sell 30% x books on the first day, and sell 120%*30%x books on the second day, and the following equation is obtained according to the conditions:

120%*30%x-30%x=30, find x=500.