What is the ratio of the mass of CO to CO2 with an equal number of atoms?

Analysis: Because CO and CO2 contain the same number of atoms, the ratio of their amounts of matter must be 3:2

Then according to m=nm

Then there is m(co):m(co2)=n(co)m(co):n(co2)m(co2)=3*28:2*44=21:22

So the ratio of the mass of Co to Co2 with the same number of atoms is 21:22

1 CO molecule contains 2 atoms, and 1 CO2 molecule contains 3 atoms.

If the number of atoms is equal, then the ratio of the number of molecules is 3:2

CO molecular weight = 28, CO2 molecular weight = 44

Then the ratio of masses is (28 3):(44 2) = 84 : 88 = 21:22

The number of atoms contained in CO and CO2 is equal, i.e. the ratio of the amount of matter is 3:2;Then the mass ratio is (3*28):(2*44)=21:22

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1 molecule of CO contains one C atom and one O atom A molecule of CO2 contains one C atom and two O atoms.

The ratio of the atomic number of Co and Co2 for the same number of molecules is 2:3, so through the simplest calculation, we can know that the number of atoms contained in 3 CO molecules and 2 CO2 molecules is equal, which is the ratio of the number of molecules when the number of atoms is equal, then the mass ratio is calculated co: 3*28=84 2*44=88

co:co2=84:88=21:22

It is equivalent to three CO and two CO2, and the ratio of mass = (12 + 16) * 3:88 = 84:88 = 21:22

The relative mass of the CO is 28

The relative mass of CO2 is 44

When the molecular quantity ratio of two molecules is 11:7, the mass is equal.

At this time, the number of atoms contained in CO is 11*2=22, and the number of primordial early fingers contained in CO2 is 3*7=21, so the ratio of the number of atoms contained in CO to CO2 is 22:21

If there is a CO of 1mol, then there is also a CO of 1mol and the mass of CO of 21mol is 1*28=28g

The mass of CO2 in 1mol is 1*44=44g

Therefore, the mass ratio is 28:44=7:11

1mol of CO has 1mol of oxygen atoms.

1mol of CO2 has 1*2=2mol of oxygen atoms.

Therefore, the ratio of the number of oxygen atoms is 1:2

The mass ratio of the carbon element contained here is the material and mass ratio of the carbon atom to the slag ratio, and the quantity ratio of the substances of CO and CO2 is respectively obtained: 2 28 and 1 44, and then the ratio of the two is obtained by 22:7

Analysis: 1 C contains 6 protons, and 1O contains 8 protons. Therefore, a CO2 contains 22 protons, and a CO contains 14 protons, and the ratio of the amount of mass tolerance is equal to the ratio of the number, and because of the amount of CO2 and CO of the group beam and other substances, the ratio of the number of protons contained in the spring of the group is 22:

co: 28 where the ratio of c is 12 28

CO2: 44- where the ratio of C is 12 44 Let the mass of MCO in C = M * 12 28

C = m*12 in CO2 44

So the ratio c is m*12 28:m*12 44=44:28=11:7

1: Molar mass is like the density of matter, it is a property of the substance itself, and it has nothing to do with the amount of matter, molar mass = relative molecular mass, so the ratio of molar mass is 28:44=7:11

2: Because it contains the same number of molecules, the amount of the substance = the number of molecules na, so the ratio of the quantity of the substance is 1:1

3: Untraced mass = amount of matter * molar mass, so the ratio of mass is 7:114: because a CO or CO2 molecule contains a carbon atom, the ratio of the number of carbon atoms contained in the Hu = the ratio of the number of molecules containing CO to CO2 = 1:1

If there is a CO of 1mol, then there is also a CO of 1mol and the mass of CO of 21mol is 1*28=28g

The mass of CO2 in 1mol is 1*44=44g

Therefore, the mass ratio is 28:44=7:11

1mol of CO has 1mol of oxygen atoms.

1mol of CO2 has 1*2=2mol of oxygen atoms.

Therefore, the ratio of the number of oxygen atoms is 1:2

Suppose both are 1mol

Then the number of atoms contained in CO is 6+8=14

The number of atoms contained in CO2 is 6 + 8 * 2 = 22

Therefore, the ratio of the two is 7:11