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Question 1: Point (1, 1).
The second question, points (2,-3).
If you need the process, hi me.
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Question 1. 1. x +x-1=0 to get x +x=1 (very important) 2, x 3+2x +x-7 (deform the formula and beat it with "x +x") x(x +x) + x -7 (note: x +x=1, so the value in the preceding parentheses is 1).
x+x -7 (Note: the same x +x=1, so the value of the previous "x+x" is 1) 2.Suppose the average monthly growth rate for 11 December is x, then.
10000*(1+x)²+10000*(1+x)=231001+x)²+1+x)
x²+x=
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I just want to say、Is this a question for the second year of junior high school ==、
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x²+x=1
x^3+2x²+x-7
x(x²+x)+x²-7
x*1+x²-7
x²+x-7
2.Suppose the average monthly growth rate for 11 December is x, then.
10000*(1+x)²+10000*(1+x)=23100x=
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Refers to a right-angled isosceles triangle. Area = 1 2 * 5 * 5 = 25 2 According to the Pythagorean theorem, the line segment of the waist extension line = the balance of things (10 -6°) = 8, then the large right-angle cover is made of the triangle on one side of Hu Xin = 18, one side = 6
hypotenuse = (18 +6) = 6 10
The area of the square = 6 10 * 6 10 = 36 * 10 = 360
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m=-1 or m=2
First, multiply the left and right sides of the original equation by x(x+1) to reduce the original equation to an integral equation.
Since the original equation has an additional root, the root increment must make the denominator 0, so x=0 or x+1=0.
Just bring x=0 and x=-1 into the integer equation to find the value of m.
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m x squared.
Yes or light x squared.
If the whole square m is equal to 0,
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Answer: 2:5 Similar triangles are proportional to the corresponding sides, ab:
a′b′=2:5,ad:dc=a'd':
d'c'=2:5, known abc a b c so angle a = angle a according to the corner edge, bad b a d', ad and a'd'The ratio is 2:5.
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Set a blouse with cloth A, a pair of pants with cloth B, get:
y*a =x
4y*b=3x
The upper and lower phases are divided by celery to get:
a/b=4/3
Therefore, the cloth of a blouse is 4 times higher than that of a plum's pants.
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