How to calculate the water gravity of the water supply pipe, how to find the area and weight of the

Gravity of water = (The value is sufficient) (The radius of the pipe, in meters) The length of the small bridge (the length of the pipe in the suspension section, the unit is also meters) The density of water (1000kg m, calculated according to pure water) g (The value is, the above calculation is the gravity of water, and the final unit is n (ox), you also need to add the gravity of this pipe to the gravity you need!) But in fact, the gravity of the tube on the bridge is a little smaller than this value, because there is a support at both ends of the tube! There is little difference between static and dynamic, and if there are no large number of bubbles in the water flow, the water flow vibration can be ignored, which basically has no effect on the bridge!

Hope it helps the landlord!

If it is a horizontal pipeline arranged along the bridge, whether it is in the still water state or in the flowing water state, the vertical force borne by the small bridge is: the weight of the pipe + the weight of the water in the pipe.

Horizontal flow only produces an additional push-pull force in the horizontal direction, which is proportional to the length of the horizontal pipe: f= g( d 2 4)jl = g( d 2 4)h

where: —water density; g – acceleration due to gravity; — pi; d - inner diameter of the tube; j – hydraulic grade drop (head loss per unit length); l - pipe length; h – head loss in horizontal pipes.

The 2-inch tube is very small, you can calculate the weight of a pipe and a water weight, and the water weight can be calculated by using the cross-sectional area * length * density.

Suppose the outer diameter of the tube is d(mm), the thickness is d(mm), the length is l(mm), the density is p(g cm3), and the weight of the tube is w(kg);

The weight of the tube can be calculated as follows: w(kg) = x d(d-d) x l x g 1000000 = x d(d-d) x l x = x d x (d-d) x l

In the above formula, the diameter, thickness, and length are in millimeters, and the unit of weight of the pipe is kilograms.

Using the above formula, bringing in your data, we can get the weight of the tube w = x 2x (50-2) x 200 =

The water pressure of the meter water pipe is 6 kilometers long and the water pressure of the gravity water pressure is equivalent to the water pressure of the 100-meter-deep pool bottom, that is, 10 atmospheres. Pipeline water pressure: When the water flow stops flowing and relapses, the pressure at a certain point on the pipeline is equal to the depth of the water surface to the water source of the pipeline multiplied by the density of the water and then multiplied by the acceleration of gravity.

The flow of water in the pipeline must be calculated according to the Bernoulli energy equation: z1+p1 ( g)+v1 2 (2g)= z2+p2 ( g)+v2 2 (2g)+(l d)v 2 (2g)+ v 2 (2g).

Summary. Hello, pipe area algorithm: Calculation formula with cylindrical side area = circumference of the bottom circle height circumference of the circle = pi diameter Is 1000 millimeters or meters?

If it is meters: The surface area of this steel pipe: square meters If it is millimeters:

The surface area of this steel pipe: square meters.

Hello, pipeline area algorithm: Calculation formula with cylindrical side area = circumference of the circle of the bottom ruler filial piety height limb circumference of the circle = pi diameter 1000 is millimeters or meters? If it's m:

The surface area of this steel pipe: square meters If it is millimeters: The surface area of this steel pipe is trapped in slag:

Square metre. The basic formula of theoretical weight pure pinning: m=f l p 1000 Description: m: weight (kg) f: cross-sectional area to make a bond (mm2) l: long bucket regret degree (m) p: density (g cm3) f = wall thickness (outer diameter - wall thickness).

Hello! If it is a horizontal pipe arranged along the bridge, whether it is in the still water state or in the flowing water state, the force in the vertical direction borne by the small bridge is: the self-weight of the pipe.

The water in the pipe is heavy. The horizontal flow will only produce an additional push-pull force in the horizontal direction, which is proportional to the length of the horizontal pipeline: f= g( d 2 4)jl = g( d 2 4)h

where: —water density; g – acceleration due to gravity; — pi; d - inner diameter of the tube; j – hydraulic grade drop (head loss per unit length); l - pipe length; h – head loss in horizontal pipes.

Typing isn't easy, oh!

The 2-inch tube is very small, you can calculate the weight of a pipe and a water weight, and the water weight can be calculated by using the cross-sectional area * length * density.

The water pipe can be seen as a cylinder.

The radius of the base circle is (25-2*).

If the height is 5, the volume v=pai*(r2)*h, where r=10 h=5, then the mass of water is m=p*v

p=1*(10)3kg/(m)3