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The heat engine, working once, is divided into four strokes: suction stroke, compression stroke, work stroke, exhaust stroke.
Among them, only the power stroke does the work externally, and the rest relies on the inertia of the work stroke.
The efficiency of the heat engine is not much different from the efficiency algorithm of the pulley block. It is also a useful total work.
The useful work of the heat engine, such as the car, is the distance traveled by the car (I have done a lot of questions, and it seems that I can only ask the car).
The total work is the fuel, which completely burns the heat released.
That is, the calorific value * the quality of the fuel.
ps: At present, the mechanical efficiency of gasoline engines is about 25%-35% There is no extra high diesel engine is slightly higher.
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One work cycle, one work on the outside!
Heat engine power = w useful q amp.
w useful = f (traction) s (distance).
q discharge (heat emitted by complete combustion of fuel) = qm
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Do one work in one work cycle.
The heat emitted by the complete combustion of the consumed fuel is the "total work" Q amp = qm The work done by the car to overcome the resistance of the movement or the work done by moving the distance under the action of traction force is the useful work w=fs=w q
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For a four-stroke internal combustion engine, work is done only once in one duty cycle. p=w/t
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Traction. x
Speed x Time = Energy Consumed = Combustion Value of Gasoline x Mass of Gasoline x Heat Engine Efficiency. So.
xv (velocity).
x3600 (1 hour 3600 seconds) =
It can be concluded that v=
Meter seconds.
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It's going to be a high school entrance examination, and ask this kind of simple question, in a word, I'm not familiar with the textbooks at all, the high school entrance examination is not a selection exam, most of them are basic knowledge, I suggest you, look at the textbooks.
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The question of heat engine efficiency completely confuses you.
Who said that "absorbed heat equals useful work"?
Definition of heat engine efficiency: In the heat engine, the ratio of the part of energy e used to do useful work to the total energy e total released when the fuel is completely burned is called the efficiency of the heat engine.
i.e. =e has e total (usually in percentages).
See image below: <>
The leftmost text: The energy e1 emitted by the complete combustion of fuel This is the total e in the formula.
What is the total energy used for? That's what the four arrows in the diagram say. Only part of it is used for the work (e4 in the figure), and the rest is lost (indicated by the three arrows in the middle of the figure), which is the extra work that has to be done.
According to this diagram, the efficiency of the heat engine can be expressed as =e4 e1.
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The formula for heat engine efficiency: =q has q total 100%.
It refers to the ratio of the heat converted into mechanical work in the working part of the heat engine and the heat obtained by the working fluid from the heater. If denoted by t, there is t=w q1=( q1-q2) q1=1- q2 q1
If you have any questions, please feel free to ask.
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Answer: Heat engine efficiency = w q
wActive work: The part of energy that is converted into mechanical energy in the heat engine.
w=fs f traction force s the distance of the heat engine movement.
Q The heat emitted by the combustion of fuel.
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w has q put 100 f pull s distance q put 100 : divided by f pull: traction.
S-distance: The distance traveled.
Q Release: The heat that is released.
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Useful work, that is, mechanical slippery energy.
The total work is the energy that is generated by the ignition of this burning.
Useful and swift work: q = cm t = fifth power. Efficiency =
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D. Test question analysis: The efficiency of the heat engine refers to the ratio of the energy used by the heat engine to do useful work to the energy produced by the complete combustion of the fuel; The efficiency of the heat engine is high, and it is said that the energy used by the heat engine to do useful work has a high ratio of the energy produced by the complete combustion of the fuel, not that the more useful work, the greater the mechanical efficiency, a is wrong; Power is a physical quantity that indicates how fast or slow an object does work, and the efficiency of the heat engine refers to the ratio of the energy used by the heat engine to do useful work to the energy produced by the complete combustion of the fuel.
Comments: The key to solving this problem is to be familiar with the difference between power and mechanical efficiency: the efficiency of the heat engine refers to the ratio of the energy used by the heat engine to do useful work and the energy produced by the complete combustion of the fuel; Power is a physical quantity that indicates how fast or slow an object does work.
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One work cycle, one work on the outside!
Heat engine power = w useful q amp.
w useful = f (traction) s (distance).
q discharge (heat emitted by complete combustion of fuel) = qm
-
Do one work in one work cycle.
The heat emitted by the complete combustion of the consumed fuel is the "total work" Q amp = qm The work done by the car to overcome the resistance of the movement or the work done by moving the distance under the action of traction force is the useful work w=fs=w q
-
Traction. x
Speed x Time = Energy Consumed = Combustion Value of Gasoline x Mass of Gasoline x Heat Engine Efficiency. So.
xv (velocity).
x3600 (1 hour 3600 seconds) =
It can be concluded that v=
Meter seconds.
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