Chemistry questions ,,, the periodic problems of the elements, and they are in a hurry!!

Just the answer. When I see zy2 and zy3, I want to have more valence elements. For example, S.

Push zy2 first, and zy3 are so2 and x2s respectively, that is. x is an element of group 1a. Again in the third cycle, for na

Na2S+H2SO4===> can be neutralized to obtain S element. (As long as it is in principle.) It doesn't matter if he's learned it or not).

So the previous push is correct

Original answers. Wish! 】

x2z is na2s

ZY2 is SO2

ZY3 is SO3

Both Na and S are in the third cycle, SO3 is combined with water to form H2SO4, H2SO4 reacts with Na2S to form H2S gas (using the principle of strong acid to weak acid), and H2S reacts with SO2 to form S element].

Hope!! Thank you!!

Start with strong acids, common strong acids, because they are compounded, so they can't be hydrochloric acid, and they are combined with hydration, and the first thing that comes to mind is HNO3 or H2SO4

So consider ZY3 as So3 and then assume that X2S reacts with H2SO4 to metacompose.

Hydrogen sulfide is generated, and it reacts with SO2 to form Z S element, which proves that Y is oxygen and Z is sulfur.

Compounds that are in the same period as S and can form X2S are Na thanks.

x=h (elemental hydrogen).

y=o (elemental oxygen).

z=s (element sulfur).

a=h2 (hydrogen molecule).

x2z = h2s (hydrogen sulfide).

ZY3 = SO3 (sulfur trioxide).

I'm not bad at chemistry, o( o!

Satisfied with the trouble to adopt, thank you.

Isn't it after every chemistry book.

Hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxyfluorine, neon, sodium, magnesium, aluminum, silicon, phosphorus, sulfur, chloride, argon, potassium, calcium, scandium, titanium, vanadium, cadmium, manganese, iron, cobalt, nickel, copper, zinc, gallium, germanium, arsenic, selenium, bromine, krypton.

1) In the aluminium chloride solution, aluminium chloride is a solute, which is composed of two elements, aluminium and chlorine, of which aluminium is a metal element, and its element symbol is permeation: al;

2) In the aluminum chloride solution, there are anion and cation chloride ions and cationic aluminum ions, and the symbol of chloride ions is: cl-;

3) The solvent in the solution is water, and the valency of the oxygen bush modification element in the water is -2 valence, which can be expressed as: H2

O4) The solute in the aluminium chloride solution is aluminium chloride, and according to the algebraic sum of the zero analysis of the positive and negative valencies in the compound, the chemical formula of aluminium chloride is: AlCl3;

So the answer is: (1) al; （2）cl-；（3）h2

o（4）alcl3．

I should choose B for this question.

The boiling point of water is higher than that of hydrogen sulfide because water contains hydrogen bonds.

Ammonia is less stable than water because it is non-metallic, from left to right.

Sulfurous acid cannot oxidize copper.

As for y, because the conditions given by the question are relatively few, it may be sodium, magnesium and aluminum, and this question does not want you to deduce y. None of the options.

But I think Y is more likely to be na. But this one doesn't matter.

Pro, the first 20 elements of the periodic table: hydrogen (H), helium (He), lithium (Li), beryllium (Be), boron (B), carbon (C), nitrogen (N), oxygen (O), fluorine (f), neon (Ne), sodium (Na), magnesium (mg), aluminum (Al), silicon (Si), phosphorus (P), sulfur (S), chlorine (Cl), argon (Ar), potassium (K), calcium (Ca). The back of five five is better:

Hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, neon, sodium, magnesium, aluminum, silicon, phosphorus, sulfur, chloride, argon, potassium, calcium.

Metal Activity Order Table: Potassium, Calcium, Sodium, Magnesium, Aluminum, Zinc (Zn), Iron (Fe), Tin (Sn), Lead (Pb), Hydrogen, Copper (Cu), Mercury (Hg), Silver (Ag), Platinum (Pt), Gold (Au). Among them, the metal element in front of hydrogen can react with dilute sulfuric acid, dilute hydrochloric acid, etc. to replace the hydrogen inside.

There is a problem to know, and the requirements of the question are nh3 ph3, alcl3, bf3, so3, pcl3, na3n, so when y is m, x can be m+6 m+14 m+4 m+4 m+8 m-2 m-4

So there's no detailed idea of choosing d, which is to write down all xy3 and do the math.

The substance may be BF3, SO3, NH3, PH3, ALCL3, PCL3, ALF3, etc.

Therefore, the atomic number of x may be (corresponding to the above) m-4, m+8, m+6, m+14, m-4, m-2, m+4 and d.

The first thing that comes to mind is NH3, then N is element 7, H is element 1, then 5 must be, C is not.

Then there is SO3, S is element 16, O is element 8, then 3 is also wanted, A is not wanted.

Then I thought of NF3, this substance is there, then n is 7, F is 9, then 4 is wanted, so choose D