Remove CO2 and introduce a small amount of HCl into the Na2CO3 solution

Of course not.

Although HCl is easily soluble in water, it can also react with Na2CO3.

But don't forget that CO2 can also continue to react with Na2CO3.

co2+na2co3=2nahco3

You don't know that.

Can CO2 still be washed out in that case?

I recommend using a saturated baking soda solution.

It's NaHCO3, so that carbon dioxide can't react with it.

HCl, on the other hand, can be washed out.

What comes out of this is pure carbon dioxide gas.

The best way to remove the small amount of HCl gas contained in CO2 is to pass a gas mixture into NaHCO3 (saturated baking soda solution scrubbing gas).

Because there is a reaction as follows: CO2 + Na2CO3 + H2O = 2NaHCO3

While both sodium carbonate and sodium bicarbonate can absorb hydrochloric acid, sodium carbonate reacts with carbon dioxide to form sodium bicarbonate, which only reacts with hydrochloric acid.

The principle of removing impurities:

1) No increase: no new impurities are added.

2) No reduction: The purified substance cannot be reduced.

3) Easy to separate: easy to operate and easy to separate.

The gas produced after the reaction is carbon dioxide, which is not impurities, and the other product, sodium chloride, is soluble in water and not a gas, so it can be removed.

When introduced into a saturated sodium bicarbonate solution, sodium carbonate will not work and will continue to react with carbon dioxide.

No way. CO2 is also easily soluble in water with Na2CO3 to form NaHCO3

Na2CO3 solution will absorb CO2 and form NaHCO3, so it is better to use NaHCO3 to remove impurities. Complete.

I don't know, maybe NaHCO3 is better, because HCl is a small amount, and CO2 and HCl and NaCO3 will produce NAHCO3 instead of CO2 when HCl is insufficient

The method of removing Na2CO3 in NaHCO3 solution is to introduce carbon dioxide into Na2CO3, which will react to generate sodium bicarbonate solution to achieve the purpose of removing impurities, CO2+H2O+CO32-=2HCO3-.

Chemical equation: Na2CO3 + H2O + CO2 = 2NaHCO3.

In addition to impurities, at least two conditions must be met: the added reagent can only react with impurities, not with the original substance, and no new impurities can be added during the reaction; Na2CO3 in solution can react with CO2 and H2O to form NaHCO3, and NaHCO3 does not react with CO2, so CO2 can be introduced to remove impurities.

Here's why:

Sodium carbonate is more alkaline than sodium hypochlorite, and sodium hypochlorite is more alkaline than sodium bicarbonate. The principle of making weak bases from strong bases, so here is the generated HCO3-.

clo-+h2o+co2 hclo +hco3-not hi,,,Ignored。

Because carbonate is more acidic than hypochlorite, carbonate reacts with hypochlorous acid to form bicarbonate and hypochlorite. So the ionic equation should be clo +h2o+co2 hclo+hco3. To dispose of a printed circuit board is to dissolve the copper.

There is a white precipitate in the final solution, which precipitates: b

Na2SiO3 solution Carbon dioxide passes into sodium silicate and silicic acid precipitates. Because carbonic acid is stronger than silicic acid.

2CO2+Na2SiO3+2H2O=2NaHCO3+H2SiO3 Naalo2 solution Carbon dioxide is introduced into metaaluminic acid to produce double hydrolysis, resulting in the formation of aluminum hydroxide Naalo2+CO2+2H2O=Al(OH)3 +NaHCO3 Saturated Na2CO3 solution Carbon dioxide is introduced into sodium carbonate and sodium bicarbonate precipitation. Because sodium bicarbonate is less soluble than sodium carbonate.

Na2CO3 + H2O + CO2 = 2NaHCO3 CaCl2 solution while carbonic acid is weaker than hydrochloric acid. So it will not react with calcium chloride Ca(OH)2 excess CO2 to produce Ca(HCO3)2Ca(OH)2+2CO2=Ca(HCO3)2, I hope it will help you.

H2O+CO2+CaCl2= =2HCl+CaCO3 because hydrochloric acid is more acidic than carbonic acid and does not react.

CO2 + Na2SiO3 = Na2CO3 + H2SiO3 because carbonic acid is more acidic than silicic acid.

CO2+Naalo2=NaHCO3+Al(OH)3 Aluminum hydroxide is amphoteric and less acidic than carbonic acid.

CO2 + Na2CO3 (saturated) + H2O = 2NaHCO3 because sodium bicarbonate is much less soluble than sodium carbonate.

Mr. CO2 + Ca(OH)2 = CaCO3 + 2H2O is a precipitate, but there is an excess of CO2.

CO2+CaCO3+H2O=Ca(HCO3)2 white precipitate dissolved.

So choose B

Election does not react with CO2.

At the same temperature, the solubility of NaHCO3 is smaller than that of Na2CO3).

b;1. No reaction;

precipitation); precipitation);

If you have any questions, please ask!

Here the acidity is H2CO3>HCO3>HCO3 - the equation you wrote is actually a two-step reaction.

CLO-+CO2+H2O=HCO+HCO3- 1CLO-+ HCO3- =HCO+CO32- 2 The first step of strong acid to weak acid can occur.

The second step is to make strong acid from weak acid, which cannot happen.

So the total equation is Equation 1

If you don't understand, please ask.

It is not easy to answer the question, and I hope to cooperate with o( o

Good luck with your studies.

Because CO2 is also soluble in water, CO2 + H2O = H2CO3, H2CO3 ionization produces bicarbonate, there is a large amount of bicarbonate in NaHCO3 solution, bicarbonate can inhibit the reaction between CO2 and H2O, so use saturated NaHCO3 solution to remove HCl in the mixed gas, which can make CO2 dissolved in water as little as possible.

In addition, HCl+NaHCO3=NaCl+H2O+CO2, saturated NaHCO3 solution may make HCl absorption more complete, and the CO2 produced is not an impurity.

The reason for not using NaCO3 is: CO2 + H20 + Na2CO3 = 2NaHCO3

Whereas, HCl+NaHCO3=NaCl+H2O+CO2

This problem can be completely solved by using NaHCO3, CO2 does not reflect with NaHCO3, and HCl reacts with it to produce CO2.