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The two above level 10 were human-translated.

From home to work.

Ken is a half-hour train ride.

15 minutes by bus.

and a 10-minute walk. The average speed of a train is known to be a kilometer per hour.

The average speed of the buses is B kilometers per hour.

and his average walking speed is c kilometers per hour. a) Find out the length of the distance traveled by each of the different means of transport. b) Find out the length of the walk from Ken's home to the company.

Answer: [Distance = Speed High Bridge Lead x Time] a) Train speed = a kilometer per hour.

Time taken by train = hours so.

Distance traveled by train = km Bus speed = b km per hour.

Time taken by bus = hours so.

Distance traveled by bus = km Walking speed = c km per hour.

Time to take the bus = hours So.

Distance traveled = km b) Total length of distance traveled from Ken's home to the company = km.

If q and r are positive, what percent of (q+1) is equal to r?

Answer: r (q+1).

Solution: When two cars meet, use 60 (75-60)=4 (hours).

The distance between the two cities is 4*(75+60)=540 (km).

A: The two cities are 540 kilometers apart.

Meeting time: 60 (75-60) 60 15 4 hours.

Distance: (75+60)x4=135x4=440 km.

Set the time to t

75t-60t=60

t=4s=75t+60t=540

The distance is 540 km.

(20 4)2=cm)).

Answer: Its height is centimeters.

Tons) A: It can load 65 tons of coal.

1.Square side length = 20 4 = 5 meters.

Height = 24 5 5 = meters.

2.Total volume = 10 10 cubic meters.

Mass=500 tons.

1.The area of the ground is 5*5=25 square meters.

24 cubic meters 25 square meters = 24 25 meters.

2.One carriage can hold 10*65t

The maximum volume that can be sawn is a cube with a variable length of 2dm, v=2*2*2=8, and the volume of this cuboid is 64, so 64 8=8, choose c

The greatest common factor is 2

Then 8 2 = 4 and 4 2 = 2

4 2 1 = 8.

C is 8 km away from B, X and Y are departing from C at the same time, but X is going towards B. They return as soon as they arrive at their destination. The speed of y is 2 times that of x. When X arrives at D, X and Y are 1km apart. Q: How far is Y from B?

Hope satisfied.

C is 8 km away from B, X and Y depart from C at the same time, X arrives at the destination and returns, X is twice as fast as Y, and when X arrives, Y is still 1 km away from B, and asks how far Y is from B at that time (exhausted......）

There is an unknown x

x=108-（2/5+1）x

Find the raw data x.

Literal translation: When 2 5 of a number (hypothetical x) is added to this number, and then this sum is subtracted by 108, the result is still this raw data x.

What is this number.

Answer: 45

When a certain number of 2/5 of the amount is added and the money is subtracted from 108, the result is the original number. What was the original number? Because I don't know the original text, I modified it to aim for smoothness, and you can ask questions if you have any questions.